ISEE Lower Level Quantitative : Operations with fractions and whole numbers

Study concepts, example questions & explanations for ISEE Lower Level Quantitative

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Example Questions

Example Question #81 : Operations With Fractions And Whole Numbers

David lives \(\displaystyle \frac{2}{4}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{1}{5}\) of the way there and then stopped to tie his shoe. How far did he travel before he stopped to tie his shoe? 

Possible Answers:

\(\displaystyle 3\textup { miles}\)

\(\displaystyle \frac{2}{20}\textup { of a mile}\)

\(\displaystyle 2\textup { miles}\)

\(\displaystyle \frac{5}{20}\textup { of a mile}\)

\(\displaystyle \frac{3}{20}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{2}{20}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{1}{5}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{2}{4}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{1}{5}\times\frac{2}{4}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model. 

 2 20

We make the area model \(\displaystyle 4\) by \(\displaystyle 5\) because those are the denominators of our fractions. We shade up \(\displaystyle 1\) and over \(\displaystyle 2\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{1}{5}\times\frac{2}{4}=\frac{2}{20}\)

 

Example Question #82 : Operations With Fractions And Whole Numbers

Matt lives \(\displaystyle \frac{2}{4}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{2}{5}\) of the way there and then stopped to tie his shoe. How far did he travel before he stopped to tie his shoe? 

Possible Answers:

\(\displaystyle 4\textup { miles}\)

\(\displaystyle \frac{5}{20}\textup { of a mile}\)

\(\displaystyle \frac{8}{20}\textup { of a mile}\)

\(\displaystyle 5\textup { miles}\)

\(\displaystyle \frac{4}{20}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{4}{20}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{2}{5}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{2}{4}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{2}{5}\times\frac{2}{4}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

4 20

We make the area model \(\displaystyle 4\) by \(\displaystyle 5\) because those are the denominators of our fractions. We shade up \(\displaystyle 2\) and over \(\displaystyle 2\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{2}{5}\times\frac{2}{4}=\frac{4}{20}\)

Example Question #83 : Operations With Fractions And Whole Numbers

Brian lives \(\displaystyle \frac{2}{4}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{3}{5}\) of the way there and then stopped to tie his shoe. How far did he travel before he stopped to tie his shoe? 

Possible Answers:

\(\displaystyle \frac{6}{20}\textup { of a mile}\)

\(\displaystyle \frac{1}{20}\textup { of a mile}\)

\(\displaystyle 1\textup { mile}\)

\(\displaystyle \frac{5}{20}\textup { of a mile}\)

\(\displaystyle 5\textup { miles}\)

Correct answer:

\(\displaystyle \frac{6}{20}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{3}{5}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{2}{4}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{3}{5}\times\frac{2}{4}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

6 20

We make the area model \(\displaystyle 4\) by \(\displaystyle 5\) because those are the denominators of our fractions. We shade up \(\displaystyle 3\) and over \(\displaystyle 2\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{3}{5}\times\frac{2}{4}=\frac{6}{20}\)

 

Example Question #84 : Operations With Fractions And Whole Numbers

Greg lives \(\displaystyle \frac{6}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{1}{4}\) of the way there and then stopped to tie his shoe. How far did he travel before he stopped to tie his shoe? 

Possible Answers:

\(\displaystyle \frac{7}{28}\textup { of a mile}\)

\(\displaystyle 7\textup { miles}\)

\(\displaystyle \frac{5}{28}\textup { of a mile}\)

\(\displaystyle \frac{6}{28}\textup { of a mile}\)

\(\displaystyle 5\textup { miles}\)

Correct answer:

\(\displaystyle \frac{6}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{1}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{6}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{1}{4}\times\frac{6}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

6 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 1\) and over \(\displaystyle 6\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{1}{4}\times\frac{6}{7}=\frac{6}{28}\)

Example Question #85 : Operations With Fractions And Whole Numbers

Dan lives \(\displaystyle \frac{6}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{2}{4}\) of the way there and then stopped to tie his shoe. How far did he travel before he stopped to tie his shoe? 

 

Possible Answers:

\(\displaystyle 7\textup { miles}\)

\(\displaystyle \frac{7}{28}\textup { of a mile}\)

\(\displaystyle 12\textup { miles}\)

\(\displaystyle \frac{12}{28}\textup { of a mile}\)

\(\displaystyle \frac{8}{28}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{12}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{2}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{6}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{2}{4}\times\frac{6}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

12 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 2\) and over \(\displaystyle 6\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{2}{4}\times\frac{6}{7}=\frac{12}{28}\)

 

Example Question #86 : Operations With Fractions And Whole Numbers

Tim lives \(\displaystyle \frac{6}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{3}{4}\) of the way there and then stopped to pet a dog. How far did he travel before he stopped to pet the dog? 

