MCAT Physical : MCAT Physical Sciences

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

Example Question #9 : Nuclear Chemistry And Electrons

In the operation of nuclear reactors, engineers make use of substances known as neutron poisons. These are used to help store nuclear waste and slow nuclear reactions, but are also generated naturally in nuclear chain reactions as a by-product. This natural by-product can stop the desirable chain reaction present in a nuclear reactor used for power generation. 

For example, in nuclear power plants, U-235 is used as a fuel. U-235 absorbs a neutron, and subsequently generates neutrons (which power the chain reaction) and Xe-135. Xe-135 is a well-known neutron poison, and thus can impact the continued chain reaction of a nuclear power plant if it becomes over abundant during power generation. 

To help account for this, engineers have developed measurements to quantify the impact of Xe-135 on nuclear operations. For instance, the time during which there is an inability to start a reactor due to the buildup of Xe-135 is referred to as the precluded start-up time. Also, the amount of time that the reactor cannot override the effects of built up Xe-135 is called poison outage time. Perhaps the most important measure that engineers have developed is the neutron absorption capacity (σ), which is measured in units of barns and is a function of microscopic cross section. Xe-135 has a neutron absorption capacity of 2.00 * 106 barns, while another common poison, Sm-149, has a neutron absorption capacity of 74,500 barns. 

What is the force responsible for attracting neutrons to the nuclei of neutron poisons?

Possible Answers:

Strong nuclear force

Covalent force

Gravitational force

Electrostatic force

Electroweak force

Correct answer:

Strong nuclear force

Explanation:

The subatomic particles in an atom's nucleus, protons and neutrons, are held together by their own force called the strong nuclear force. Strong nuclear forces act in a somewhat counterintuitive way, and only over very short distances. The strong force is what allows protons to overcome their electrical repulsion to one another and exist together in the nucleus.

Example Question #10 : Nuclear Chemistry And Electrons

In the nucleus, the accumulation of positive charges creates an electrostatic repulsion, known as the electromagnetic force. With the repulsive force that is generated, what is responsible for binding atoms together?

Possible Answers:

The binding energy of the strong force is greater than the electrostatic repulsion of the electromagnetic force

The nucleus is constantly disintegrating and reforming, giving off the appearance that it is bound together

The presence of neutrons are able to neutralize the repulsive force

The gravitational force on Earth binds nucleons together

Correct answer:

The binding energy of the strong force is greater than the electrostatic repulsion of the electromagnetic force

Explanation:

The binding energy of atoms is due in large part to the nuclear force, or strong force, which is the most powerful of the four universal forces.

Because the magnitude of the strong force is so large, it is able to overcome the electromagnetic force that is generated by the repulsion of like charges. Atoms exist in other parts of the universe beyond Earth, so the gravitational force is clearly not responsible. Neutrons have "neutral" charge, but that does not mean they are able to "neutralize" positive or negative charges.

Example Question #11 : Nuclear Chemistry And Electrons

Nuclear attraction is a force between which two subatomic particles?

Possible Answers:

Neutrons and neutrons

Neutrons and electrons

Protons and electrons

Neutrons and protons

Correct answer:

Neutrons and protons

Explanation:

Nuclear attraction is a force that holds together the molecules in the nucleus of an atom. Remember that there are a total of three subatomic particles in an atom: protons, neutrons, and electrons. Protons are positively charged, neutrons are neutral, and electrons are negatively charged. Of the three subatomic particles, only protons and neutrons are found inside the nucleus. Nuclear attraction must occur between a neutron and a proton. This force counteracts repulsion between protons to hold the nucleus together. Electrons are found in electron shells outside the nucleus and do not participate in nuclear attraction.

Example Question #12 : Nuclear Chemistry And Electrons

Which of the following is true about nuclear attraction force?

I. It occurs between two quarks

II. It occurs between two hadrons

III. It is classified as a strong force

Possible Answers:

I and II

II only

I and III

I only

Correct answer:

II only

Explanation:

Nuclear forces occur between protons and neutrons in the nucleus of an atom. Recall that quarks are elementary particles that make up composite particles called hadrons. Protons and neutrons are types of hadrons; therefore, nuclear forces occur between two hadrons.

There are four major types of fundamental forces: gravitational force, electromagnetic force, weak force, and strong force. Gravitational force is the attractive force between two bodies, electromagnetic force is a combination of the force between charges and magnetic force, weak force is the force between a W boson and a Z boson, and strong force is the force that occurs between two quarks. Nuclear forces between protons and neutrons are an effect created by the strong force between two quarks; however, nuclear forces are not classified as a type of strong force.

Example Question #13 : Nuclear Chemistry And Electrons

Choose the best answer for the following question.

You have a  sample of an unknown substance with a half-life of 3 days. After 9 days how much of the substance remains?

