We begin by using inverse operations, exactly as if we were solving an equation. In this case, we must isolate the variable by subtracting  from both sides. This leaves us with . Finally, we again use inverse operations--in this case dividing by --to end up with a final inequality of . Note that we do not flip the inequality because we are not dividing by a negative number.

The compund inequality requires a graph in which the values of  are greater than 5 AND less than or equal to 9. That is,  is all the real numbers between 5, not included, and 9, included. Since 5 is not included, there is no "or equal to" sign on the greater than inequality, we place and open circle above 5. Since 9 is included, we place a closed circle above 9. 

First, graph the line of the equation. It is written in slope-intercept from; therefore the slope is  and the y-intercept is .

When an inequality is written as less than or greater than, a dashed line is used. When an inequality is written as less than or equal to, or greater than or equal to, a solid line is used. Therefore, a dashed line should be used, eliminating two of the answer choices.

Next, use a test point to determine which regions should be shaded. A test point can be any point not on the line; the origin is generally a good choice. If the origin, , is subsituted into the question and the statement is TRUE, the graph should be shaded on the side of the line that contains the origin. If the statement is false, the other side should be shaded.

This statement is TRUE; the section containing the origin should be shaded.

For a compound inequality, we solve each inequality individually. Thus, for the first inequality, , we obtain the solution  and for the second inequality, , we obtain the solution . In interval notation, the solutions are  and , respectively. Because our compound inequality has the word "or", this means we union the two solutions to obatin . 

First, we find the equation of the boundary line using the two intercepts. The slope is 

.

The -intercept is .

The slope-intercept form of the equation is therefore

.

Put this in standard form:

The inequality is therefore either  or .  To determine which, test a point that falls in the shaded region. The easiest is :

This inequality holds, so the answer is .

A horizontal line has equation  for some value of ; since the line goes through a point with -coordinate 3, the line is . Also, since the line is solid and the region above this line is shaded in, the corresponding inequality is .

A vertical line has equation  for some value of ; since the line goes through a point with -coordinate 4, the line is . Also, since the line is solid and the region right of this line is shaded in, the corresponding inequality is .

Since only the region belonging to both sets is shaded - that is, their intersection is shaded - the statements are connected with "and". The correct choice is .

First, we determine the equation of the boundary line. This line includes points  and  , so the slope can be calculated as follows:

Since we also know the -intercept is , we can substitute  in the slope-intercept form to obtain the equation of the boundary line:

The boundary is included, as is indicated by the line being solid, so the equality symbol is replaced by either  or . To find out which one, we can test a point in the solution set - for ease, we will choose :

 _____ 

  _____ 

  _____ 

0 is less than 3 so the correct symbol is . 

The inequality is .

First, we determine the equation of the boundary line. This line includes points  and  , so the slope can be calculated as follows:

Since we also know the -intercept is , we can substitute  in the slope-intercept form to obtain equation of the boundary:

The boundary is included, as is indicated by the line being solid, so the equality symbol is replaced by either  or . To find out which one, we can test a point in the solution set - for ease, we will choose :

 _____   

  _____ 

  _____ 

0 is less than 7 so the correct symbol is . 

The correct choice is .

First, we determine the equation of the boundary line. This line includes points  and  , so the slope can be calculated as follows:

Since we also know the -intercept is , we can substitute  in the slope-intercept form to obtain equation of the boundary:

The boundary is excluded, as is indicated by the line being dashed, so the equality symbol is replaced by either  or . To find out which one, we can test a point in the solution set - we will choose :

 _____ 

  _____ 

 _____ 

 _____ 

1 is greater than 0 so the correct symbol is 

The inequality is 

Given the above graph, we can initially deduce that , , and  are not the correct answer; the dashed line in the graph indicates that no point on the line  is a solution to the inequality. Thus, we're left with  and .

We can use a test point to determine which of the remaining inequalities is the correct answer. The test point can be any point that is not on the line, so let's select  in this case. Plugging  into  yields . Since this is true, we know that every point on the same side of the line as  will yield a true result, and that our graph represents .