All Differential Equations Resources
Example Questions
Example Question #1 : Introduction To Differential Equations
State the order of the given differential equation and determine if it is linear or nonlinear.
Third ordered, linear
Second ordered, linear
Third ordered, nonlinear
Fourth ordered, linear
Second ordered, nonlinear
Third ordered, linear
This problem contains two questions that need to be solved for: order of the differential equation and whether it is linear or nonlinear.
To determine the order of the differential equation, look for the highest derivative in the equation.
For this particular function recall that,
therefore the highest derivative is three which makes the equation a third ordered differential equation.
The second part of this problem is to determine if the equation is linear or nonlinear. For a differential equation to be linear two characteristics must hold true:
1. The dependent variable and all its derivatives have a power involving one.
2. The coefficients depend on the independent variable .
Looking at the given function,
it is seen that all the variable and all its derivatives have a power involving one and all the coefficients depend on therefore, this differential equation is linear.
To answer this problem completely, the differential equation is a linear, third ordered equation.
Example Question #1 : Introduction To Differential Equations
Which of the following definitions describe an autonomous differential equation.
A differential equation that models growth exponentially.
A differential equation that has Eigen Values of 0.
A differential equation that does not depend explicitly on the independent variable of the equation; usually denoted or .
A differential equation that does not depend explicitly on the dependent variable of the equation; usually denoted .
A differential equation that does not depend explicitly on the independent variable of the equation; usually denoted or .
By definition, an autonomous differential equation does not depend explicitly on the independent variable. An autonomous differential equation will take the form
Example Question #2 : Introduction To Differential Equations
State the order of the given differential equation and determine if it is linear or nonlinear.
Second ordered, nonlinear
Third ordered, linear
Second ordered, linear
Third ordered, nonlinear
Fourth ordered, linear
Third ordered, linear
This problem contains two questions that need to be solved for: order of the differential equation and whether it is linear or nonlinear.
To determine the order of the differential equation, look for the highest derivative in the equation.
For this particular function recall that,
therefore the highest derivative is three which makes the equation a third ordered differential equation.
The second part of this problem is to determine if the equation is linear or nonlinear. For a differential equation to be linear two characteristics must hold true:
1. The dependent variable and all its derivatives have a power involving one.
2. The coefficients depend on the independent variable .
Looking at the given function,
it is seen that all the variable and all its derivatives have a power involving one and all the coefficients depend on therefore, this differential equation is linear.
To answer this problem completely, the differential equation is a linear, third ordered equation.
Example Question #2 : Introduction To Differential Equations
Find Order and Linearity of the following differential equation
Third Order - NonLinear
Second Order - NonLinear
Second Order - Linear
Third Order - Linear
None of the other answers.
Third Order - Linear
This equation is third order since that is the highest order derivative present in the equation.
This is equation in linear because and derivatives appear to the first power only. and do not affect the linearity.
Example Question #41 : Differential Equations
If is some constant and the initial value of the function, is six, determine the equation.
First identify what is known.
The general function is,
The initial value is six in mathematical terms is,
From here, substitute in the initial values into the function and solve for .
Finally, substitute the value found for into the original equation.
Example Question #1 : Initial Value Problems
So this is a separable differential equation, but it is also subject to an initial condition. This means that you have enough information so that there should not be a constant in the final answer.
You start off by getting all of the like terms on their respective sides, and then taking the anti-derivative. Your pre anti-derivative equation will look like:
Then taking the anti-derivative, you include a C value:
Then, using the initial condition given, we can solve for the value of C:
Solving for C, we get
which gives us a final answer of:
Example Question #1 : Initial Value Problems
Solve the initial value problem for .
We have so that and . Solving for y,
and
which we can write because is just another arbitrary constant.
Plugging in our initial value, we have leaving us with a final answer of .
Note, this type of equation pops up frequently in the course and is potentially good to just memorize. For , we have
Example Question #1 : Initial Value Problems
With
So this is a separable differential equation with a given initial value.
To start off, gather all of the like variables on separate sides.
Then integrate, and make sure to add a constant at the end
To solve for y, take the natural log, ln, of both sides
Be careful not to separate this, a log(a+b) can't be separated.
Plug in the initial condition to get:
So raising e to the power of both sides:
Solving for C:
giving us a final answer of:
Example Question #1 : Initial Value Problems
Solve the separable differential equation
with the initial condition
none of these answers
So this is a separable differential equation with a given initial value.
To start off, gather all of the like variables on separate sides.
Notice that when you divide sec(y) to the other side, it will just be cos(y),
and the csc(x) on the bottom is equal to sin(x) on the top.
Integrating, we get:
so we can plug pi/4 into both x and y:
this gives us a C value of
In order to solve for y, we just need to take the arcsin of both sides:
Example Question #1 : Initial Value Problems
Solve the differential equation
Subject to:
none of these answers
So if you rearrange this equation, you will arrive at a separable differential equation by adding the to the other side:
Now, to solve this, multiply the dx to the other side and take the anti-derivative:
Then, after the anti-derivative, make sure to add the constant C:
Now, plug in the initial condition that y(0)=0, which will give you a C=0 as well. Then just take the square root, and you arrive at:
Then, to get the correct answer, simplify by factoring out an and pulling it outside of the square root to get:
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