All Calculus 3 Resources
Example Questions
Example Question #41 : Cross Product
Determine the cross product , if and
The cross product of two vectors is a new vector. In order to find the cross product, it is useful to know the following relationships between the directional vectors:
Note how the sign changes when terms are reordered; order matters!
Scalar values (the numerical coefficients) multiply through, e.g:
With these principles in mind, we can calculate the cross product of our vectors and
Example Question #42 : Cross Product
Determine the cross product , if and
The cross product of two vectors is a new vector. In order to find the cross product, it is useful to know the following relationships between the directional vectors:
Note how the sign changes when terms are reordered; order matters!
Scalar values (the numerical coefficients) multiply through, e.g:
With these principles in mind, we can calculate the cross product of our vectors and
Example Question #43 : Cross Product
Which of the following is true? (assume all vectors are -dimensional. is the acute angle between the two vectors.)
All of the other answers are false.
There are a few approaches to answering this.
One is to notice that the right hand side of each equation is some number times some number times some other number, whereas is a vector. It is not possible for a vector to equal a number (or a "scalar" technically), so
, and
are out of the question.
is not correct since the right hand side of the equation is the definition of the dot product of two vectors, which is not represented by the left hand side.
is true. While it's not the definition of the cross product, it is a formula used to find the area of the parallelogram formed by vectors .
Example Question #44 : Cross Product
Evaluate .
None of the other answers
To evaluate the cross product, we use the determinant formula
.
So we have
Example Question #45 : Cross Product
Evaluate
None of the other answers
A quick way to answer this is to note that the two vectors point in the same direction (one is a scalar multiple of the other). Hence they are parallel, and their cross product is the zero vector.
We can still use the formula
to evaluate it as well.
We have
Example Question #46 : Cross Product
Evaluate the following cross product:
where:
The cross product is the determinant of the following matrix:
Which is equal to:
Which, in bracket form, is the same as
Example Question #51 : Cross Product
Find the cross product of the two vectors
The cross product of the two vectors
is defined as the determinant of the matrix
For the vectors in the problem we solve the determinant of the matrix
which is
Example Question #52 : Cross Product
Find the cross product of the two vectors:
To find the cross product of two vectors, we must write the determinant of the vectors:
Next, we take the cross product. One can do this by multiplying across from the top left to the lower right, and continuing downward, and then subtracting the terms multiplied from top right to the bottom left:
The vector is written in unit vector notation. We simply take the coefficients of our unit vectors and correspond them to x, y, and z:
Example Question #53 : Cross Product
Determine the cross product (in vector notation) of the vectors
and
We must first write the determinant in order to take the cross product of the two vectors:
where i, j, and k are the unit vectors corresponding to the x, y, and z direction respectively.
Next, we take the cross product. One can do this by multiplying across from the top left to the lower right, and continuing downward, and then subtracting the terms multiplied from top right to the bottom left:
Writing this in vector notation, we get
Example Question #54 : Cross Product
Find the cross product of the two vectors, in standard form:
To start, we must write the determinant in order to take the cross product of the two vectors:
where i, j, and k are the unit vectors corresponding to the x, y, and z direction respectively.
Next, we take the cross product. One can do this by multiplying across from the top left to the lower right, and continuing downward, and then subtracting the terms multiplied from top right to the bottom left:
which simplified becomes
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