All AP Physics 2 Resources
Example Questions
Example Question #5 : Poiseuille Flow And Turbulence
Use the following information to answer questions 1-6:
The circulatory system of humans is a closed system consisting of a pump that moves blood throughout the body through arteries, capillaries, and veins. The capillaries are small and thin, allowing blood to easily perfuse the organ systems. Being a closed system, we can model the human circulatory system like an electrical circuit, making modifications for the use of a fluid rather than electrons. The heart acts as the primary force for movement of the fluid, the fluid moves through arteries and veins, and resistance to blood flow occurs depending on perfusion rates.
To model the behavior of fluids in the circulatory system, we can modify Ohm’s law of V = IR to ∆P = FR where ∆P is the change in pressure (mmHg), F is the rate of flow (ml/min), and R is resistance to flow (mm Hg/ml/min). Resistance to fluid flow in a tube is described by Poiseuille’s law: R = 8hl/πr4 where l is the length of the tube, h is the viscosity of the fluid, and r is the radius of the tube. Viscosity of blood is higher than water due to the presence of blood cells such as erythrocytes, leukocytes, and thrombocytes.
The above equations hold true for smooth, laminar flow. Deviations occur, however, when turbulent flow is present. Turbulent flow can be described as nonlinear or tumultuous, with whirling, glugging or otherwise unpredictable flow rates. Turbulence can occur when the anatomy of the tube deviates, for example during sharp bends or compressions. We can also get turbulent flow when the velocity exceeds critical velocity vc, defined below.
vc = NRh/ρD
NR is Reynold’s constant, h is the viscosity of the fluid, ρ is the density of the fluid, and D is the diameter of the tube. The density of blood is measured to be 1060 kg/m3.
Another key feature of the circulatory system is that it is set up such that the organ systems act in parallel rather than in series. This allows the body to modify how much blood is flowing to each organ system, which would not be possible under a serial construction. This setup is represented in Figure 1.
One of the effects of norepinephrine is vasoconstriction of peripheral blood vessels. If the medication reduces the diameter of a peripheral vessel in the hands by ½, what effect does this have on the flow of blood to hands?
Flow will decrease by a factor of 16
Flow will decrease by a factor of 8
Flow will increase by a factor of 8
Flow will increase by a factor of 16
Flow will decrease by a factor of 16
Resistance is measured by the equation .
If the diameter is reduced by half, the radius is reduced by half. This will increase resistance by a factor of 24, or 16. We know that the circulatory system is set up as a parallel system so the pressure in any branch must be constant, allowing only flow to change. Using the equation ∆P = FR, if resistance increases by a factor of 16 and the flow stays the same, then flow decreases by a factor of 16 since pressure is constant.
∆P = F2R2 – F1R1 = 0
16R1 = R2
F2R2 = F1R1
F216R1 = F1R1
F2= (1/16)F1
Example Question #6 : Poiseuille Flow And Turbulence
Which change will produce the greatest increase to flow rate through a tube?
Tripling the length of the tube while halving the pressure
Quadrupling the pressure
Doubling the radius
Halving the length of the tube while tripling the pressure
Doubling the pressure
Doubling the radius
The equation for flow rate through a section of tube is given by Poiseulle's law. Though you will not need to memorize this equation, you must be familiar with the relationships it describes on a conceptual basis.
In this equation, is the radius, is the change in pressure, is the liquid viscosity, and is the length of the tube.
Of the given answer option, doubling the radius would multiply the flow rate by , resulting in the greatest increase.
Example Question #71 : Fluids And Gases
Which of the following would tend to decrease the viscosity of a liquid flowing through a pipe?
Decreasing the diameter of the pipe
Decreasing the volumetric flow rate of the liquid
Increasing the length of the pipe
Increasing the temperature
Increasing the pressure
Increasing the temperature
The factors that influence viscosity are:
1. The molecular structure of the given liquid (i.e. what liquid is flowing)
2. Temperature
3. Extreme pressure
Liquids become less viscous with increased temperature. As temperature increases, the molecules move faster relative to one another and spend less time in contact with each other. This behavior causes the intermolecular forces to decrease, so the viscosity decreases.
