Using the Pythagorean Theorem, we can find the edge of a side to be √50, by 2a²=10². This can be reduced to 5√2. This can then be multiplied by 4 to find the perimeter. 

We start by dividing the area of square R (48) by 12, to come up with the area of square T, 4.  Then take the square root of the area to get the length of one side, giving us 2.

Let x represent the length of the original square in inches.  Thus the area of the original square is x².  Two inches are added to x, which is represented by x+2.  The area of the resulting square is (x+2)².  We are given that the new square is 64 sq. inches greater than the original.  Therefore  we can write the algebraic expression:

x² + 64 = (x+2)²

FOIL the right side of the equation.

x² + 64 = x² + 4x + 4 

Subtract x² from both sides and then continue with the alegbra.

64 = 4x + 4

64 = 4(x + 1)

16 = x + 1

15 = x

Therefore, the length of the original square is 15 inches.

If you plug in the answer choices, you would need to add 2 inches to the value of the answer choice and then take the difference of two squares.  The choice with 15 would be correct because 17² -15² = 64.

The area of a square is equal to length times width or length squared (since length and width are equal on a square). Therefore, the length of one side is  or  The perimeter of a square is the sum of the length of all 4 sides or

Given that the square's diagonals pass through the circle's center, those diagonals must each form a diameter of the circle. The circle's diameter is twice its radius, i.e. , which is . Since this diameter (i.e., the square's diagonal) is the hypotenuse of a right triangle formed by two sides of the square, the length of one of the square's sides can be calculated with the Pythagorean Theorem.  replace  and  because the sides of the square must be equal in length. Since the objective is to solve for the square's area, solve for  since one side squared will be the square's area.

 units squared

Quadrilateral ABCD has four ninety-degree angles, which means that it has four right angles because every right angle measures ninety degrees. If a quadrilateral has four right angles, then it must be a rectangle by the definition of a rectangle. This means statement I is definitely true.

However, just because ABCD has four right angles doesn't mean that it is a rhombus. In order for a quadrilateral to be considered a rhombus, it must have four congruent sides. It's possible to have a rectangle whose sides are not all congruent. For example, if a rectangle has a width of 4 meters and a length of 8 meters, then not all of the sides of the rectangle would be congruent. In fact, in a rectangle, only opposite sides need be congruent. This means that ABCD is not necessarily a rhombus, and statement II does not have to be true.

A square is defined as a rhombus with four right angles. In a square, all of the sides must be congruent. In other words, a square is both a rectangle and a rhombus. However, we already established that ABCD doesn't have to be a rhombus. This means that ABCD need not be a square, because, as we said previously, not all of its sides must be congruent. Therefore, statement III isn't necessarily true either.

The only statement that has to be true is statement I.

The answer is I only.

A rhombus is any quadrilateral with four congruent sides. A square is a quadrilateral with four congruent sides and four right angles. A square is also a rhombus.

Rectangles will have two pairs of congruent sides, but not all four sides will be congruent.

If the diagonals of a quadrilateral are perpendicular bisectors of one another, then the quadrilateral must be a rhombus, but not necessarily a square. Since all rhombi are also parallelograms, quadrilateral ABCD must be both a rhombus and parallelogram.

In order to determine the area of a rhombus you either need a base and a height OR the length of the two diagonals OR the base and an angle.  Because we are only given the base with no information about the height, there is not enough information to determine the area of the rhombus.

The formula for the perimeter of a rhombus is:

Where  is the length of the side

Plugging in our values, we get:

The formula for the area of a rhombus is:

Where  is the length of one diagonal and  is the length of another diagonal

By drawing the diagonals, we create a right triangle with the hypotenuse as  and the side as .

Since we know that  is a phythagorean triple, we can infer that the third side is .

Plugging in our values, we get: