All AP Physics 1 Resources
Example Questions
Example Question #21 : Ohm's Law
You connect a circuit with a resistor and a voltage source. The resistor has a resistance of and the voltage source supplies . How many electrons will pass through this circuit in a period?
To calculate the amount of electrons flowing through this circuit we need to first calculate the current. Use Ohm’s law:
Solve for current:
The question gives us the voltage and resistance; therefore, the current flowing through this circuit is
Recall that current is the amount of electrons flowing through a circuit per unit time.
Solving for the charge of electrons gives us
Recall that an electron contains ; therefore, the number of electrons in this circuit is
This means that electrons are flowing through this circuit every five seconds.
Example Question #21 : Ohm's Law
A circuit consists of a single voltage source and a single resistor. When is fed through the circuit, a current of is measured through the resistor. What is the measured current if a voltage of is fed through the circuit?
Using ohm's law, the resistance is determined to be which is calculated to be . Ohm's law is used again to find the current at with the same resistance.
Example Question #21 : Circuits
For a given electrical circuit, if you double the current, the resistance __________?
remains the same
halves
doubles
quadruples
quarters
halves
Recall Ohm's Law:
where is the voltage, is the current, and is the resistance.
Since the two quantities we are interested in are on the same side of the equation, they are inversely proportional. Hence, if one increases, the other one decreases by the same ratio. Since the current is doubling, the resistance must halve for the circuit to be the same.
Example Question #24 : Ohm's Law
Consider the circuit diagram shown. In this circuit, the values of , , and are known, but the value of is variable.
Which of the following expressions would give a situation in which the voltmeter in the diagram would read zero?
To answer this question, we'll need to find an expression for the value of the variable resistor that would make the voltmeter read zero.
First, it's important to realize what situation would result in a reading of zero from the voltmeter. For there to be no reading, that means that there cannot be any voltage difference between the top row of resistors and the bottom row. For this to happen, the voltage drop for the resistors on the left of the voltmeter must be equal, and the same is true for the two resistors to the right of the voltmeter. In other words, both rows of resistors will experience the same voltage decrease as current flows through, thus the difference of voltage drop in the top and bottom row will be identical.
So let's consider the top and bottom resistors on the left side first. In the top left corner, the voltage of the first resistor will be from Ohm's law. Moreover, the voltage drop of the bottom left resistor will be . These two voltages will need to be equal to one another in order to have the voltmeter read zero.
Now let's take a look at the other resistors on the right. The voltage of the third resistor will be and the voltage of the variable resistor will be . Just as before, these two resistors will also need to be equal in voltage.
Now that we have the two expressions shown above, we can isolate the term for the variable resistance in terms of the other three resistors to find our answer.
Example Question #1 : Equivalent Resistance
Consider the following circuit:
What is the total equivalent resistance of the circuit?
First we need to condense R3 and R4. They are in series, so we can simply add them to get:
Now we can condense R2 and R34. They are in parallel, so we will use the following equation:
Therefore:
The equivalent circuit now looks like:
Since everything is in series, we can simply add everything up:
Example Question #2 : Equivalent Resistance
Consider the given circuit:
What is the current through the system if we attach a resistor from point A to B?
The new circuit has two resistors in parallel: R2 and the new one attached. To find the equivalent resistance of these two branches, we use the following expression:
In this new equivalent circuit everything is in series, so we can simply add up the resistances:
Now we can use Ohm's law to calculate the total current through the circuit:
Example Question #2 : Equivalent Resistance
Consider the given circuit:
How much resistance must be applied between points A and B for the circuit to have a total current of 3A?
We will be working backwards on this problem, using the current to find the resistance. We know the voltage and desired current, so we can calculate the total necessary resistance:
Then we can calculate the equivalent resistance of the two resistors that are in parallel (R2 and our unknown):
Now we can calculate what the resistance between point A and B:
Rearranging for the desired resistance:
Example Question #2 : Equivalent Resistance
Consider the circuit:
If the equivalent resistance of the circuit is and each resistor is the same, what is the value of each resistor?
None of these
We can use the equation for equivalent resistance of parallel resistors to solve this equation:
We know the equivalent resistance, and we know that the resistance of each of the four resistors is equal:
Example Question #3 : Equivalent Resistance
Consider the circuit:
If the power dissipated throughout the entire circuit is , what is the value of ?
Since we know the power loss and voltage of the circuit, we can calculate the equivalent resistance of the circuit using the following equations:
Substituting Ohm's law into the equation for power, we get:
Rearranging for resistance, we get:
This is the equivalent resistance of the entire circuit. Now we can calculate R4 using the expression for resistors in parallel:
Example Question #2 : Equivalent Resistance
Consider the circuit:
If the current flowing through the circuit is , what is the value of R1?
We can use Ohm's law to calculate the equivalent resistance of the circuit:
Now we can use the expression for combining parallel resistors to calculate R1:
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