Possible Answers:

Correct answer:

Explanation:

Since the half-life of the sample is 3 days long, throughout the course of 9 days, the sample will undergo a half-life cycle 3 times. This means we have to half the mass of the original sample 3 times.

We originally start with 

After 3 days: 

After 6 days: 

After 9 days: 

Another way to solve these types of problems is using this formula:  where  is the number of half lives. 

thus  or  of the original sample remains. 

 

Therefore after 9 days, there will be  of the original sample remaining.

Example Question #1 : Intensity And Decibels

At a local concert, a speaker is set up to produce low-pitched base sounds with a frequency range of 20Hz to 200Hz, which can be modeled as  sine waves. In a simplified model, the sound waves the speaker produces can be modeled as a cylindrical pipe with one end closed that travel through the air at a velocity of , where T is the temperature in °C.

If the sound crew wanted to quadruple the intensity of the sound, they could __________.

Possible Answers:

halve the frequency of the sound wave

halve the amplitude of the sound wave

double the amplitude of the sound wave

halve the air density

Correct answer:

double the amplitude of the sound wave

Explanation:

This question asks us to determine what would happen to the intensity of a sound wave if a variable could be changed. First, we need to remember the equation for intensity: , where A is the wave amplitude, rho is the density of the medium, f is the frequency of the wave, and v is the velocity of the wave.

This formula is important to understand qualitatively. For the MCAT, it is important to understand how the various factors impact the intensity of a wave. If we wanted to quadruple the intensity, we can see that we could double amplitude or double frequency. Seeing that we want the sound pitch to remain the same, we would want to double the amplitude and not the frequency. The relationship between intensity, frequency, and amplitude is important to understand.

Example Question #2 : Intensity And Decibels

At a local concert, a speaker is set up to produce low-pitched base sounds with a frequency range of 20Hz to 200Hz, which can be modeled as  sine waves. In a simplified model, the sound waves the speaker produces can be modeled as a cylindrical pipe with one end closed that travel through the air at a velocity of , where T is the temperature in °C.

If the sound crew wanted to halve the intensity of the sound, they could __________.

Possible Answers:

double the size of the room

double the amplitude of the sound wave

halve the size of the room

double the frequency of the sound wave

Correct answer:

double the size of the room

Explanation:

This question asks us to determine what would happen to the intensity of a sound wave if a variable could be changed. First, we need to remember the equation for intensity, , where P is the power of the wave, A is the area,  is the wave amplitude, rho is the density of the medium, f is the frequency of the wave, and v is the velocity of the wave.

This formula is important to understand qualitatively. For the MCAT, it is important to understand how the various factors impact the intensity of a wave. If we wanted to halve the intensity, we can see that we could halve the power of the wave or double the area the wave is hitting; thus, we could double the size of the room, allowing the sound wave to have more room to spread out and increasing the area the wave interacts with.

Example Question #1 : Intensity And Decibels

At a local concert, a speaker is set up to produce low-pitched base sounds with a frequency range of 20Hz to 200Hz, which can be modeled as  sine waves. In a simplified model, the sound waves the speaker produces can be modeled as a cylindrical pipe with one end closed that travel through the air at a velocity of , where T is the temperature in °C.

Find the intensity of a 35dB base wave produced by the speaker.

Possible Answers:

Correct answer:

Explanation:

This question asks us to determine the intensity of a wave, given to us as a comparison of the wave intensity to the intensity of the limit of human hearing. In math terms, we know that the decibel scale is calculated as shown below.

I0 is the limit of human hearing (10-12 W/m2).

Example Question #4 : Intensity And Decibels

A song comes onto your car radio and you lower the volume from a setting of  to a setting of . How much has the intensity level decreased?

Possible Answers:

Correct answer:

Explanation:

Regardless of the units measured, a ten-fold decrease in volume equals a  decrease in intensity level.

Here, there is a twenty-fold decrease in sound intensity.

A ten-fold decrease would be a  change, and a hundred-fold decrease would be a  change. A  decrease is closer to a ten-fold decrease than a hundred-fold decrease, hence the decrease in intensity level should be closer to .

Example Question #1 : Intensity And Decibels

Which statement best explains why sound intensity is lessened when a wall is placed between the source and listener?

Possible Answers:

Sound travels more slowly in solid than air

Part of the sound energy is reflected by the solid

Sound frequency is lower in solid than air

Sound wavelength is shorter in solid than air

Correct answer:

Part of the sound energy is reflected by the solid

Explanation:

When a sound wave contacts a surface, it transfers longitudinal vibration into the solid. Because of the increased density in the solid, these longitudinal compressions actually speed up and increase in wavelength. The frequency of the sound remains constant.

Only some of the sound energy is transferred to the solid, however. When the wave impacts the solid, some of the energy is bounced of the surface and reflected back to the source as an echo. This reduction of energy accounts for the lessened intensity experienced by a listener on the opposite side of the wall. Energy is also lost to internal reflection within the wall.

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