Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #55 : Solving Equations

Solve for :

$2 = \frac{ 2x - 4 }{ 3 }$

Possible Answers:

$\frac{ 1}{2}$

Correct answer:

Explanation:

In order to solve the equation, we have to isolate the variable. We do this by performing the same operation to either side of the equation.

$2 = \frac{ 2x - 4 }{ 3 }$

First multiply both sides by 3.

6 = 2x - 4 .

Next, add 4 to both sides.

10 = 2x

Finally, divide both sides by 2.

5 = x

Report an Error

Example Question #2382 : Algebra Ii

Solve for :

$\frac{ 20 }{ x - 7 } = 4$

Possible Answers:

$1.\overline{81}$

6.75

220

Correct answer:

Explanation:

Before we start with inverse opperations, we need x to be out of the denominator:

$\frac{ 20 }{x - 7 } = 4$

First multiply both sides by x- 7.

20 = 4(x-7)

Next, divide both sides by 4.

5 = x - 7

Finally, add 7 to both sides.

12 =x

Report an Error

Example Question #2383 : Algebra Ii

Solve the following equation for :

x^2-5x+6=0

Possible Answers:

x=2

x=-2 and x=-3

No real solutions

x=2 and x=3

Correct answer:

x=2 and x=3

Explanation:

Solve the following equation for x:

x^2-5x+6=0

Begin by factoring the given equation.

We want something of the following form:

$(x\pm a)(x\pm b)=0$

Where a and b multiply to get 6 and add to get .

A good place to start would be listing the multiples of 6:1,2,3,6

2 and 3 seem like a good place to start. Since we need negative 5 and positive 6, keeping 2 and 3 negative seem like a good bet.

(x-2)(x-3)=0

Because this equation is set equal to zero, we can use the zero product property rule to set each half of our factored equation equal to zero and then solve.

x-2=0

x=2

x-3=0

x=3

So we have 2 answers: x=2 and x=3

Report an Error

Example Question #2384 : Algebra Ii

Solve this equation: $4x+.25=8x-\frac{31}{4}$

Possible Answers:

x=.75

x=.25

x=1

x=2

x=4

Correct answer:

x=2

Explanation:

$4x+.25=8x-\frac{31}{4}$

Combine terms by subtracting:

$.25=4x-\frac{31}{4}$

Convert non terms to decimals or to fractions:

$\frac{1}{4}=4x-\frac{31}{4}$

We choose to convert to a fraction because it is easier.

Combine fractions by adding:

$\frac{1}{4}+\frac{31}{4}=4x$

$\frac{32}{4}=4x$

Simplify and solve for :

8=4x

x=2

Report an Error

Example Question #2385 : Algebra Ii

Solve: $e^{x+2} = e^{-x}$

Possible Answers:

ln(-1)

2ln(2)

$\frac{1}{e}$

Correct answer:

Explanation:

Since the bases are alike in this problem, taking the log of both sides will eliminate the base terms.

Take the natural log of both sides.

$ln(e^{x+2}) = ln(e^{-x})$

The equation becomes:

x+2=-x

Solve for .

2x+2=0

2x=-2

x=-1

The answer is:

Report an Error

Example Question #2386 : Algebra Ii

Solve the equation for

5(-2x-4)-3(4x+5)=97

Possible Answers:

132

Correct answer:

Explanation:

5(-2x-4)-3(4x+5)=97

-10x-20-12x-15=97

-22x-35=97

-22x=132

Divide both sides by

x = -6

Report an Error

Example Question #9 : Linear Systems With Two Variables

Solve the system of equations.

x-3y=-22

4x+2y=-4

Possible Answers:

(-4,-6)

(-4,0)

(-4,6)

(4,-6)

Correct answer:

(-4,6)

Explanation:

Use elimination, multiply the top equation by -4 so that you can eliminate the X's.

x-3y=-22

4x+2y=-4

__________________

-4x+12y=88

4x+2y=-4

Combine these two equations, and then you have;

14y=84

y=6

Plug in y into one of the original equations and solve for x.

x-3(6)=-22

x-18=-22

x=-4

Your solution is (-4,6) .

