All Algebra 1 Resources
Example Questions
Example Question #161 : Systems Of Equations
Solve for :
First, combine like terms to get .
Then, subtract 3 and from both sides to get .
Then, divide both sides by 2 to get a solution of .
Example Question #42 : Equations / Solution Sets
Solve this system of equations:
To solve this system of equations, the elimination method can be used (the terms cross out).
Once you eliminate the , you have .
Then isolate for , and you get .
Plug into the first equation to solve for .
Example Question #162 : Systems Of Equations
Solve the following system of equations:
This system has no solution.
This system has an infinite number of solutions.
This system has an infinite number of solutions.
Rearrange the second equation:
This is just a multiple of the first equation (by a factor of 3). Therefore, the two equations are dependent on each are and are going to have an infinite number of solutions.
Example Question #1 : Solve Systems Of Two Linear Equations: Ccss.Math.Content.8.Ee.C.8b
Solve the set of equations:
Solve the first equation for :
Substitute into the second equation:
Multiply the entire equation by 2 to eliminate the fraction:
Using the value of , solve for :
Therefore, the solution is
Example Question #2 : Systems Of Equations
Find the solution:
To solve this system of equations, we must first eliminate one of the variables. We will begin by eliminating the variables by finding the least common multiple of the variable's coefficients. The least common multiple of 3 and 2 is 6, so we will multiply each equation in the system by the corresponding number, like
.
By using the distributive property, we will end up with
Now, add down each column so that you have
Then you solve for and determine that .
But you're not done yet! To find , you have to plug your answer for back into one of the original equations:
Solve, and you will find that .
Example Question #2 : Solve Systems Of Two Linear Equations: Ccss.Math.Content.8.Ee.C.8b
Solve the following system of equations:
Set the two equations equal to one another:
2x - 2 = 3x + 6
Solve for x:
x = -8
Plug this value of x into either equation to solve for y. We'll use the top equation, but either will work.
y = 2 * (-8) - 2
y = -18
Example Question #163 : Systems Of Equations
Solve the following system of equations:
Solve the second equation for y:
x - 2y = 4
-2y = 4 - x
y = -2 + x/2
Plug this into the first equation:
3x + 2(-2 + x/2) = 8
Solve for x:
3x - 4 + x = 8
4x = 12
x = 3
Plug this into the second equation to get a value for y:
3 - 2y = 4
2y = -1
y = -0.5
Example Question #164 : Systems Of Equations
Solve the following system of equation
Cannot be solved
Start with the equation with the fewest variables, .
Solve for by dividing both sides of the equaion by 6:
Plug this value into the second equation to solve for :
Subtract 10 from both sides:
Divide by 9:
Plug these and values into the first equation to find :
Combine like terms:
Subtract 2:
Divide by -4:
Therefore the final solution is .
Example Question #165 : Systems Of Equations
Two integers, and , sum to 16, but when is doubled, they sum to 34. Find and .
No solution
and add up to 16:
When is doubled to , they sum to 34:
We have two equations and two unknowns, so we can find a solution to this system.
Solve for in the first equation:
Plug this into the second equation:
Solve for :
Use this value to find . We already have a very simple equation for , .
Therefore the answer is .
Example Question #261 : Equations / Inequalities
Solve for .
For the second equation, solve for in terms of .
Plug this value of y into the first equation.
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