GRE Subject Test: Chemistry : General Chemistry

Study concepts, example questions & explanations for GRE Subject Test: Chemistry

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Example Questions

Example Question #11 : Acid Base Reactions

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If 4.2 moles of  is reacted with 3.5 moles of , how many grams of  is produced?

Possible Answers:

Correct answer:

Explanation:

 is the limiting reactant because based on the equation,  and react in a 1:1 mole ratio. However, there is 0.5 moles more of  than  therefore the amount of  produced is limited by the amount of present in the reaction. Based on the equation for every 1 mole of  reacted, 1 mole of  was produced:

Therefore,

Example Question #13 : Acid Base Chemistry

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Determine the acid dissociation constant for a  monoprotic acid  dissolved in the  in which a pH meter for read pH  for the solution.

Possible Answers:

Correct answer:

Explanation:

The acid dissociation constant expression for this reaction is:

Due to the dissociation of :

Using the following equation, we can calculate the  concentration:

Plug the values obtained in to the acid dissociation constant expression:

Example Question #1 : Titrations

Which of the following pH values is an acceptable equivalence point for a weak base being titrated by a strong acid?

Possible Answers:

Correct answer:

Explanation:

The equivalence point is the point during a titration when there are equal equivalents of acid and base in the solution. Since a strong acid will have more effect on the pH than the same amount of a weak base, we predict that the solution's pH will be acidic at the equivalence point. 5.2 and 1.3 are both acidic, but 1.3 is remarkably acidic considering that there is an equal amount of base in the solution. As a result, 5.2 is a more appropriate answer.

The equivalence point for a strong acid and strong base will be 7.0. When one of the compounds is weak, however, it will dissociate less than its strong counterpart. In our case, the base will dissociate less than the acid. The acid, thus, contributes more to the pH character of the solution.

Example Question #1 : Titration Curves

A weak acid is slowly titrated with a strong base. Where on the titration curve would the solution be the most well-buffered?

Possible Answers:

The half equivalence point

The equivalence point

When the amount of base added equals the amount of acid in the solution.

When no base has been added

Correct answer:

The half equivalence point

Explanation:

At the half equivalence point, the concentration of acid in the solution is equal to the concentration of the conjugate base in solution. At this point, the graph shows a line that is near horizontal. This means that base or acid could be added and the pH of the solution would change very slowly.

Remember that pH is on the y-axis of the titration curve; thus a near-horizontal line will signify a region where pH is most stable. At the half equivalence point, pH = pKa.

Example Question #2 : Titration Curves

Which of the following curves represents the titration of a strong base by a strong acid?

Possible Answers:

C

D

A

B

Correct answer:

A

Explanation:

Since we are adding acid to a base, the pH must decrease. The initial base will have a high pH, while the final acid will have a low pH; the right of the curve must be lower than the left. In addition, the pH does not change very rapidly until the equivalence point is reached, hence the curve must show little initial change followed by a rapid change.

Example Question #2 : Titrations

Which of the following is an indication of when a reaction has reached the equivalence point.

Possible Answers:

When the volume of both reactants are equal

When there is a color change

The end point of a titration

Moles of titrant equals moles of analyte

Correct answer:

Moles of titrant equals moles of analyte

Explanation:

The equivalence point is the point in a titration at which the number of moles of titrant equals the number of moles of analyte. The endpoint in a titration is when the color of the reaction changes to that of the desired (often neutral) pH. However this is not the same as the equivalence point, which is a stoichiometric value. Indicators may change colors several times throughout a neutralization reaction, thus this is not an accurate attribute of the reaction to use as the equivalence point. Furthermore, the concentrations of titrant and the analyte are rarely equivalent, and there could be differing numbers of ionizable groups on each species.

Example Question #3 : Titrations

Considering the given chemical reaction, determine the number of moles of  in a 20mL solution if it takes 19.00mL of a 0.0500M  solution to reach the endpoint of a titration.

Possible Answers:

Correct answer:

Explanation:

 and  react in a 1:1 mole ratio. Therefore the number of moles of  at the end point of the reaction equals to the number of moles of . We can use the concentration as a conversion factor to determine the number of moles reacted.

Example Question #4 : Titrations

Considering the given chemical reaction, determine the concentration of  in a 40.00mL solution if it takes 25.00mL of a 0.0350M  solution to reach the endpoint of a titration.

Possible Answers:

Correct answer:

Explanation:

 and  react in a 1:1 mole ratio. Therefore the number of moles of  at the end point of the reaction equals to the number of moles of .

Example Question #5 : Titrations

Considering the given neutralization reaction, what is the concentration of the sodium chloride solution if it takes 20.00mL of 0.045M  to neutralize 20mL of the  solution?

Possible Answers:

Correct answer:

Explanation:

Based on the equation given, we know the that  reacts with  in a 1:1 mole ratio. We can use the molar concentration given as a conversion factor to determine the number of moles of  used which will be equal to the number of moles of  used.

To determine the molar concentration of  used, we can simply use the following equation:

We have determined that the concentration of  used is equal to the concentration of  used.

Example Question #6 : Titrations

A vinegar sample was determined by a titration with  to have  moles  of  in a 2.00 grams of vinegar. What would be the percent mass of this vinegar solution?

Possible Answers:

Correct answer:

Explanation:
We must first calculate the molecular weight of
We can calculate the grams of  using the molecular weight calculated as a conversion factor:
Finally, we can calculate the percent mass using the total grams of vinegar solution:
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