There are TWO ways:

Method $\displaystyle 1:$

$\displaystyle 4(x-12)=96$ Distribute the $\displaystyle 4$.

$\displaystyle 4x-48=96$ Add $\displaystyle 48$ on both sides.

$\displaystyle 4x=144$ Divide $\displaystyle 4$ on both sides.

$\displaystyle x=36$

Method $\displaystyle 2$:

$\displaystyle 4(x-12)=96$ Divide $\displaystyle 4$ on both sides.

$\displaystyle x-12=24$ Add $\displaystyle 12$ on both sides.

$\displaystyle x=36$

There are TWO ways:

Method $\displaystyle 1$: (not so preferred)

$\displaystyle \frac{2}{3}(x+3)=24$ Distribute $\displaystyle \frac{2}{3}$.

$\displaystyle \frac{2x}{3}+2=24$ Subtract $\displaystyle 2$ on both sides.

$\displaystyle \frac{2x}{3}=22$ Multiply $\displaystyle \frac{3}{2}$ on both sides.

$\displaystyle x=33$

Method $\displaystyle 2$: (preferred)

$\displaystyle \frac{2}{3}(x+3)=24$ Multiply $\displaystyle \frac{3}{2}$ on both sides.

$\displaystyle x+3=36$ Subtract $\displaystyle 3$ on both sides.

$\displaystyle x=33$

$\displaystyle \frac{2}{3}=\frac{x}{12}$ Cross-multiply.

$\displaystyle 3x=24$ Divide $\displaystyle 3$ on both sides.

$\displaystyle x=8$

$\displaystyle \frac{4}{x+12}=\frac{10}{85}$ Cross-multiply. Remember the $\displaystyle 10$ multiplies the whole expression.

$\displaystyle 10(x+12)=4*85$ Distribute.

$\displaystyle 10x+120=340$ Subtract $\displaystyle 120$ on both sides.

$\displaystyle 10x=220$ Divide $\displaystyle 10$ on both sides.

$\displaystyle x=22$

Solve $\displaystyle 2x+5=7$ by:

The objective is to solve the equation to find what $\displaystyle x$ is equal to, so we need to have $\displaystyle x=$ a value.

First subtract 5 from both sides , and we will get:

$\displaystyle 2x=2$

Divide both sides by 2 and the solution is:

$\displaystyle x=1$

The objective is to solve the equation to find what $\displaystyle x$ is equal to, so we need to have $\displaystyle x=$ a value.

$\displaystyle 4x+18=2x-4$

1. Subtract $\displaystyle 2x$ from both sides, and we will have:

$\displaystyle 2x+18=-4$

2. Subtract 18 from both sides, and we will have:

$\displaystyle 2x=-22$

3. Divide both sides of the equation by 2 and the solution is:

$\displaystyle x=-11$

To solve:

$\displaystyle 5x + 14 -2(x+4)=x+3(x+1)-(x-3)$

1. First clear the parentheses.

$\displaystyle 5x + 14 -2x-8=x+3x+3-x+3$

2. Add the variables.

$\displaystyle 3x+ 14-8=3x+3+3$

3. Add the integers.

$\displaystyle 3x+ 6=3x+6$

4. Subtract $\displaystyle 3x$ from each side.

$\displaystyle 6=6$

Which is always true, so x can be all real numbers.

To simplify this you need to isolate x by subtracting 64 from both sides then taking the square root to get:

$\displaystyle \small \sqrt{-100}$

you cannot take the square root of a negative number so you answer is no solution.

This is a simple two step problem in which you need to isolate "x" The first step is to subtract the 36 from both sides. Upon doing this you get:

$\displaystyle \small -12x=60$

The next step is to divide by -12 to get "x" by itself.

Your final answer is:

$\displaystyle \small x=-5$

$\displaystyle 3x - 2 = \frac{x}{4}$

We can start by multiplying both sides by the denominator $\displaystyle 4$

$\displaystyle 4\times (3x-2)=4\times \frac{x}{4}$

$\displaystyle 12x - 8 = x$

Isolate terms with $\displaystyle x$ on one side of the equation, 

$\displaystyle 12x -x = 8$

Collect terms and solve, 

$\displaystyle 11x = 8$

$\displaystyle x = \frac{8}{11}$