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High School Math : How to solve two-step equations with integers in pre-algebra

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Example Questions

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $\frac{x}{4}+16=48$

Possible Answers:

x=8

x=128

x=16

x=64

Correct answer:

x=128

Explanation:

To solve for , begin by subtracting from both sides of the equation:

$\frac{x}{4}+16-16=48-16$

$\frac{x}{4}=32$

Then multiply both sides by :

$\frac{x}{4}\cdot 4=32\cdot 4$

x=128

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Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for if, 4(x+8)=72

Possible Answers:

x=10

x=4

x=8

x=12

Correct answer:

x=10

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

4x+32=72

Then subtract from both sides of the equation:

4x+32-32=72-32

4x=40

Then divide each side of the equation by :

$\frac{4x}{4}=\frac{40}{4}$

x=10

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Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 8(x-7)=40

Possible Answers:

$x=\frac{47}{8}$

x=14

x=12

x=8

Correct answer:

x=12

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

8x-56=40

Then add to both sides of the equation:

8x-56+56=40+56

8x=96

Then divide both sides by :

$\frac{8x}{8}=\frac{96}{8}$

x=12

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Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 7x-82=2

Possible Answers:

x=48

x=24

x=16

x=12

Correct answer:

x=12

Explanation:

To solve for , first add to both sides of the equation:

7x-82+82=2+82

7x=84

Then divide each side of the equation by :

$\frac{7x}{7}=\frac{84}{7}$

x=12

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Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $\frac{x}{9}+71=89$

Possible Answers:

x=144

x=162

x=81

x=9

Correct answer:

x=162

Explanation:

To solve for , first subtract from both sides of the equation:

$\frac{x}{9}+71-71=89-71$

$\frac{x}{9}=18$

Then multiply each side of the equation by :

$\frac{x}{9}\cdot 9=18\cdot 9$

x=162

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Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when -3(x+16)=12

Possible Answers:

x=-28

x=7

x=-20

x=20

Correct answer:

x=-20

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

-3x-48=12

Then add to both sides of the equation:

-3x-48+48=12+48

-3x=60

Then divide both sides of the equation by :

$\frac{-3x}{-3}=\frac{60}{-3}$

x=-20

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Example Question #74 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when 8x+64=128

Possible Answers:

x=8

x=64

x=36

x=16

Correct answer:

x=8

Explanation:

To solve for , first subtract from both sides of the equation:

8x+64-64=128-64

8x=64

Then divide both sides of the equation by :

$\frac{8x}{8}=\frac{64}{8}$

x=8

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Example Question #75 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $\frac{x}{13}-8=6$

Possible Answers:

x=64

x=80

x=28

x=182

Correct answer:

x=182

Explanation:

To solve for , first add to both sides of the equation:

$\frac{x}{13}-8+8=6+8$

$\frac{x}{13}=14$

Then multiply both sides of the equation by :

$\frac{x}{13}\cdot 13=14\cdot 13$

x=182

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Example Question #76 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when -6(x-3)=30

Possible Answers:

x=8

x=4

x=-2

x=2

Correct answer:

x=-2

Explanation:

To solve for , first distribute the outside the parentheses to both values inside the parentheses:

-6x+18=30

Then subtract from both sides of the equation:

-6x+18-18=30-18

-6x=12

Then divide both sides by :

$\frac{-6x}{-6}=\frac{12}{-6}$

x=-2

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Example Question #77 : How To Solve Two Step Equations With Integers In Pre Algebra

Solve for when $7x^{2}=112$

Possible Answers:

$x=\pm3$

$x=\pm6$

$x=\pm4$

$x=\pm7$

Correct answer:

$x=\pm4$

Explanation:

To solve for , first divide both sides of the equation by :

$\frac{7x^{2}}{7}=\frac{112}{7}$

$x^{2}=16$

Then take the square root of both sides of the equation:

$\sqrt{x^{2}}=\sqrt{16}$

x=4

However, remember that $(-4)^{2}$ is also equal to , so the answer is both positive and negative .

$x=\pm4$

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High School Math : How to solve two-step equations with integers in pre-algebra

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #71 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #72 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #73 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #74 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #75 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #76 : How To Solve Two Step Equations With Integers In Pre Algebra

Example Question #77 : How To Solve Two Step Equations With Integers In Pre Algebra

All High School Math Resources

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