The trick to this problem is to see that three of the choices have the numerator and denominator 3 units apart. The other two choices can be made three units apart as well- multiply both  and  by  to get them to be  and , respectively.

The trick is that once all fractions are the same units apart in denominator and numerator, the biggest number is the largest fraction.

We need to order: three fifths, seven eights, 0.5, sixteen eighteenths, 97%, seventeen fifths.

Let us re-write each as a fraction: , , , , , and . We can now easily order these:

Long division shows that 1/5 = 0.20 and 1/6 = 0.16666...  0.13 < 0.16 < 1/6 < 0.19 < 1/5 < 0.22 < 0.25.

Turn Trevor and Will’s amounts into decimals to compare: 20% = 0.20  and 7/12 = 0.5083 rounded. When the answer choices are converted into decimals, 2/7 = 0.2871 is the only value between 0.20 and 0.5083.

To solve this problem we set up a ratio of part of total. The part is the number of boys in the class and the total is the number of boys and girls in the class.

now to find the percent we can multiply this fraction by 10/10

From here we can see that it is 30%

To figure out what percentage of the class chose green markers, you must first figure out what fraction of the class chose green markers. Then, you must convert that fraction into a percentage.  

Figure out the fraction:

7 students chose green markers

40 students total

Fraction of students who chose green: 

To convert this fraction to a percentage, you must multiply the fraction times 100, then divide the numerator by the denominator. You multiply the fraction times 100 because in order to figure out the percent, you must figure out what the fraction means "for (per) every hundred (cent)".  

Multiply times 100

Therefore, the answer is .

For any percent  we can write it as a fraction in the form 

So we can write  as 

Then we simplify

So our simplified answer is 

In order to find the probability of rolling two even numbers on 2 dice we need to find the probability of each dice having an even number on the roll and then multiply them together.

The probability of rolling an even number is

because 2, 4, and 6 are even numbers which goes in the numerator and there are 6 total numbers which goes in the denominator. After this we reduce the fraction and get one half. Then we need to muliply this by probability of the second dice having an even number.

We can re write 15% as a fraction and then use proportions to solve.

From here we cross multiply and divide to solve for .

To solve this problem we set up a ratio. We want to find  of . Therefore, we set up the following ratio:

In the case  represents the number of questions that are multiple choice. From here we cross multiply and divide.