There are 5 different chiral centers in the molecule as shown below:

In order for a carbon to be a chiral center, it must be bonded to 4 different groups. The total number of possible stereoisomers is equal to , where n is the number of chiral centers. So in this case, 

There are 8 chiral centers which are marked below:

Carbon atoms need to be attached to 4 different groups to have a chiral center. Keep in mind that carbon atoms with a double bond can never be chiral. Looking at chiral center 1, the carbon is bonded to an alcohol group, a hydrogen atom, and two hydrocarbon groups. The hydrocarbon group clockwise is not identical to the hydrocarbon group counterclockwise. So this carbon would be considered bonded to 4 different groups making it chiral.

The orientation of the chiral center is based on what the carbon is bonded to. The heaviest atom that the carbon is bonded is given higher priority. 

Top:   Bottom:

For the top carbon the oxygen is the heaviest, so it receives a 1, with the hydrogen as the least important group 4. The least priority group should be placed in the back, such as shown in the bottom example, before determining clockwise or counterclockwise orientation. For the bottom section, going from most important to least important groups, while ignoring the least important group, you get clock wise or  R orientation. 

Interpreting the top carbon is different because the least important group is not in the back. Reading from high to low priority, while the hydrogen is in the front, gives a S configuration (ignore the 4th priority group when rotating). Since the hydrogen group is opposite from where it should be, the orientation is opposite as well.

Label the priority of bonded groups first. 

Moving from first to second to third, which ignoring the 4th important group, gives a counterclockwise direction, or S.

Enantiomers are chiral isomers of the same molecule that are mirror images of one another. Because of this characteristic, enantiomers cannot be placed on top of one another (superimposed) and yield the same molecule.

There are 11 stereocenters, because here there are 11 asymmetric carbons and no E/Z isomerisms, nor planes of symmetry.

There are 11 stereocenters, because here there are 11 asymmetric carbons and no E/Z isomerisms, nor planes of symmetry. For compounds with no meso isomers or E/Z isomerisms, the possible number of stereoisomers is  where  is the number of stereocenters.

There are 11 asymmetric carbons and one E double bond, so there are 13 stereocenters in total.  For each E/Z isomerism, there are 2 stereocenters. 

Here there are 11 asymmetric carbons and one E/Z isomerism.

So, the number of possible stereocenters from asymmetric carbons is , and the number of possible stereoisomers from E/Z isomerisms is .

Thus the number of stereoisomers from asymmetric carbons is doubled, and   possible stereoisomers

The absolute configuration around carbons 2 and 4 is R and S, respectively. The molecule is a hexanol, and the numbering starts with the carbon closest to the hydroxyl group.