LSAT Logic Games : Solving grouping games
Study concepts, example questions & explanations for LSAT Logic Games
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Example Questions
Example Question #221 : Solving Grouping Games
A preschool intends to purchase exactly six items for its classroom. The items fall within three categories: Books, Puzzles, and Toys. The Books are identified as A, B, and C. The Puzzles are identified as K, L, and M. The Toys are identified as T, U, and Z. The selection of classroom items must meet the following conditions:
A and C cannot both be selected.
M and T cannot both be selected.
If C is selected, K is also selected.
If K is selected, M is also selected.
Each of the following is a pair items that could be purchased together EXCEPT:
L and M
T and U
A and B
K and T
C and K
K and T
B, L, U, and Z are all wildcards. That allows us to eliminate answer choices containing them. C and K can be together, as we saw in another question in this problem set. K and T can't be together: If K is in, N is in, which forces T out.
Example Question #222 : Solving Grouping Games
A preschool intends to purchase exactly six items for its classroom. The items fall within three categories: Books, Puzzles, and Toys. The Books are identified as A, B, and C. The Puzzles are identified as K, L, and M. The Toys are identified as T, U, and Z. The selection of classroom items must meet the following conditions:
A and C cannot both be selected.
M and T cannot both be selected.
If C is selected, K is also selected.
If K is selected, M is also selected.
If T is selected, which one of the following is a pair of items that must be among the animals selected?
L and M
A and B.
K and L
B and C
K and Z
A and B.
If T is in, then M, K, and C must be out, which is a full "out" group. That allows us to fill in all the "in" slots. We can eliminate all answers that contain M, K, or C.
Example Question #223 : Solving Grouping Games
A preschool intends to purchase exactly six items for its classroom. The items fall within three categories: Books, Puzzles, and Toys. The Books are identified as A, B, and C. The Puzzles are identified as K, L, and M. The Toys are identified as T, U, and Z. The selection of classroom items must meet the following conditions:
A and C cannot both be selected.
M and T cannot both be selected.
If C is selected, K is also selected.
If K is selected, M is also selected.
If all three of the Toys are purchased, which one of the following must be true?
L is purchased.
Exactly two Puzzles are purchased.
All three of the Books are selected.
K is purchased.
Exactly one Book is purchased.
L is purchased.
The Toys are T, U, and Z. U and Z are both wildcards, so they don't tell us anything. T being in means M is out, which means K and C are out. We now have all the "out" slots filled in, so that means we can fill in all the "in" slots:
T, U, Z, A, B, L
Therefore, L is in.
Example Question #224 : Solving Grouping Games
A preschool intends to purchase exactly six items for its classroom. The items fall within three categories: Books, Puzzles, and Toys. The Books are identified as A, B, and C. The Puzzles are identified as K, L, and M. The Toys are identified as T, U, and Z. The selection of classroom items must meet the following conditions:
A and C cannot both be selected.
M and T cannot both be selected.
If C is selected, K is also selected.
If K is selected, M is also selected.
The purchase of items must include
exactly two Toys.
at most two of each kind of item
at least two Puzzles
at least one of each kind of item
exactly two Books
at least one of each kind of item
This one is tricky, but we can use other questions and answers in this problem set to help us. We know from another question that all the Toys can be selected, which eliminates two answers here. Two other questions had two Puzzles out, so one answer here is eliminated. We're left with two answer choices:
"at least one of each kind of item" versus "exactly two Puzzles."
The best approach is simply to test out one of these options and determine if it works. If we try to fill in the "in" and "out" categories by eliminating one kind of item, we will find that we violate a rule. So, it must be true that at least one of kind of item is purchased.
Example Question #225 : Solving Grouping Games
Exactly Eight Classrooms—A, B, C, D, E, F, G, and H—are going on a field trip. Each classroom will go to either the museum or the observatory but not both. Exactly four classrooms go to the museum together and four go to the observatory together. The following conditions apply to the trips:
If G goes to the Observatory, then B also goes to the Observatory.
If C goes to the Museum, then E goes to the Observatory.
B and H go together.
D goes to the Museum.
What is a possible accurate list of classrooms that go to the Observatory together?
A, B, E, H
A, C, F, D
A, B, F, H
A, E, F, G,
C, E, F, H
Example Question #226 : Solving Grouping Games
Exactly Eight Classrooms—A, B, C, D, E, F, G, and H—are going on a field trip. Each classroom will go to either the museum or the observatory but not both. Exactly four classrooms go to the museum together and four go to the observatory together. The following conditions apply to the trips:
If G goes to the Observatory, then B also goes to the Observatory.
