All GRE Subject Test: Biochemistry, Cell, and Molecular Biology Resources
Example Questions
Example Question #75 : Molecular Biology And Genetics
Genome projects on Drosophila and Anopheles have identified approximately 6,000 1:1 orthologs ranging from 100% to 20% identity. Why were no orthologs at a lower identity identified?
These insects are too closely related to identify them
There are many orthologs present at other ratios clouding the data
No orthologs would exist below this threshold
It is almost impossible to align these sequences
None of these are correct
It is almost impossible to align these sequences
When two sequences have less than 20% identity, it is almost impossible to align them and identify that they are actually orthologs. This is especially the case in huge genome data sets, in which it is impossible to find matching sequences by hand.
Example Question #1 : Help With Genome Evolution
What are pseudogenes?
A gene resulting from a duplication event that has degenerated and lost its function
A gene that is no longer functional
A gene that has multiple copies in the genome
A gene with a similar function to another gene
None of these are correct
A gene resulting from a duplication event that has degenerated and lost its function
The key factors that distinguish pseudogenes are that they are sequences that result from a duplication event in the genome, but have since mutated without selection pressure and have become nonfunctional.
Example Question #2 : Help With Genome Evolution
Organisms with extremely large genomes tend to have high amounts of what?
Recombination
Intron duplication
Transposons
None of these are correct
Viral DNA insertions
Transposons
Organisms with large genomes tend to have very high levels of transposons. For instance, this is the case in our own genomes. It is hypothesized that in some organisms, there is a breakdown of systems that control insertion of transposons into the genome, resulting in large expansions.
Example Question #1 : Help With Transcription Proteins
In eukaryotes, which RNA polymerase makes rRNA?
RNA polymerase IV
RNA polymerase III
RNA polymerase II
RNA polymerase I
RNA polymerase I
The RNA polymerases are numbered in the order that their products are used in protein synthesis.
RNA polymerase I makes ribosomal rRNA in eukaryotes.
RNA polymerase II makes messenger mRNA in eukaryotes.
RNA polymerase III makes transfer tRNA in eukaryotes.
Example Question #1 : Help With Transcription Proteins
Which of the following subunits of RNA polymerase is solely required for initiation of transcription?
(beta)
(omega)
(sigma)
(alpha)
(sigma)
The sigma factor is solely required for the initiation of transcription. In fact, the sigma subunit will often fall off of the enzyme during the elongation phase of transcription. Binding of the sigma factor is an important signal for transcription to begin.
The other subunits are crucial to the elongation and termination phases.
Example Question #1 : Rna, Transcription, And Translation
Which of the following codons is the mRNA start codon that initiates translation?
UGA
UAA
AUG
UAG
AUG
The codon AUG initiates translation in both eukaryotes and prokaryotes. Interaction with this codon by a tRNA molecule allows a methionine residue to enter the ribosome and serve as the starting point for amino acid elongation.
UGA, UAA, and UAG are mRNA stop codons and stop protein synthesis by causing the ribosomal subunits to dissociate and release the polypeptide.
Example Question #1 : Transcription And Rna
Which of the following best describes the key function of helicases during transcription?
Cleaving methyl groups from an unwound DNA strand.
Separation of two strands of DNA; "unwinding" gives polymerases access to the strand.
Re-annealing of two DNA strands once transcription and translation processes are complete.
Catalyzing the interaction between transcription factors and the DNA strand.
Relief of tension in the DNA strands to prevent breakage.
Separation of two strands of DNA; "unwinding" gives polymerases access to the strand.
Helicases are required for separating two DNA strands so that the rest of transcription can take place. Polymerases work on single strands of DNA, thus the bonds holding the double strands together must be removed.
Example Question #1 : Rna, Transcription, And Translation
Transcription factors that are the first to bind DNA in heterochromatin regions, often promote euchromatin formation, and recruit other transcriptional machinery to promote transcription are best known as which of the following?
Histone demethyltransferases
RNA holoenzyme
Co-factors
Pioneer factors
DNA Polymerases
Pioneer factors
The correct answer is pioneer factors. Pioneer factors are able to bind DNA in condensed regions and promote euchromatin formation by recruitment of histone demethyltransferases and acteyltransfereses to modify proximal histones. Additionally, these pioneer factors recruit other transcription factors and co-factors to promote transcription. DNA polymerases are involved with DNA replication, not transcription. The RNA holoenzyme is a protein complex consisting of RNA polymerase, transcription factors, and regulator proteins that binds promoters and catalyzes transcription.
Example Question #1 : Rna, Transcription, And Translation
Before RNA polymerase can initiate transcription, this protein must bind to it, creating the RNA polymerase holoenzyme and allowing for the initiation of transcription.
Sigma factor
Topoisomerase
Helicase
Beta factor
Activator protein
Sigma factor
RNA polymerase cannot initiate transcription by itself. It binds to the promoter but must wait for a sigma factor to bind to it. Now the RNA polymerase holoenzyme can proceed with transcription.
Example Question #2 : Rna, Transcription, And Translation
Which of the following is not dependent on the C-terminal domain (CTD) of RNA polymerase II?
None of the other answers
mRNA splicing
5' capping
Transcription termination
Polyadenylation
None of the other answers
The correct answer is none of the other answers. Only mRNA transcribed by polymerase II undergo 5' capping, polyadenylation, and splicing. The C-terminal domain of this polymerase serves as a binding site and docking platform for many of the enzymes that initiate these processes. Moreover, experiments in which the CTD is truncated show that mRNA transcripts are not capped, polyadenylated, and spliced.