Possible Answers:

\(\displaystyle 18\textup { miles}\)

\(\displaystyle \frac{9}{28}\textup { of a mile}\)

\(\displaystyle \frac{18}{28}\textup { of a mile}\)

\(\displaystyle 9\textup { miles}\)

\(\displaystyle \frac{14}{28}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{18}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{3}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{6}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{3}{4}\times\frac{6}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

18 28


We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 3\) and over \(\displaystyle 6\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{3}{4}\times\frac{6}{7}=\frac{18}{28}\)

Example Question #51 : Interpret The Product (A/B) × Q As A Part Of A Partition Of Q Into B Equal Parts: Ccss.Math.Content.5.Nf.B.4a

Zach lives \(\displaystyle \frac{5}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{3}{4}\) of the way there and then stopped to pet a dog. How far did he travel before he stopped to pet the dog? 

Possible Answers:

\(\displaystyle 11\textup { miles}\)

\(\displaystyle 8\textup { miles}\)

\(\displaystyle \frac{11}{28}\textup { of a mile}\)

\(\displaystyle \frac{8}{28}\textup { of a mile}\)

\(\displaystyle \frac{15}{28}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{15}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{3}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{5}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{3}{4}\times\frac{5}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

15 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 3\) and over \(\displaystyle 5\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{3}{4}\times\frac{5}{7}=\frac{15}{28}\)

Example Question #52 : Interpret The Product (A/B) × Q As A Part Of A Partition Of Q Into B Equal Parts: Ccss.Math.Content.5.Nf.B.4a

Charlie lives \(\displaystyle \frac{5}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{2}{4}\) of the way there and then stopped to pet a dog. How far did he travel before he stopped to pet the dog? 

Possible Answers:

\(\displaystyle \frac{7}{28}\textup { of a mile}\)

\(\displaystyle \frac{10}{28}\textup { of a mile}\)

\(\displaystyle 28\textup { miles}\)

\(\displaystyle \frac{3}{28}\textup { of a mile}\)

\(\displaystyle 7\textup { miles}\)

Correct answer:

\(\displaystyle \frac{10}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{2}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{5}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{2}{4}\times\frac{5}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

10 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 2\) and over \(\displaystyle 5\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{2}{4}\times\frac{5}{7}=\frac{10}{28}\)

Example Question #53 : Interpret The Product (A/B) × Q As A Part Of A Partition Of Q Into B Equal Parts: Ccss.Math.Content.5.Nf.B.4a

Russell lives \(\displaystyle \frac{5}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{1}{4}\) of the way there and then stopped to pet a dog. How far did he travel before he stopped to pet the dog? 

 

Possible Answers:

\(\displaystyle 28\textup { miles}\)

\(\displaystyle 4\textup { miles}\)

\(\displaystyle \frac{5}{28}\textup { of a mile}\)

\(\displaystyle \frac{4}{28}\textup { of a mile}\)

\(\displaystyle \frac{6}{28}\textup { of a mile}\)

Correct answer:

\(\displaystyle \frac{5}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{1}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{5}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{1}{4}\times\frac{5}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

5 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 1\) and over \(\displaystyle 5\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{1}{4}\times\frac{5}{7}=\frac{5}{28}\)

 

Example Question #54 : Interpret The Product (A/B) × Q As A Part Of A Partition Of Q Into B Equal Parts: Ccss.Math.Content.5.Nf.B.4a

Shaun lives \(\displaystyle \frac{4}{7}\) of a mile away from his friend's house. He walked \(\displaystyle \frac{3}{4}\) of the way there and then stopped to pet a dog. How far did he travel before he stopped to pet the dog? 

 

 

Possible Answers:

\(\displaystyle \frac{12}{28}\textup { of a mile}\)

\(\displaystyle \frac{1}{28}\textup { of a mile}\)

\(\displaystyle 1\textup { mile}\)

\(\displaystyle \frac{7}{28}\textup { of a mile}\)

\(\displaystyle 12\textup { miles}\)

Correct answer:

\(\displaystyle \frac{12}{28}\textup { of a mile}\)

Explanation:

A keyword in our question that gives us a clue that we are going to multiply to solve this problem is the word "of". \(\displaystyle \frac{3}{4}\) of the way to his friends house he stopped. 

We know that his friend lives \(\displaystyle \frac{4}{7}\) of a mile away from him so we can set up our multiplication problem. 

\(\displaystyle \frac{3}{4}\times\frac{4}{7}\)

We can set up a tiled area model to help us solve the problem.

We use the denominators for the dimensions of our area model, and we use the numerators to fill parts of the area model.

 

12 28

We make the area model \(\displaystyle 7\) by \(\displaystyle 4\) because those are the denominators of our fractions. We shade up \(\displaystyle 3\) and over \(\displaystyle 4\), because those are the numerators of our fractions. Our answer is a fraction made up of the boxes that are shaded (the numerator) and the total tiles in the area model (the denominator).  

\(\displaystyle \frac{3}{4}\times\frac{4}{7}=\frac{12}{28}\)

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