First step for finding limits: evaluate the function at the limit.

which is an Indeterminate Form.

This got us nowhere. However, since we have an indeterminate form, we can use L'Hopital's Rule (take the derivative of the top and bottom and the limit's value won't change).

This is something we can evaluate:

The value of this limit is .

The equation given is a model of logistic growth. Note that one of the other common forms this equation might be given in is . What we want to know is what the population will be given unlimited time, or what  is.

Looking at the form of the derivative above, note that if we start with 14 bunnies, we get a positive derivative. This means that the population is increasing. As our function is continuous, the population will keep growing until the derivative hits 0. When does this occur?

In the above form, it should be more clear that the derivative is only 0 at  and . Thus, the population will keep growing, but never go above 350, because if it were to hit 350, the derivative would be 0 and growth would stop. (Alternatively, if the population were above 350, you can see the derivative would be negative and that the population would shrink back down to 350. Indeed, it wasn't necessary to tell you we started with 14 bunnies -- the limit will be the same for any positive starting value.)

Unlike vertical asymptotes, horizontal asymptotes of certain functions may be crossed. In these cases, and in the case of the given function, the horizontal asymptote may be crossed and even have defined values laying on it (e.g., f(0)=0 for the function provided). 

What is meaningful about the horizontal asymptote in this example is that it suggests the behavior of the function at large magnitudes. The denominator will increase much faster than the numerator. That is to say that the  will grow exponentially larger the  in the numerator such that, at large values (both positive and negative), the function will output y-values tending toward y=0.

Step 1: Rewrite the problem.

integral (x³+x^1/2) dx from 0 to 1 

Step 2: Integrate 

x⁴/4 + 2x^(2/3)/3 from 0 to 1

Step 3: Plug in bounds and solve. 

[1⁴/4 + 2(1)^(2/3)/3] – [0⁴/4 + 2(0)^(2/3)/3] = (1/4) + (2/3) = (3/12) + (8/12) = 11/12

Integral from 1 to 2 of (1/x³) dx

Integral from 1 to 2 of (x^-3) dx

Integrate the integral. 

 from 1 to 2 of (x^–2/-2)  

(2^–2/–2) – (1^–2/–2) = (–1/8) – (–1/2)=(3/8)

In order to evaluate the indefinite integral, ask yourself, "what expression do I differentiate to get 4".  Next, use the power rule and increase the power of  by 1. To start, we have , so in the answer we have .  Next add a constant that would be lost in the differentiation.  To check your work, differentiate your answer and see that it matches "4".

Use the inverse Power Rule to evaluate the integral.  We know that  for .  We see that this rule tells us to increase the power of  by 1 and multiply by .  Next always add your constant of integration that would be lost in the differentiation.  Take the derivative of your answer to check your work.

Use the inverse Power Rule to evaluate the integral.  We know that  for .  We see that this rule tells us to increase the power of  by 1 and multiply by .  Next always add your constant of integration that would be lost in the differentiation.  Take the derivative of your answer to check your work.

Use the inverse Power Rule to evaluate the integral.  Firstly, constants can be taken out of integrals, so we pull the 3 out front.  Next, according to the inverse power rule, we know that  for .  We see that this rule tells us to increase the power of  by 1 and multiply by . Next always add your constant of integration that would be lost in the differentiation.  Take the derivative of your answer to check your work.

Use the inverse Power Rule to evaluate the integral.  We know that  for .  We see that this rule tells us to increase the power of  by 1 and multiply by .  Next always add your constant of integration that would be lost in the differentiation.  Take the derivative of your answer to check your work.