Report an Error

Example Question #542 : Basic Single Variable Algebra

Find a solution to the following equation:

45-13x=84

Possible Answers:

x=-3

x=-6

x=3

x=13

Correct answer:

x=-3

Explanation:

Find a solution to the following equation:

45-13x=84

We can solve for x using basic algebra.

Begin by subtracting 45:

-13x=84-45

-13x=39

Now, divide by -13 to find the final answer:

$x=39\div-13=-3$

Making our answer:

x=-3

Report an Error

Example Question #62 : Solving Equations

$\frac{2}{3}x+\frac{2}{3}=-\frac{2}{3}$

Possible Answers:

$x=\frac{3}{2}$

$x=-\frac{3}{2}$

The answer is not present

x=2

x=-2

Correct answer:

x=-2

Explanation:

$\frac{2}{3}x+\frac{2}{3}=-\frac{2}{3}$

Isolate the term with x:

$\frac{2}{3}x=-\frac{2}{3}-\frac{2}{3}$

Simplify:

$\frac{2}{3}x=-\frac{4}{3}$

Isolate x entirely:

$\frac{3}{2}*\frac{2}{3}x=-\frac{4}{3}*\frac{3}{2}$

$\mathbf{x=-2}$

Report an Error

Example Question #2389 : Algebra Ii

$x=\sqrt{8+2x}$

Possible Answers:

Cannot be solved

$x=2\hspace{1mm}and\hspace{1mm}x=-4$

$x=2\hspace{1mm}and\hspace{1mm}x=4$

$x=-2\hspace{1mm}and\hspace{1mm}x=4$

$x=-2\hspace{1mm}and\hspace{1mm}x=-4$

Correct answer:

$x=-2\hspace{1mm}and\hspace{1mm}x=4$

Explanation:

$x=\sqrt{8+2x}$

Square both sides to remove the radical:

x^2=8+2x

Move all terms to the left side and set equal to 0:

x^2-2x-8=0

Factor the quadratic and set the factors equal to 0:

(x+2)(x-4)=0

Solve the factors:

$(x+2)=0\rightarrow \mathbf{x=-2}$

$(x-4)=0\rightarrow \mathbf{x=4}$

Report an Error

View Algebra 2 Tutors

Dana
Certified Tutor

Northern Arizona University, Bachelor in Arts, Law Enforcement Intelligence Analysis. Grand Canyon University, Master of Scie...

View Algebra 2 Tutors

Mariam
Certified Tutor

Yarmouk University, Bachelor of Science, Mathematics. Touro College, Master of Science, Teacher Education, Multiple Levels.

View Algebra 2 Tutors

Thavisha
Certified Tutor

Minnesota State University-Mankato, Bachelor of Science, Mathematics.

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in San Diego, Reading Tutors in Boston, GRE Tutors in San Diego, Reading Tutors in Seattle, Biology Tutors in Philadelphia, GRE Tutors in Denver, MCAT Tutors in New York City, SSAT Tutors in Phoenix, Calculus Tutors in Washington DC, SSAT Tutors in Denver

Popular Courses & Classes

ACT Courses & Classes in San Diego, GMAT Courses & Classes in Washington DC, GRE Courses & Classes in Boston, Spanish Courses & Classes in Boston, SSAT Courses & Classes in Miami, GMAT Courses & Classes in San Diego, ISEE Courses & Classes in New York City, SAT Courses & Classes in Chicago, ISEE Courses & Classes in Denver, SAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

SSAT Test Prep in Dallas Fort Worth, ACT Test Prep in San Francisco-Bay Area, GRE Test Prep in Denver, ISEE Test Prep in Houston, LSAT Test Prep in San Francisco-Bay Area, SAT Test Prep in Atlanta, MCAT Test Prep in Phoenix, MCAT Test Prep in Atlanta, ISEE Test Prep in New York City, SAT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #55 : Solving Equations

Example Question #2382 : Algebra Ii

Example Question #2383 : Algebra Ii

Example Question #2384 : Algebra Ii

Example Question #2385 : Algebra Ii

Example Question #2386 : Algebra Ii

Example Question #9 : Linear Systems With Two Variables

Example Question #542 : Basic Single Variable Algebra

Example Question #62 : Solving Equations

Example Question #2389 : Algebra Ii

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: