All SAT Math Resources
Example Questions
Example Question #21 : Decimals And Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #71 : Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #72 : Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #73 : Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #74 : Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #75 : Percentage
Find the percentage equivalent of the decimal:
In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:
Example Question #51 : Percentage
The population of Town A is 12,979 people in 1995. The population, when measured again in 2005, is 22,752. What was the change in population to the nearest whole percentage point?
68%
43%
57%
175%
75%
75%
Since we are looking for the change, we must take the
(Ending Point – Starting Point)/Starting Point * 100%
(22752 – 12979)/12979 * 100%
9773/12979 * 100%
0.753 * 100%
75%
Example Question #1 : Percent Of Change
A factory produced 2500 units during the month of September. In order to increase production by 12% in the month of October, the factory hired more workers. How many units were produced in October?
3200
2800
3000
4000
3600
2800
This is a percentage increase problem.
Easiest approach : 2500 x 1.12 = 2800
In this way you are adding 12% to the original.
Using the formula, find 12% of 2500
12/100 = x/2500,
30000 = 100x
300 = x
Now add that to the original to find the new production:
2500 + 300 = 2800
Example Question #51 : Percentage
The radius of a given circle is increased by 20%. What is the percent increase of the area of the circle.
44%
40%
20%
100%
144%
44%
If we plug-in a radius of 5, then a 20% increase would give us a new radius of 6 (which is 1.2 x 5). The area of the new circle is π(6)2 = 36π, and the area of the original circle was π(5)2 = 25π . The numerical increase (or difference) is 36π - 25π = 11π. Next we have to divide this difference by the original area: 11π/25π = .44, which multiplied by 100 gives us a percent increase of 44%. The percent increase = (the numerical increase between the new and original values)/(original value) x 100. The algebraic solution gives us the same answer. If radius r of a certain circle is increased by 20%, then the new radius would be (1.2)r. The area of the new circle would be 1.44 π r2 and the area of the original circle πr2. The difference between the areas is .44 π r2, which divided by the original area, π r2, would give us a percent increase of .44 x 100 = 44%.
Example Question #241 : Arithmetic
Phoenicia is a grocery store that is expanding quickly.
In 2011 Phoenicia's total sales were $1,800,800.
In 2012 their sales rose to $2,130,346.
By what percentage did the store increase its income from 2011 to 2012.
(Round answer to the nearest tenth.)
18.3%
19.2%
21.0%
16.4%
10.5%
18.3%
$1,800,800 divided by 100 equals 18,008 and $2,130,346 divided by 18,008 is 118.3
So we know that $2,130,346 is 118.3% of the sales in the previous year. Hence sales increased by 18.3%.