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Example Questions
Example Question #471 : Organic Chemistry
What type of reaction would ensue if the ketone compound shown was introduced to (a Grignard reagent in water).
Oxidation-reduction reaction
Grignard addition reaction
No reaction
No reaction
Grignard reagents are known for their ability to readily attack carbonyls at the point of their carbons. However, Grignard reagents do not work in the presence of protic solvents. Rather than reacting with the desired molecule, the Grignard is so unstable that it will readily accept a proton from a protic solvent. The Grignard then becomes inert and no reaction ensues with the desired molecule.
Example Question #472 : Organic Chemistry
3-bromopropene was treated with
What is the final major product?
Cyclohexene
Hexanol
Hexene
6-bromohex-4-ene
Hexene
Any time we have a Grignard reagent and a primary haloalkane, we will see a substitution reaction, identical to an reaction. In this case, the Grignard can easily attack the haloalkane as the bromine leaves to create hexene.
Example Question #6 : Organic Reducing Agents
What reactant(s) is/are needed to drive this reaction?
The carbons on the epoxide compound experience a slightly positive charge. As a result, a Gringard reagent can easily attack the less substituted side of the epoxide to break the ring and to form a six membered carbon chain. is used to protonate the negatively charged oxygen atom.
Example Question #473 : Organic Chemistry
Which of the following can be reduced when mixed with ?
is a very powerful reducing agent that works to reduce almost any carbonyl compound. is an amide and the only carbonyl compound given of the answer choices.
Example Question #24 : Redox Chemistry
What reagents are needed to satisfy the given reaction?
This problem requires that we convert our ketone group into a chlorine. However, this cannot be done directly, and requires multiple steps.
We begin by reducing the ketone with to form an alcoxide. The alcoxide undergoes workup (the process whereby a negatively charged oxygen gains a proton) via , depicted above as simply "". We now have a secondary alcohol. From here, we can simply use the reagent to convert the alcohol into the desired chlorine.
Example Question #474 : Organic Chemistry
What is the product of the given reaction?
V
II
IV
I
III
IV
First step: esterification
Second step: lithium aluminum hydride reduction
Third step: neutralization to form primary alcohol
Fourth step: SN2 reaction to form final chlorinated product
Example Question #475 : Organic Chemistry
What is the result of the following reaction?
All of the above
Lithium Aluminum Hydride is a potent reducing agent; it has the ability to turn esters and aldehydes into primary alcohols, and ketones into secondary alcohols. The starting material is an aldehyde, so the correct answer is thus a primary alcohol ONLY.
Example Question #476 : Organic Chemistry
Which of the following is not a reducing agent?
is not a reducing agent; peroxides (compounds with the formula R-O-O-R) are oxidizing agents. A very common peroxide is sodium peroxide .
All of the other listed compounds are reducing agents.
Example Question #1 : Using Other Organic Reducing Agents
Which reagents reduce alkynes to trans alkenes?
Meta-Chloroperoxybenzoic acid
produces a trans-alkene from an alkyne whereas produces a cis-alkene. reduces an alkyne all the way down to an alkane. is a strong oxidizing agent.
Example Question #3 : Using Other Organic Reducing Agents
Identify the major product of the pictured reaction. Assume workup.
1.
2.
3.
4.
This is a standard organolithium reaction.
The organolithium product can be thought of as a strong nucleophile. The carbon steals an electron from the lithium to create . From there, the highly reactive carbo-anion is free to attack the ketone at the site of its carbon to form a tertiary alcohol on the cyclohexane.
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