SAT Math : Solid Geometry

Study concepts, example questions & explanations for SAT Math

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Example Questions

Example Question #21 : Solid Geometry

Find the surface area of a cube given side length of 3.

Possible Answers:

Correct answer:

Explanation:

To find the surface area of a cube means to find the area around the entire object. In the case of a cube, we will need to find that area of all the sides and the top and bottom. Since a cube has equal side lengths, the area of each side and the area of the top and bottom will all be the same.

Recall that the area for a side of a cube is:

From here there are two approaches one can take.

Approach one:

Add all the areas together.

Approach two:

Use the formula for the surface area of a cube,

In this particular case we are given the side length is 3.

Thus we can find the surface area to be,

by approach one,

and by appraoch two,

.

Example Question #11 : How To Find The Surface Area Of A Cube

Find the volume of a cube given side length of 3.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the surface area of a cube.

If you do not remember the formula for the test, it is important to draw a picture or to visually conceptualize it. Remember, when finding area of a square or rectangle, you simply multiply the two side lengths. So for a cube in 3 dimensions, you simply have to multiply those three together.

However, a cube is a special case where all three lengths are the same. Thus,

Example Question #22 : Cubes

A cube has given volume . What is its surface area?

Possible Answers:

Correct answer:

Explanation:

First, we need the side length of the cube. Given that , where is a side length, we can solve for  and set  simply by taking the cube root of both sides.

Then we need to remember or realize that the surface area of a cube is because there will be six identical square faces. Plugging in , we get as our answer.

Example Question #21 : Solid Geometry

Find the surface area of a cube with side length 8.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the surface area of a cube.

If this is not a formula you have committed to memory, remember that a cube has 6 faces with equal area. So, start by calculating the surface area of one side (64) and add it 6 times. Thus,

Example Question #21 : Cubes

You own a Rubik's cube with a volume of . What is the surface area of the cube?

Possible Answers:

Not enough information to solve

Correct answer:

Explanation:

You own a Rubik's cube with a volume of . What is the surface area of the cube?

To solve for edge length, think of the volume of a cube formula:

Now, we have the volume, so just rearrange it to solve for side length:

Next, recall the surface area of a cube formula:

Plug in and simplify to get:

Example Question #596 : Problem Solving

A room has dimensions of 23ft by 17ft by 10ft. The last dimension is the height of the room. It has one door that is 2.5ft by 8ft and one window, 3ft by 6ft. There is no trim to the floor, wall, doors, or windows. If one can of paint covers 57 ft2 of surface area. How many cans of paint must be bought to paint the walls of the room.

Possible Answers:

18

11

14

15

13

Correct answer:

14

Explanation:

If broken down into parts, this is an easy problem. It is first necessary to isolate the dimensions of the walls. If the room is 10ft high, we know 23 x 17 designates the area of the floor and ceiling. Based on this, we know that the room has the following dimensions for the walls: 23 x 10 and 17 x 10. Since there are two of each, we can calculate the total area of walls - ignoring doors and windows - by doubling the sum of these two areas:

2 * (23 * 10 + 17 * 10) = 2 * (230 + 170) = 2 * 400 = 800 ft2

Now, we merely need to calculate the area "taken out" of the walls:

For the door: 2.5 * 8 = 20 ft2 

For the windows: 3 * 6 = 18 ft2

The total wall space is therefore: 800 – 20 – 18 = 762 ft2

Now, if one can of paint covers 57 ft2, we calculate the number of cans necessary by dividing the total exposed area by 57: 762/57 = (approx.) 13.37.

Since we cannot buy partial cans, we must purchase 14 cans.

Example Question #23 : Solid Geometry

A cubic box has sides of length x. Another cubic box has sides of length 4x. How many of the boxes with length x could fit in one of the larger boxes with side length 4x?

Possible Answers:

4

40

80

16

64

Correct answer:

64

Explanation:

The volume of a cubic box is given by (side length)3. Thus, the volume of the larger box is (4x)3 = 64x3, while the volume of the smaller box is x3. Divide the volume of the larger box by that of the smaller box, (64x3)/(x3) = 64.

Example Question #722 : Sat Mathematics

I have a hollow cube with 3” sides suspended inside a larger cube of 9” sides.  If I fill the larger cube with water and the hollow cube remains empty yet suspended inside, what volume of water was used to fill the larger cube?

Possible Answers:

73 in3

216 in3

72 in3

698 in3

702 in3

Correct answer:

702 in3

Explanation:

Determine the volume of both cubes and then subtract the smaller from the larger.  The large cube volume is 9” * 9” * 9” = 729 in3 and the small cube is 3” * 3” * 3” = 27 in3.  The difference is 702 in3.

Example Question #1 : Cubes

A cube weighs 5 pounds. How much will a different cube of the same material weigh if the sides are 3 times as long?

Possible Answers:

135 pounds

45 pounds

10 pounds

15 pounds

Correct answer:

135 pounds

Explanation:

A cube that has three times as long sides is 3x3x3=27 times bigger than the original. Therefore, the answer is 5x27= 135.

Example Question #1 : How To Find The Volume Of A Cube

If the volume of a cube is 50 cubic feet, what is the volume when the sides double in length?

Possible Answers:

300 cu ft

500 cu ft

400 cu ft

200 cu ft

100 cu ft

Correct answer:

400 cu ft

Explanation:

Using S as the side length in the original cube, the original is s*s*s. Doubling one side and tripling the other gives 2s*2s*2s for a new volume formula for 8s*s*s, showing that the new volume is 8x greater than the original.

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