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Example Questions
Example Question #1151 : Calculus
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #132 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using four midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #133 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #134 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #135 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using two midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #136 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #137 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #138 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #139 : Midpoint Riemann Sums
Utilize the method of midpoint Riemann sums to approximate using three midpoints.
A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length and variable heights , which depend on the function value at a given point .
We're asked to approximate
So the interval is , the subintervals have length , and since we are using the midpoints of each interval, the x-values are
Example Question #131 : Differential Functions
Utilize the method of midpoint Riemann sums to approximate the average of over the interval using four midpoints.
To find the average of a function over a given interval of values , the most precise method is to use an integral as follows:
Now for functions that are difficult or impossible to integrate,a Riemann sum can be used to approximate the value. A Riemann sum integral approximation over an interval with subintervals follows the form:
It is essentially a sum of rectangles each with a base of length equal to the subinterval length , and variable heights , which depend on the function value at a given point .
Now note that when using the method of Riemann sums to find an average value of a function, the expression changes:
We're asked to approximate the average of over the interval
The subintervals have length , and since we are using the midpoints of each interval, the x-values are