All ISEE Upper Level Quantitative Resources
Example Questions
Example Question #1 : How To Find The Length Of The Diagonal Of A Rhombus
A rhombus has sidelength ten inches; one of its diagonals is one foot long. Which is the greater quantity?
(a) The length of the other diagonal
(B) One and one-half feet
(B) is greater
(A) and (B) are equal
(A) is greater
It is impossible to determine which is greater from the information given
(B) is greater
The diagonals of a rhombus are each other's perpendicular bisector, so, as can be seen in the diagram below, one side of a rhombus and one half of each diagonal form a right triangle. If the other diagonal has length , then the right triangle has hypotenuse 10 inches and legs one-half of one foot and - that is, six inches and .
This triangle fits the well-known Pythagorean triple of 6-8-10, so
The other diagonal measures 16 inches. One and one-half feet is equal to 18 inches, making (B) greater.
Example Question #271 : Isee Upper Level (Grades 9 12) Quantitative Reasoning
Rhombus has two diagonals that intersect at point ; . Which is the greater quantity?
(a)
(b)
(a) and (b) are equal
(a) is greater
It is impossible to tell from the information given
(b) is greater
(a) and (b) are equal
The diagonals of a rhombus always intersect at right angles, so . The measures of the interior angles of the rhombus are irrelevant.
Example Question #71 : Quadrilaterals
Which is the greater quantity?
(a) The area of the rectangle on the coordinate plane with vertices
(b) The area of the rectangle on the coordinate plane with vertices
(a) is greater.
(a) and (b) are equal.
It is impossible to tell from the information given.
(b) is greater.
(a) and (b) are equal.
(a) The first rectangle has width and height ; its area is .
(b) The second rectangle has width and height ; its area is .
The areas of the rectangle are the same.
Example Question #1 : How To Find The Area Of A Rectangle
A rectangle on the coordinate plane has its vertices at the points .
Which is the greater quantity?
(a) The area of the portion of the rectangle in Quadrant I
(b) The area of the portion of the rectangle in Quadrant III
(a) is greater.
It is impossible to tell from the information given.
(b) is greater.
(a) and (b) are equal.
(a) and (b) are equal.
(a) The portion of the rectangle in Quadrant I is a rectangle with vertices , so its area is .
(a) The portion of the rectangle in Quadrant III is a rectangle with vertices , so its area is .
Example Question #1 : How To Find The Area Of A Rectangle
. Which is the greater quantity?
(a) The area of the square on the coordinate plane with vertices
(b) The area of the rectangle on the coordinate plane with vertices
It is impossible to tell from the information given.
(a) is greater.
(b) is greater.
(a) and (b) are equal.
(a) is greater.
(a) The square has sidelength , and therefore has area .
(b) The rectangle has width and height , and therefore has area .
Since , the square in (a) has the greater area.
Example Question #1 : Rectangles
The perimeter of a rectangle is one yard. The rectangle is three times as long as it is wide. Which is the greater quantity?
(a) The area of the rectangle
(b) 60 square inches
(b) is greater
(a) is greater
(a) and (b) are equal
It is impossible to tell form the information given
(a) is greater
Let be the width of the rectangle. Then its length is , and its perimeter is
Since the perimeter is one yard, or 36 inches,
inches is the wiidth, and inches is the length, so the area is
square inches. (a) is the greater quantity.
Example Question #2 : Rectangles
If one rectangular park measures and another rectangular park measures , how many times greater is the area of the second park than the area of the first park?
First, you must compute the area of both parks. The area of a rectangle is length times width. Therefore, the area of park one is , which is . The area of park two is , which is Then, divide the area of the second park by the area of the first park (). This yields 3 as the answer.
Example Question #6 : How To Find The Area Of A Rectangle
The sum of the lengths of three sides of a rectangle is 572 inches; the width of the rectangle is 60% of its length. Give its area in square inches.
It is impossible to determine the area from the given information.
It is impossible to determine the area from the given information.
Since the width of the rectangle is 60% of its length, we can write .
However, it is not clear from the problem which three sides - two lengths and a width or two widths and a length - we are choosing to have sum 572 inches. Depending on the three sides chosen, we can either set up
or
Since the length cannot be determined with certainty, neither can the width, and, subsequently, neither can the area.
Example Question #7 : How To Find The Area Of A Rectangle
Five rectangles each have the same length, which we will call . The widths of the five rectangles are 7, 5, 8, 10, and 12. Which of the following expressions is equal to the mean of their areas?
The area of a rectangle is the product of its width and its length. The areas of the five rectangles, therefore, are . The mean of these five areas is their sum divided by 5, or
Example Question #8 : How To Find The Area Of A Rectangle
Two rectangles, A and B, each have perimeter 32 feet. Rectangle A has length 12 feet; Rectangle B has length 10 feet. The area of Rectangle A is what percent of the area of Rectangle B?
The perimeter of a rectangle can be given by the formula
Since for both rectangles, 30 is the perimeter, this becomes
, and subsequently
.
Rectangle A has length 12 feet and, subsequently. width 4 feet, making its area
square feet
Rectangle B has length 10 feet and, subsequently. width 6 feet, making its area
square feet
The area of Rectangle A is
of the area of Rectangle B.