All PSAT Math Resources
Example Questions
Example Question #892 : Algebra
Expand the expression:
When using FOIL, multiply the first, outside, inside, then last expressions; then combine like terms.
Example Question #4 : Distributive Property
Expand the following expression:
Which becomes
Or, written better
Example Question #1 : How To Use Foil In The Distributive Property
Which of the following is equal to the expression ?
Multiply using FOIL:
First = 3x(2x) = 6x2
Outter = 3x(4) = 12x
Inner = -1(2x) = -2x
Last = -1(4) = -4
Combine and simplify:
6x2 + 12x - 2x - 4 = 6x2 +10x - 4
Example Question #2 : How To Use Foil In The Distributive Property
Simplify the expression.
None of the other answers
Solve by applying FOIL:
First: 2x2 * 2y = 4x2y
Outer: 2x2 * a = 2ax2
Inner: –3x * 2y = –6xy
Last: –3x * a = –3ax
Add them together: 4x2y + 2ax2 – 6xy – 3ax
There are no common terms, so we are done.
Example Question #5 : Distributive Property
Given the equation above, what is the value of ?
Use FOIL to expand the left side of the equation.
From this equation, we can solve for , , and .
Plug these values into to solve.
Example Question #6 : Distributive Property
Expand and simplify the expression.
We can solve by FOIL, then distribute the . Since all terms are being multiplied, you will get the same answer if you distribute the before using FOIL.
First:
Inside:
Outside:
Last:
Sum all of the terms and simplify. Do not forget the in front of the quadratic!
Finally, distribute the .
Example Question #11 : How To Use Foil In The Distributive Property
If , , and , then
To find what equals, you must know how to multiply times , or, you must know how to multiply binomials. The best way to multiply monomials is the FOIL (first, outside, inside, last) method, as shown below:
Multiply the First terms
Multiply the Outside terms:
Multiply the Inside terms:
Note: this step yields a negative number because the product of the two terms is negative.
Multiply the Last terms:
Note: this step yields a negative number too!
Putting the results together, you get:
Finally, combine like terms, and you get:
Example Question #1 : Equations / Inequalities
Factor 4x3 – 16x
cannot be factored
4x(x + 2)(x + 2)
4x(x – 2)(x – 2)
4x(x + 2)(x – 2)
4x(x2 – 4)
4x(x + 2)(x – 2)
First pull out any common terms: 4x3 – 16x = 4x(x2 – 4)
x2 – 4 is a difference of squares, so we can also factor that further. The difference of squares formula is a2 – b2 = (a – b)(a + b). Here a = x and b = 2. So x2 – 4 = (x – 2)(x + 2).
Putting everything together, 4x3 – 16x = 4x(x + 2)(x – 2).
Example Question #2 : Equations / Inequalities
Factor the following equation.
x2 – 16
(x)(x – 4)
(x + 4)(x – 4)
(x2)(4 – 2)
(x – 4)(x – 4)
(x + 4)(x + 4)
(x + 4)(x – 4)
The correct answer is (x + 4)(x – 4)
We neen to factor x2 – 16 to solve. We know that each parenthesis will contain an x to make the x2. We know that the root of 16 is 4 and since it is negative and no value of x is present we can tell that one 4 must be positive and the other negative. If we work it from the multiple choice answers we will see that when multiplying it out we get x2 + 4x – 4x – 16. 4x – 4x cancels out and we are left with our answer.
Example Question #1 : How To Factor An Equation
If x3 – y3 = 30, and x2 + xy + y2 = 6, then what is x2 – 2xy + y2?
180
cannot be determined
24
5
25
25
First, let's factor x3 – y3 using the formula for difference of cubes.
x3 – y3 = (x – y)(x2 + xy + y2)
We are told that x2 + xy + y2 = 6. Thus, we can substitute 6 into the above equation and solve for x – y.
(x - y)(6) = 30.
Divide both sides by 6.
x – y = 5.
The original questions asks us to find x2 – 2xy + y2. Notice that if we factor x2 – 2xy + y2 using the formula for perfect squares, we obtain the following:
x2 – 2xy + y2 = (x – y)2.
Since we know that (x – y) = 5, (x – y)2 must equal 52, or 25.
Thus, x2 – 2xy + y2 = 25.
The answer is 25.