Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves. 

1st quartile: 

Median of 1st quartile: 

2nd quartile = Median:  

3rd quartile:

Median of 3rd quartile:  

To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows: 

Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves. 

1st quartile: 

Median of 1st quartile: 

2nd quartile = Median: 

3rd quartile: 

Median of 3rd quartile: 

To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows: 

Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves. 

1st quartile: 

Median of 1st quartile: 

2nd quartile= Median: 

3rd quartile: 

Median of 3rd quartile: 

To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines.

Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves. 

1st quartile: 

Median of 1st quartile: 

2nd quartile = Median: 

3rd quartile:

Median of 3rd quartile:  

To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows: 

Put the data in numerical order (from smallest to largest) if it isn't already. In order to find the median, divide the data into two halves. In order to divide the values into quartiles, find the median of the two halves. 

1st quartile: 

Median of 1st quartile: 

2nd quartile = Median: 

3rd quartile:

Median of 3rd quartile:  

To construct the Box and Whisker Plot we use the minimum and the maximum value in the data set as the ends of the whiskers. To construct the box, we plot a line at the median of the 1st quartile, the median of our total data set, and at the median of the 3rd quartile. Then we connect the tops and bottom of the lines. The result is as follows: 

The median value of the data set, 86, is represented by the dashed line inside the box.

The maximum and minimum of the data set, 100 and 75 (respectively), are found at the far ends of the 2 whiskers on either end.

The range of the data set is found by subtracting the minimum from the maximum; 100-75=25, so the range is 25.

The upper and lower quartiles are given by the two boundaries between the box and the whiskers: the lower quartile (1^st quartile) is the left boundary, 80 in the data set; the upper quartile (3rd quartile) is the right boundary, which is 92 in the data set.

All of the other choices are provided by the box and whisker plot, so the correct choice is "The box and whisker plot gives you all of these"

 students achieved scores between 200 and 600, and Carla outscored all of them. 

 students achieved scores between 200 and 700. However, Carla did not outscore all of them. 

Carla's score had to have been between 600 and 700, so of the five choices, 660 is the only possible one.

The dividing points of the intervals used to classify students on this graph occur at multiples of 100. No details are given for each interval beyond the number of students who scored in it, so, for example, within the interval 500-600, it is not made clear how many of the 40 students scored above or below 550. The answer is that insufficient information is provided.

The midrange is the mean of the highest and lowest scores.

Each "stem" in the left column represents the tens digits of the scores; each of the numbers in its row, or "leaf" represents the units digits. The lowest score is represented by the 4 "leaf" in the "3" row - that is, it is 34 - and the highest score is represented by the 8 "leaf" in the "9" row - that is, 98. The midrange is therefore

Solution

The height of each bar shows the number of employees who attained that particular level of education. So to find the total number of employees, we add the numbers shown by all the bars in the histogram.

The total number of employees is 200.