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SSAT Middle Level Math : How to divide variables

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Example Questions

Example Question #1 : How To Divide Variables

Solve for the variable:

4x+5=21 $\displaystyle 4x+5=21$

Possible Answers:

x=26 $\displaystyle x=26$

There is not enough information to answer this question.

x=5 $\displaystyle x=5$

x=21 $\displaystyle x=21$

x=4 $\displaystyle x=4$

Correct answer:

x=4 $\displaystyle x=4$

Explanation:

In order to answer this question, you must isolate $\displaystyle x$ on one side of the equation.

4x+5=21 $\displaystyle 4x+5=21$ (Subtract $\displaystyle 5$ from both sides.)

4x=16 $\displaystyle 4x=16$

$\frac{4x}{4}=\frac{16}{4}$ $\displaystyle \frac{4x}{4}=\frac{16}{4}$

x=4 $\displaystyle x=4$

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Example Question #112 : Variables

If y=12 $\displaystyle y=12$ and z=3 $\displaystyle z=3$, then $\frac{y}{z}$ $\displaystyle \frac{y}{z}$ is equal to:

Possible Answers:

$\displaystyle 6$

$\frac{1}{4}$ $\displaystyle \frac{1}{4}$

$\frac{1}{3}$ $\displaystyle \frac{1}{3}$

$\displaystyle 3$

$\displaystyle 4$

Correct answer:

$\displaystyle 4$

Explanation:

If y=12 $\displaystyle y=12$ and z=3 $\displaystyle z=3$, then when plugging the variables into the fractional form of $\frac{y}{z}$ $\displaystyle \frac{y}{z}$, the result is $\frac{12}{3}$ $\displaystyle \frac{12}{3}$, which is equal to 4, which is therefore the correct answer.

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Example Question #3 : How To Divide Variables

Solve for the variable:

3x+6=15 $\displaystyle 3x+6=15$

Possible Answers:

x=1 $\displaystyle x=1$

x=2 $\displaystyle x=2$

x=4 $\displaystyle x=4$

x=6 $\displaystyle x=6$

x=3 $\displaystyle x=3$

Correct answer:

x=3 $\displaystyle x=3$

Explanation:

In order to answer this question, you must isolate $\displaystyle x$ on one side of the equation.

3x+6=15 $\displaystyle 3x+6=15$ (Subtract $\displaystyle 6$ from both sides.)

3x = 9 $\displaystyle 3x = 9$

$\frac{3x}{3}=\frac{9}{3}$ $\displaystyle \frac{3x}{3}=\frac{9}{3}$

x=3 $\displaystyle x=3$

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Example Question #113 : Variables

If y=30 $\displaystyle y=30$ and x=5 $\displaystyle x=5$, then $\frac{y}{x}$ $\displaystyle \frac{y}{x}$ is equal to:

Possible Answers:

$\displaystyle 6$

$\displaystyle 5$

$\displaystyle 4$

30.5 $\displaystyle 30.5$

$\frac{6}{5}$ $\displaystyle \frac{6}{5}$

Correct answer:

$\displaystyle 6$

Explanation:

If y=30 $\displaystyle y=30$ and x=5 $\displaystyle x=5$, then when plugging the variables into the fractional form of:

$\frac{y}{x}=\frac{30}5$ $\displaystyle \frac{y}{x}=\frac{30}5$

$\frac{30}{5}=\frac{6}{1}=6$ $\displaystyle \frac{30}{5}=\frac{6}{1}=6$

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Example Question #2 : How To Divide Variables

Simpify the expression.

$\frac{24abcdefg}{24abcdefgh}$ $\displaystyle \frac{24abcdefg}{24abcdefgh}$

Possible Answers:

$\frac{abcdefg}{abcdefgh}$ $\displaystyle \frac{abcdefg}{abcdefgh}$

$\frac{abcdefg}{h}$ $\displaystyle \frac{abcdefg}{h}$

$\frac{1}{h}$ $\displaystyle \frac{1}{h}$

$\frac{24}{h}$ $\displaystyle \frac{24}{h}$

$\frac{1}{abcdefgh}$ $\displaystyle \frac{1}{abcdefgh}$

Correct answer:

$\frac{1}{h}$ $\displaystyle \frac{1}{h}$

Explanation:

To solve this problem you can cancel out like terms in the numerator and denominator. For example,

$\frac{24}{24}=1$ $\displaystyle \frac{24}{24}=1$

$\frac{a}{a}=1$ $\displaystyle \frac{a}{a}=1$

So,

$\frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}=\frac{1}{h}$ $\displaystyle \frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}=\frac{1}{h}$

All the other terms cancel each other out because they are equal to one.

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SSAT Middle Level Math : How to divide variables

Study concepts, example questions & explanations for SSAT Middle Level Math

All SSAT Middle Level Math Resources

Example Questions

Example Question #1 : How To Divide Variables

Example Question #112 : Variables

Example Question #3 : How To Divide Variables

Example Question #113 : Variables

Example Question #2 : How To Divide Variables

All SSAT Middle Level Math Resources

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