Volume of a pyramid is

Thus:

Area of the base is .

Therefore, each side is .

If the height, which is twice the length of the base edges, measures 6 meters, then each base edge must measure 3 meters.  

Since the base is a square, the area of the base is 3 x 3 = 9.  

Therefore the volume of the right pyramid is V = (1/3) x area of the base x height = 1/3(9)(6) = 18.

The formula for the area of a pyramid is . In this case, the length is , the width is , and the height is . 

 and . 

To find the volume of a pyramid, you need to use the equation below:

To find the height (shown by the yellow line), we can draw a right triangle using the yellow line, blue line and side b (5 inches). Because the hypotenuse is 5 inches, using the common Pythagorean 3-4-5  triple. The blue line is 3 inches and the yellow line (height) is 4 inches. Also, to find side a, we can use the blue line (3 inches) and half of the red line (3 inches)  and the Pythagorean Theorum.

Because the base is a square, the area of the base is equal to the square of side a:

Now we plug in these values to find the volume:

The volume  of a rectangular pyramid with height , base width , and base length  is given by 

.

For this pyramid, , , and  To calculate its volume, substitute the values for , , and  into the formula:

Therefore, the volume of the given rectangular pyramid is 

First we write out the equation we are given. H + (2L +2W) = 360.  H = 40 and L = 23

40 + (2(23) + 2W) = 360

40 + (46 + 2W) = 360

46 + 2W = 320

2W = 274

W = 137

Method 1:

Trial and error to find a combination of factors of 80 that differ by the same amount will eventually yield 2, 5, 8.  The average is 5.

Method 2:

Three terms of an arithmetic sequence can be written as x, x+d, and x+2d. Multiply these together using the distributive property to find the volume and the following equation results:

x³ + 3dx² + 2d²x - 80 = 0

Find an integer value of x that creates an integer solution for d.  Try x=1 and we see the equation 1 + 3d + 2d² - 80 = 0 or 2d² + 3d -79 = 0.  The determinant of this quadratic is 641, which is not a perfect square.  Therefore, d is not an integer when x=1.

Try x=2 and we see the equation 8 + 12d + 4d² - 80 = 0 or d² + 3d - 18 = 0.  This is easily factored to (d+6)(d-3)=0 so d=-6 or d=3.  Since a negative value of d will result in negative dimensions of the prism, d must equal 3.  Therefore, when substituting x=2 and d=3, the dimensions x, x+d, and x+2d become 2, 5, and 8.  The average is 5.

Based on our prompt, we can say that the prism has dimensions that can be represented as:

Dim1: x

Dim2: 2 * Dim1 = 2x

Dim3: (1/4) * Dim2 = (1/4) * 2x = (1/2) * x

More directly stated, therefore, our dimensions are: x, 2x, and 0.5x. Therefore, the volume is x * 2x * 0.5x = 64, which simplifies to x³ = 64. Solving for x, we find x = 4. Therefore, our dimensions are:

x = 4

2x = 8

0.5x = 2

Or: 2 x 4 x 8

Based on our prompt, we can say that the prism has dimensions that can be represented as:

Dim1: x

Dim2: 3 * Dim1 = 3x

Dim3: 5 * Dim1 = 5x

More directly stated, therefore, our dimensions are: x, 3x, and 5x. Therefore, the volume is x * 3x * 5x = 120, which simplifies to 15x³ = 120 or x³ = 8. Solving for x, we find x = 2. Therefore, our dimensions are:

x = 2

3x = 6

5x = 10

Or: 2 x 6 x 10

Call , , and  the length, height, and width of the crate. 

The length of the crate is two-thirds its width, so

The length of the crate is three-fourths its height, so 

The dimensions of the crate in terms of  are , , and . The surface area is found using the formula:

Substitute:

Solve for :

 meters. 

Since one meter comprises 100 centimeters, multiply by 100 to convert to centimeters:

This rounds to 111 centimeters.