All High School Math Resources
Example Questions
Example Question #196 : Algebraic Equations
Solve for if .
To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted so we must add the number, , to each side of the equation
Perform the math so our equation becomes .
Then we divide each side of the equation by the number that is in front of to get by itself
Perform the math to find the answer
The answer is .
Example Question #197 : Algebraic Equations
Solve for if .
To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted so we must add the number, , to each side of the equation
Perform the math so our equation looks like
Then we divide each side of the equation by the number that is in front of to get by itself
Perform the math to find the answer .
Example Question #198 : Algebraic Equations
Solve for if
The problem above is a two-step algebra problem with distribution.
To solve you must first distribute the outside of the parentheses into both of the numbers inside by multiplying.
Remember when you distribute a negative that both of the numbers inside the parentheses are being multiplied by a negative number so they must flip signs.
Our problem now looks like
Then we must get our variable, , by itself.
We must add the number, , to each side of the equation
Perform the math so our equation looks like
Then we divide each side of the equation by the number that is in front of to get by itself
Solve the math to find the answer .
Example Question #41 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if
When there are variables and numbers on each side of the equation, to solve we must mathematically move the variables onto one side and the numbers onto the other.
To do this we put all of the variables on the right side of the equal sign by subtracting from the each side of the equation to have
When adding or subtracting variables you only add or subtract the numbers in front of the variables. If there is no number the number value is .
Perform the math
Then to get all of the integers to the left side we will add to each side of the equation to have
Perform the math
The answer is .
Example Question #42 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for where .
To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being added so we must subtract the number, , from each side of the equation
Perform the math so our equation looks like
Then we divide each side of the equation by the number that is in front of to get by itself
Perform the math to find the answer .
Example Question #41 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for where
To perform a two-step algebra problem with addition and multiplication we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted so we must add the number, , to each side of the equation
Perform the math so our equation looks like
Then we divide each side of the equation by the number that is in front of to get by itself
Perform the math to find the answer .
Example Question #42 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if
The problem above is a two-step algebra problem with distribution.
To solve you must first distribute the outside of the parentheses into both of the numbers inside by multiplying.
Perform the multiplication with and each of the numbers inside the parentheses to get our new equation,
Then we must get our variable, , by itself.
We must subtract the number, , from each side of the equation
Perform the math so our equation looks like
Then we divide each side of the equation by the number that is in front of to get by itself
Solve the math to find the answer .
Example Question #203 : Algebraic Equations
Solve for if
To solve for we must get all of the numbers on the other side of the equation as .
When solving a simple two-step equation we must remove the numbers that are interacting with in this order: Addition/Subtraction, Multiplication/Division, Exponents.
To do this in a problem where is being multiplied by a number, we must divide both sides of the equation by the number.
In this case the number is so we divide each side of the equation by to make it look like this
Our simplified equation becomes
To solve an equation with we must take the square root of each side of the equation to get by itself.
Doing this makes our problem look like
Then we perform the square root to get the answer
Remember that can also equal so our answer will be both positive and negative.
The final answer looks like .
Example Question #45 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if
To perform a two step algebra problem with addition and division we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being subtracted so we must add the number, , to each side of the equation
Perform the math so our equation looks like
Then we multiply each side of the equation by the number that is under to get by itself
Perform the math to find the answer .
Example Question #46 : How To Solve Two Step Equations With Integers In Pre Algebra
Solve for if
To perform a two-step algebra problem with addition and division we must remove the numbers from so it is by itself on one side of the equation.
To do this we first look to see if a number is being added or subtracted from .
In this case a number is being added so we must subtract the number, , from each side of the equation
Perform the math so our equation looks like
Then we multiply each side of the equation by the number that is in front of to get by itself
Perform the math to find the answer .
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