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Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

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All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #14 : How To Find The Area Of A Rectangle

What is the area of a rectangle that has a length of and a width of 0.75 ?

Possible Answers:

55.25

63.75

76.75

69.75

Correct answer:

63.75

Explanation:

Recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, plug in the given length and width to find the area.

When multiplying decimals together first move the decimal over so that the number is a whole integer.

$0.75\rightarrow 75$

Now we multiple the integers together.

$0.75\cdot 85\rightarrow 75\cdot 85=6375$

From here, we need to move the decimal place back. In this particular problem we moved the decimal over a total of two decimal places.

Therefore our answer becomes,

$6375\rightarrow 63.75$

$\text{Area}=85 \times 0.75= 63.75$

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Example Question #15 : How To Find The Area Of A Rectangle

What is the area of a rectangle that has a length of and a width of $\frac{1}{7}$ ?

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Now, plug in the given length and width to find the area.

When multiplying fractions, multiply the numerators together and multiply the denominators together. After multiplication is done, find common factors in the numerator and denominator to cancel out and completely simplify the fraction. In this particular case the integer can be written as a fraction by putting it over one.

$\textup{Area}=\frac{63}{1}\times \frac{1}{7}$

$\text{Area}= \frac{1 \times 63 }{7\times 1}= \frac{63}{7}=\frac{7\cdot 9}{7}=9$

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Example Question #16 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{24}{2}-5=7$

Simplify.

$\text{Width}=7$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=5 \times 7$

Solve.

$\text{Area}=35$

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Example Question #17 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{18}{2}-6$

Simplify.

$\text{Width}=3$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=6 \times 3$

Solve.

$\text{Area}=18$

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Example Question #167 : Quadrilaterals

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{36}{2}-12$

Simplify.

$\text{Width}=6$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=12 \times 6$

Solve.

$\text{Area}=72$

Report an Error

Example Question #571 : Basic Geometry

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

144

132

156

168

Correct answer:

156

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{50}{2}-13$

Simplify.

$\text{Width}=12$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=13 \times 12$

Solve.

$\text{Area}=156$

Report an Error

Example Question #572 : Basic Geometry

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{28}{2}-13$

Simplify.

$\text{Width}=1$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=13 \times 1$

Solve.

$\text{Area}=13$

Report an Error

Example Question #575 : Plane Geometry

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

280

130

140

160

Correct answer:

140

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{48}{2}-10$

Simplify.

$\text{Width}=14$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=10 \times 14$

Solve.

$\text{Area}=140$

Report an Error

Example Question #576 : Plane Geometry

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

175

250

350

300

Correct answer:

250

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{70}{2}-25$

Simplify.

$\text{Width}=10$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=25 \times 10$

Solve.

$\text{Area}=250$

Report an Error

Example Question #576 : Plane Geometry

If the perimeter of a rectangle is , and the length fo the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{40}{2}-5$

Simplify.

$\text{Width}=15$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=5 \times 15$

Solve.

$\text{Area}=75$

Report an Error

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Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #14 : How To Find The Area Of A Rectangle

Example Question #15 : How To Find The Area Of A Rectangle

Example Question #16 : How To Find The Area Of A Rectangle

Example Question #17 : How To Find The Area Of A Rectangle

Example Question #167 : Quadrilaterals

Example Question #571 : Basic Geometry

Example Question #572 : Basic Geometry

Example Question #575 : Plane Geometry

Example Question #576 : Plane Geometry

Example Question #576 : Plane Geometry

All Basic Geometry Resources

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