If C goes to the Museum, then E goes to the Observatory.
B and H go together.
D goes to the Museum.
If B goes to the museum, it must be true that
G goes to the Observatory.
F goes to the Museum.
A goes to the Observatory.
H goes to the Observatory.
E goes to the Museum.
A goes to the Observatory.
If B goes to the Museum, H also goes to the Museum. Since B goes to the Museum G cannot go to the Observatory. D always goes go the Museum.
The game can be mapped out as follows:
Museum: B, D, G, H
Observatory: A, C, E, F
Thus, A must go to the Observatory.
Example Question #227 : Solving Grouping Games
Exactly Eight Classrooms—A, B, C, D, E, F, G, and H—are going on a field trip. Each classroom will go to either the museum or the observatory but not both. Exactly four classrooms go to the museum together and four go to the observatory together. The following conditions apply to the trips:
If G goes to the Observatory, then B also goes to the Observatory.
If C goes to the Museum, then E goes to the Observatory.
B and H go together.
D goes to the Museum.
Which, if true, allows for the accurate prediction of where all the classrooms will go?
C goes to the Observatory.
G goes to the Museum.
H goes to the Museum.
A goes to the Observatory.
B goes to the Observatory.
H goes to the Museum.
There is only one possible world where H goes to the Museum.
Museum: B, D, G, H
Observatory: A, C, E, F
H going to the Museum requires B also goes to the Museum. B going to the Museum means G must also go to the Museum. And D always goes to the Museum. Thus, knowing H goes to the Museum allows for the entire game to be completely mapped out.
Example Question #228 : Solving Grouping Games
There are exactly sixth different ingredients—Apple, Banana, Cucumber, Dragonfruit, Eggplant, and Fig—that can be used to make a smoothie. Each ingredient can only be used once. A smoothie is made with the follow conditions:
At least four ingredients are used.
If Apples are used, then Dragonfruit is also used.
If Eggplant is used, then Cucumber is not used.
Fig must be used.
Which is a possible acceptable combination of ingredients that could be used to make a smoothie?
Banana, Cucumber, Fig
Apples, Banana, Cucumber, Dragonfuit
Apples, Banana, Cucumber, Fig
Apples, Banana, Cucumber, Dragonfuit, Fig
Banana, Cucumber, Dragonfruit, Eggplant, Fig
Apples, Banana, Cucumber, Dragonfuit, Fig
Only the choice “Apples, Banana, Cucumber, Dragonfuit, Fig” does not violate any of the conditions given.
Apples, Banana, Cucumber, Dragonfuit (Fig is not used)
Apples, Banana, Cucumber, Fig (Apples are used but Dragonfruit is not)
Banana, Cucumber, Dragonfruit, Eggplant, Fig (Both Eggplant and Cucumber cannot be used)
Banana, Cucumber, Fig (There are not at least four ingredients)
Example Question #229 : Solving Grouping Games
Exactly Eight Classrooms—A, B, C, D, E, F, G, and H—are going on a field trip. Each classroom will go to either the museum or the observatory but not both. Exactly four classrooms go to the museum together and four go to the observatory together. The following conditions apply to the trips:
If G goes to the Observatory, then B also goes to the Observatory.
If C goes to the Museum, then E goes to the Observatory.
B and H go together.
D goes to the Museum.
If C goes to the Museum, how many different possible groups of classrooms are there that go to the Museum?
Five
Six
Four
Two
Three
Three
If C goes to the museum the possible games can be mapped out as follows:
Museum: A, C, D, F
Observatory: B, E, G, H
And,
Museum: C, D, G, __
Observatory: B, E, H, __
A and F can thus be switched creating two possibilities. Add these two possibilities to the first game shown for a total of three possible groups.
Example Question #230 : Solving Grouping Games
Exactly Eight Classrooms—A, B, C, D, E, F, G, and H—are going on a field trip. Each classroom will go to either the museum or the observatory but not both. Exactly four classrooms go to the museum together and four go to the observatory together. The following conditions apply to the trips:
If G goes to the Observatory, then B also goes to the Observatory.
If C goes to the Museum, then E goes to the Observatory.
B and H go together.
D goes to the Museum.
If A and F do not go on the field trip together, which other pair of classrooms cannot go together?
B and C
A and D
C and E
D and G
E and G
C and E
If A and F do not go together, the game can be mapped out as follows:
Museum: A/F, C, D, G
Observatory: A/F, B, E, H
Or,
Museum: A/F, D, E, G
Observatory: A/F, B, C, H
In neither of these possible games are C and E together.
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