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SSAT Elementary Level Math : Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #151 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

$\frac{\begin{array}[b]{r}6\\ -\ 2\end{array}}{ \ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 2\end{array}}{ \ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 6$

$\displaystyle 2$

$\displaystyle 3$

$\displaystyle 5$

$\displaystyle 4$

Correct answer:

$\displaystyle 4$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 6$ and count back $\displaystyle 2$.

6,5,4 $\displaystyle 6,5,4$

$\frac{\begin{array}[b]{r}6\\ -\ 2\end{array}}{ \ \ \ \space 4}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 2\end{array}}{ \ \ \ \space 4}$

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Example Question #281 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{ \ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{ \ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 1$

$\displaystyle 3$

$\displaystyle 5$

$\displaystyle 4$

Correct answer:

$\displaystyle 1$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 7$ and count back $\displaystyle 6$.

$\displaystyle 7, 6, 5, 4, 3, 2, 1$

$\frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{ \ \ \ \space 1}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{ \ \ \ \space 1}$

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Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

$\frac{\begin{array}[b]{r}6\\ -\ 1\end{array}}{ \ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 1\end{array}}{ \ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 4$

$\displaystyle 1$

$\displaystyle 5$

$\displaystyle 3$

Correct answer:

$\displaystyle 5$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 6$ and count back $\displaystyle 1$.

6,5 $\displaystyle 6,5$

$\frac{\begin{array}[b]{r}6\\ -\ 1\end{array}}{ \ \ \ \space 5}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 1\end{array}}{ \ \ \ \space 5}$

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Example Question #181 : Adding And Subtracting Within 20

$\frac{\begin{array}[b]{r}10\\ -\ 7\end{array}}{ \ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}10\\ -\ 7\end{array}}{ \ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 3$

$\displaystyle 2$

$\displaystyle 4$

$\displaystyle 5$

$\displaystyle 6$

Correct answer:

$\displaystyle 3$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 10$ and count back $\displaystyle 7$.

$\displaystyle 10, 9, 8, 7, 6, 5, 4, 3$

$\frac{\begin{array}[b]{r}10\\ -\ 7\end{array}}{ \ \ \ \space 3}$ $\displaystyle \frac{\begin{array}[b]{r}10\\ -\ 7\end{array}}{ \ \ \ \space 3}$

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Example Question #162 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

$\frac{\begin{array}[b]{r}12\\ -\ 9\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}12\\ -\ 9\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 4$

$\displaystyle 0$

$\displaystyle 1$

$\displaystyle 3$

Correct answer:

$\displaystyle 3$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 12$ and count back $\displaystyle 9$.

$\displaystyle 12, 11, 10, 9, 8, 7, 6, 5, 4, 3$

$\frac{\begin{array}[b]{r}12\\ -\ 9\end{array}}{ \ \ \ \space 3}$ $\displaystyle \frac{\begin{array}[b]{r}12\\ -\ 9\end{array}}{ \ \ \ \space 3}$

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Example Question #281 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}13\\ -\ 4\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}13\\ -\ 4\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 13$

$\displaystyle 11$

$\displaystyle 9$

$\displaystyle 10$

$\displaystyle 12$

Correct answer:

$\displaystyle 9$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 13$ and count back $\displaystyle 4$.

$\displaystyle 13, 12, 11, 10, 9$

$\frac{\begin{array}[b]{r}13\\ -\ 4\end{array}}{ \ \ \ \space 9}$ $\displaystyle \frac{\begin{array}[b]{r}13\\ -\ 4\end{array}}{ \ \ \ \space 9}$

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Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

$\frac{\begin{array}[b]{r}14\\ -\ 2\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}14\\ -\ 2\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 12$

$\displaystyle 10$

$\displaystyle 14$

$\displaystyle 11$

$\displaystyle 13$

Correct answer:

$\displaystyle 12$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 14$ and count back $\displaystyle 2$.

$\displaystyle 14,13,12$

$\frac{\begin{array}[b]{r}14\\ -\ 2\end{array}}{ \ \ \space 12}$ $\displaystyle \frac{\begin{array}[b]{r}14\\ -\ 2\end{array}}{ \ \ \space 12}$

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Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

$\frac{\begin{array}[b]{r}15\\ -\ 8\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}15\\ -\ 8\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 7$

$\displaystyle 10$

$\displaystyle 8$

$\displaystyle 9$

$\displaystyle 6$

Correct answer:

$\displaystyle 7$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 15$ and count back $\displaystyle 8$.

$\displaystyle 15, 14, 13, 12, 11, 10, 9, 8, 7$

$\frac{\begin{array}[b]{r}15\\ -\ 8\end{array}}{ \ \ \ \space 7}$ $\displaystyle \frac{\begin{array}[b]{r}15\\ -\ 8\end{array}}{ \ \ \ \space 7}$

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Example Question #281 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}16\\ -\ 12\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}16\\ -\ 12\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 3$

$\displaystyle 2$

$\displaystyle 1$

$\displaystyle 5$

$\displaystyle 4$

Correct answer:

$\displaystyle 4$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 16$ and count back $\displaystyle 12$.

$\displaystyle 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4$

$\frac{\begin{array}[b]{r}16\\ -\ 12\end{array}}{ \ \ \ \ \ \space 4}$ $\displaystyle \frac{\begin{array}[b]{r}16\\ -\ 12\end{array}}{ \ \ \ \ \ \space 4}$

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Example Question #191 : Adding And Subtracting Within 20

$\frac{\begin{array}[b]{r}17\\ -\ 10\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}17\\ -\ 10\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 11$

$\displaystyle 8$

$\displaystyle 10$

$\displaystyle 9$

$\displaystyle 7$

Correct answer:

$\displaystyle 7$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 17$ and count back $\displaystyle 10$.

$\displaystyle 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7$

$\frac{\begin{array}[b]{r}17\\ -\ 10\end{array}}{ \ \ \ \ \ \space 7}$ $\displaystyle \frac{\begin{array}[b]{r}17\\ -\ 10\end{array}}{ \ \ \ \ \ \space 7}$

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #151 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

Example Question #281 : Operations & Algebraic Thinking

Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

Example Question #181 : Adding And Subtracting Within 20

Example Question #162 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

Example Question #281 : Operations & Algebraic Thinking

Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

Example Question #161 : Adding And Subtracting Within 20: Ccss.Math.Content.1.Oa.C.6

Example Question #281 : Operations & Algebraic Thinking

Example Question #191 : Adding And Subtracting Within 20

All SSAT Elementary Level Math Resources

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