All Precalculus Resources
Example Questions
Example Question #1 : Systems Of Equations
Solve the following system:
We can solve the system using substitution since the bottom equation is already solved for :
Now we can plug in our value into the bottom equation to find our x-value:
So our solution is
Example Question #3 : Solve Systems Of Linear Equations
Solve the following system:
We can solve the system using elimination. We can eliminate the x terms by multiplying the bottom equation by :
and now add it to the top equation:
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We plug in our y-value into the bottom equation to get our x-value:
Our solution is then
Example Question #3 : Solve Systems Of Linear Equations
Solve the following system:
We can solve this system using either substitution or elimination. We'll eliminate them here.
Note: If you wanted to do substitution, we can do it by substituting the top equation into the bottom for .
We'll rearrange the bottom equation to have both y-values aligned and then add the equations:
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Now that we have our x-value, we can find our y-value:
Our answer is then
Example Question #10 : Inequalities And Linear Programming
Solve the following system of equations:
There are many ways to solve this system of equations. The following is just one way to reach the answer.
Add the two together, to elimnate the y variable. Solve for x and then plug it back in to the first equation to solve for y.
Example Question #11 : Inequalities And Linear Programming
Find the point of intersection by using Gaussian elimination:
To solve this, let's first try to eliminate x. We can do this by adding the two equations:
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Which implies
We can now solve for x by plugging 2 in for y in either equation.
Thus we have the answer
Example Question #12 : Solve Systems Of Linear Equations
Solve the following system of equations:
Let's solve this equation by eliminating the variable x by adding a multiple of the second equation to the first.
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Now let's combine those y values and solve for y.
Now all we have to do is plug that in for y in either original equation to solve for x.
Thus this yields the intersection point
Example Question #13 : Solve Systems Of Linear Equations
Solve the following system of equations for the intersection point in space:
Because one of the variables, z, has already been isolated, let's use the substitution method to solve this system of equations. We know z = 1, so let's plug that into the middle equation to solve for y:
Now that we have found y, let's solve for x by plugging both y and z into the top equation:
Thus we have found that the point of intersection would be
Example Question #1 : Solve Nonlinear Systems Of Equations
Solve the following system of nonlinear equations:
We can start by rearranging each equation so that y is on one side:
Now that both equations are equal to y, we can set the right sides equal to each other and solve for x:
Our last step is to plug these values of x into either equation to find the y values of our solutions:
So our solutions are the folloiwing two points:
Example Question #2 : Solve Nonlinear Systems Of Equations
Solve the following system of nonlinear equations:
Our first step is to rearrange each equation so that the left side is just y:
Now that both equations are equal to y, we can see that the right sides of each equation are equal to each other, so we set this up below and solve for x:
Our last step is to plug these values of x into either equation to solve for the y values of our solutions:
So the solutions to the system are the following points:
Example Question #3 : Solve Nonlinear Systems Of Equations
Solve the following system:
Our first step is to solve the bottom equation for
We can now substitute it into the top equation:
and solve for our values:
our values are then:
We can now plug our values into the bottom equation we had solved for and arrive at our solutions:
So, our solutions are