All AP Calculus AB Resources
Example Questions
Example Question #53 : Functions, Graphs, And Limits
Evaluate the following indefinite integral.
For this problem, we must simply remember that the integral of is , just like how the derivative of is . Just keep in mind that we need that constant of integration that would have been lost during differentiation.
Example Question #54 : Functions, Graphs, And Limits
Evaluate the following indefinite integral.
First, we know that we can pull the constant out of the integral, and we then evaluate the integral according to this equation:
. From this, we acquire the answer above. As a note, we cannot forget the constant of integration which would be lost during the differentiation.
Example Question #55 : Functions, Graphs, And Limits
The answer is . The definition of the derivative of is . Remember to add the to undefined integrals.
Example Question #261 : Ap Calculus Ab
Evaluate the integral:
1
In order to find the antiderivative, add 1 to the exponent and divide by the exponent.
Example Question #262 : Ap Calculus Ab
Evaluate:
Example Question #58 : Functions, Graphs, And Limits
Evaluate:
You should first know that the derivative of .
Therefore, looking at the equation you can see that the antiderivative should involve something close to:
Now to figure out what value represents the square take the derivative of and set it equal to what the original integral contained.
Since the derivative of contains a 3 that the integral does not show, we know that the square is equal to . Thus, the answer is .
Example Question #59 : Functions, Graphs, And Limits
Evaluate:
The antiderivative of . The derivative of . However, since there is no 2 in the original integral, we must divide by 2. Therefore, the answer is
Example Question #263 : Ap Calculus Ab
Evaluate the integral:
When taking the antiderivative add one to the exponent and then divide by the exponent.
Example Question #264 : Ap Calculus Ab
Evaluate the integral:
Cannot be evaluated
The derivative of . Therefore, the antiderivative of is equal to itself.
Example Question #33 : Comparing Relative Magnitudes Of Functions And Their Rates Of Change
Evaluate:
Can't be determined from the information given.
and
Recall that is an odd function and is an even function.
Thus, since is an odd function, the integral of this function from to will be zero.