Example Question #7 : Poiseuille Flow And Turbulence
A variation of Poiseuille's law, a relationship that helps explain fluid resistance in a pipe, is given by:
In the formula, is viscosity, is the length of the pipe, and is the diameter of the pipe.
Which one of the following effects would decrease resistance?
Increasing fluid temperature
Extending the pipe
Narrowing the pipe
Decreasing flow
Increasing fluid pressure
Increasing fluid temperature
This question can be answered quickly from logic, with little math involved. Temperature itself is not a direct variable in the given equation; however, it does relate to viscosity, . The warmer a fluid is, the lower the viscosity will become, and a fluid that is less viscous will flow more easily, creating less resistance.
The other answer choices either give changes that are unrelated to flow resistance, or increase flow resistance. Narrowing the pipe and increasing the length would increase resistance, according to the given equation. Flow and pressure can be affected by resistance, but cannot change the given resistance in a system.
Example Question #2 : Other Flow Principles
Diffusion can be defined as the net transfer of molecules down a gradient created by differing concentrations of the molecule in different locations. This is a passive, spontaneous process and relies on the random movement of molecules and Brownian motion. Diffusion is an important biological process, especially in the respiratory system where oxygen diffuses from alveoli, the basic units of lung mechanics, to red blood cells in the capillaries.
Figure 1 depicts this process, showing an alveolus separated from neighboring cells by a capillary with red blood cells. The partial pressures of oxygen and carbon dioxide are given. One equation used in determining gas exchange is Fick's law, given by:
In this equation, is the flow rate. Area and thickness refer to the permeable membrane through which the gas passes—in this case, the wall of the alveolus. and refer to the partial pressures upstream and downstream, respectively. , the diffusion constant of the gas, is defined as:
At high altitudes, the partial pressure of oxygen quickly drops while that of carbon dioxide decreases by much less. Given the following table, at what elevation is the pressure gradient of oxygen equal to half that of carbon dioxide, assuming constant capillary partial pressures of oxygen and carbon dioxide of 50mmHg and 40mmHg, respectively?
Elevation (m) |
PO2 (mmHg) |
PCO2 (mmHg) |
0 |
100 |
50 |
1000 |
80 |
40 |
2000 |
60 |
30 |
3000 |
40 |
20 |
4000 |
20 |
10 |
5000 |
10 |
0 |
This problem at first may seem straightforward, until you realize that the gradient (or difference in partial pressures of Fick's law) actually changes.
In normal circumstances, capillary pressure would be subtracted from arterial pressure; however, the body operates at a physiologic equilibrium, which essentially has a constant production of CO2 and demand for O2. At a certain point the capillary pressure will be greater than the arterial, and hence the gradient switches to Pcapillary – Parterial from the original Parterial – Pcapillary.
Simple arithmetic done alongside the table margins can quickly arrive to the correct answer. At an elevation of 3000 m, the gradients of oxygen (50 – 40 = 10 mmHg) and carbon dioxide (40 – 20 = 20 mmHg) differ by twofold. It is easy to be confused over a seemingly complicated table, when in reality, this question only asks for basic arithmetic.
Example Question #2 : Poiseuille Flow And Turbulence
Diffusion can be defined as the net transfer of molecules down a gradient created by differing concentrations of the molecule in different locations. This is a passive, spontaneous process and relies on the random movement of molecules and Brownian motion. Diffusion is an important biological process, especially in the respiratory system where oxygen diffuses from alveoli, the basic units of lung mechanics, to red blood cells in the capillaries.
