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Example Questions
Example Question #53 : Simplifying Expressions
Simplify .
When we multiply variables with exponents, we can break up the problem into two parts. The first is what happens to the numbers in from of the variable, and the other is what happens to the numbers that are exponents for the variable.
First, let's start with the numbers in front of the variable. To figure this out, we simply multiply the two numbers together, like normal:
Next, let's take a look at the exponents. To figure out the exponents, we would add the two numbers together (remember you can only do this if you're multiplying/dividing; you can't add two variables unless their exponents are the same):
Now we just put the answer for the number in front of the variable and the answer for the exponents back where we found them:
Example Question #1982 : Algebra Ii
Simplify .
It would be easier to first expand the function to see what we're working with:
Here we can see that the will simplify into , and that the two 's in the denominator will cancel with two of the 's in the numerator. That leaves us with:
When we collect the terms together we end up with:
Example Question #57 : Simplifying Expressions
Simplify the following expression:
None of the other answers
Since this is a cubed-root of terms that are multiplied together, it can be thought of as taking the cubed-root of each of the following terms -- or "how many groups of 3 are there"
: There is no cubed-root of 6, so it stays inside the root --
: there is 1 group of 3 in 4 with 1 left over. So one goes outside to represent the 1 group of 3, and the "left over" stays inside the root --
: there are 3 groups of 3 in 9 with none leftover. So, goes outside to represent the 3 groups of 3, and there is nothing left inside --
: there are 4 groups of 3 in 14 with 2 left over. So, goes outside to represent the 4 groups of 3, and the "left over" stays inside the root --
Combining like terms:
Example Question #54 : Simplifying Expressions
Use the distributive property to expand the expression.
Use the distributive property to simplify the expression. The distributive property states that to multiply a sum by a term, you first multiply each part of the sum by that term separately, and then add these terms together. It looks like this in practice:
This means we multiply -6x2 by both terms, and then add these together. Don't forget, the negative sign gets applied to each term within the sum.
Multiply the constant terms together, and the x's together to yield:
This expression is now simplified!
Example Question #1991 : Algebra Ii
Simplify the following expression:
Step 1: A power raised to a power can be simplified by multiplying the two powers.
Step 2: When a fraction is raised to a power, it applies to both the top and bottom. Again, you multiply the powers.
Step 3: When dividing exponents with the same base, you subtract the power of the bottom from the power of the top.
Example Question #1992 : Algebra Ii
Simplify the expression:
Simplify the first expression.
Rewrite the expression and combine like-terms.
The answer is:
Example Question #1993 : Algebra Ii
Simplify the expression:
Distribute the first term with the binomial.
Subtract the last term with this expression. Do not combine the terms as one unit. There are no like-terms, and the terms cannot simplified any further.
The answer is:
Example Question #151 : Basic Single Variable Algebra
Simplify the expression:
Multiply the first term with every term inside the parentheses.
Sum the terms.
Combine like-terms.
The answer is:
Example Question #61 : Simplifying Expressions
Simplify the following expression:
First, focus on the first term . By the rules for multiplying exponents,
.
Since , . Hence,
.
Now focus on the second term,. Since the exponent is negative, we must rewrite this expression as the reciprocal of the base to the positive power:
By the rules for multiplying exponents,
Since , . Hence,
.
Substituting these simplified terms into the original expression yields
.
Hence, is the correct answer.
Example Question #1994 : Algebra Ii
Simplify:
First, use the distributive property:
Now simplify by combining your like terms:
Therefore, your final answer is:
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