Figure 1 depicts this process, showing an alveolus separated from neighboring cells by a capillary with red blood cells. The partial pressures of oxygen and carbon dioxide are given. One equation used in determining gas exchange is Fick's law, given by:
In this equation, is the flow rate. Area and thickness refer to the permeable membrane through which the gas passes—in this case, the wall of the alveolus. and refer to the partial pressures upstream and downstream, respectively. , the diffusion constant of the gas, is defined as:
Using the values from Figure 1, what is the flow rate of oxygen in terms of the flow rate of carbon dioxide, given that oxygen and carbon dioxide have equal permeability?
This question is tricky because it asks you oxygen's flow rate in terms of that of carbon dioxide's; however, this problem can also be quickly solved by calculating each flow rate separately. It is important to note that since we have been told that they have equal permeability, the only values they will differ by are their partial pressure differences and molecular weights. The partial pressure difference for oxygen is 100 – 50, or 50 mmHg, and that of carbon dioxide is 50 – 40, or 10 mmHg.
From here, we see that in terms of partial pressure, the flow rate of oxygen will be 5 times greater (50/10 = 5) than carbon dioxide; however, we still must account for molecular weights, which is on the bottom of the equation. The molecular weight for oxygen is 32, and 44 for carbon dioxide; therefore, we can set our equation up to find some factor, X, that when multiplied by Pcarbon dioxide, will give us Poxygen
Poxygen = (Area/Thickness) · solubility/321/2 · 50 = (X) Pcarbon dioxide = (Area/Thickness) · solubility/441/2 · 10
Crossing out what is equal on both sides, we are left with:
50/321/2 = (X) · 10/441/2
and, X = 5 · 441/2/321/2
Example Question #1 : Continuity Equation
A liquid flows through a pipe with a diameter of 10cm at a velocity of 9cm/s. If the diameter of the pipe then decreases to 6cm, what is the new velocity of the liquid?
25cm/s
18cm/s
12cm/s
15cm/s
21cm/s
25cm/s
Rate of flow, A * v, must remain constant. Use the continuity equation, .
Solving the initial cross-sectional area yields: . The initial radius is 5cm.
Then find the final area of the pipe: . The final radius is 3cm.
Using these values in the continuity equation allows us to solve the final velocity.
Example Question #81 : Fluids And Gases
If blood flows through the aorta with velocity, , with what velocity would blood flow through the capillaries in the body?
Just like the volume flow rate equation for fluids, the flow rate of blood through the body is equal to area times velocity.
The flow rate is a constant, so depending on the area that the blood is travelling through, the velocity is constantly changing; therefore the volume flow rate though the aorta is equal to the volume flow rate in the capillaries.
Because we can determine the area of the aorta and area of the capillaries, knowing the velocity through the aorta can give the velocity through the capillaries.
Example Question #1 : Continuity Equation
Which will produce the greatest increase in flow velocity through a tube?
Doubling the tube area
Dividing the tube area by three
Doubling the tube radius
Halving the tube radius
Doubling the viscosity of the liquid
Halving the tube radius
The equation for volumetric flow rate is , where is the cross-sectional area of the tube and is the flow velocity. We can re-write this equation to solve for the velocity and include the tube radius.
Halving the radius will reduce the tube area by a factor of four.
Volumetric flow rate is constant, thus, any reduction in area will cause a corresponding increase in velocity.
Halving the radius will thus quadruple the velocity, resulting in the greatest increase of the given options.
Example Question #2 : Continuity Equation
A pipe with a diameter of 4 centimeters is attached to a garden hose with a nozzle. If the velocity of flow in the pipe is , what is the velocity of the flow at the nozzle when it is adjusted to have a diameter of 8 millimeters?
Flow rate in a pipe must be constant in order to create linear flow. This flow rate is given by the product of the cross-sectional area and the velocity of the fluid.
The cross-sectional areas of the pipe and nozzle can be found using their radii. Note that you were given dimensions in terms of diameter, so be sure to divide by 2 to get the radius.
Use these areas and the initial velocity to calculate the final velocity in the nozzle.