Call Now to Set Up Tutoring:

(888) 888-0446

New SAT Math - No Calculator : New SAT Math - No Calculator

Study concepts, example questions & explanations for New SAT Math - No Calculator

Create An Account

All New SAT Math - No Calculator Resources

3 Diagnostic Tests 1 Practice Test Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 7 Next →

Example Question #1 : How To Find Compound Interest

A truck was bought for $\$ 20,000$ in 2008, and it depreciates at a rate of $13\%$ per year. What is the value of the truck in 2016? Round to the nearest cent.

Possible Answers:

y= 6664.23

y= 5664.23

y= 6764.23

y= 6564.23

y= 16564

Correct answer:

y= 6564.23

Explanation:

The first step is to convert the depreciation rate into a decimal. $13\%=0.13$ . Now lets recall the exponential decay model. y=C(1-r)^t , where is the starting amount of money, is the annual rate of decay, and is time (in years). After substituting, we get

y=20000(1-0.13)^8

y=20000(0.87)^8

$y=20000\cdot 0.3282117$

y= 6564.23

Report an Error

Example Question #11 : New Sat Math No Calculator

What is $320^{\circ}$ in radians?

Possible Answers:

$-\frac{13\pi}{9}$

$\frac{\pi}{9}$

$\frac{9\pi}{16}$

$\frac{16}{9}$

$\frac{16\pi}{9}$

Correct answer:

$\frac{16\pi}{9}$

Explanation:

To convert degrees to radians, we need to remember the following formula.

$\mbox{degrees}\cdot \frac{\pi}{180}$ .

Now lets substitute for degrees.

$320\cdot \frac{\pi}{180}=\frac{16\pi}{9}$

Report an Error

Example Question #191 : New Sat

Trans

Lines P and Q are parallel. Find the value of .

Possible Answers:

$x=-5+ \sqrt{ 205}$

$x=-5- \sqrt{ 205}$

$x=5 + \sqrt{ 205}$

$x=\pm \sqrt{ 205}$

$x= \sqrt{ 205}$

Correct answer:

$x=-5+ \sqrt{ 205}$

Explanation:

Since these are complementary angles, we can set up the following equation.

x^2+4+10x-4=180

x^2+10x=180

x^2+10x-180=0

Now we will use the quadratic formula to solve for .

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-10\pm \sqrt{10^2-4(1)(-180)}}{2(1)}$

$x=\frac{-10\pm \sqrt{100+720}}{2}$

$x=\frac{-10\pm \sqrt{820}}{2}$

$x=\frac{-10\pm \sqrt{4\cdot 205}}{2}$

$x=\frac{-10\pm 2\sqrt{ 205}}{2}$

$x=-5\pm \sqrt{ 205}$

Note, however, that the measure of an angle cannot be negative, so $x=-5- \sqrt{ 205}$ is not a viable answer. The correct answer, then, is $x=-5+ \sqrt{ 205}$

Report an Error

Example Question #11 : New Sat Math No Calculator

Find the equation of a line that goes through the points (0,3) , and (-10,4) .

Possible Answers:

y=-10x

$y=-\frac{1}{10}x+3$

y=-13x

y=-10x+3

$y=-\frac{1}{10}x$

Correct answer:

$y=-\frac{1}{10}x+3$

Explanation:

For finding the equation of a line, we will be using point-slope form, which is

y-y_0=m(x-x_0) , where is the slope, and (x_0, y_0) is a point.

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-3}{-10-0}=\frac{1}{-10}=-\frac{1}{10}$

We will pick the point (0,3)

$y-3=-\frac{1}{10}(x-0)$

$y=-\frac{1}{10}x+3$

If we picked the point (-10,4)

$y-4=-\frac{1}{10}(x+10)$

$y=-\frac{1}{10}x-1+4$

$y=-\frac{1}{10}x+3$

We get the same result

Report an Error

Example Question #21 : How To Find The Equation Of A Line

Find the equation of a line that passes through the point (-2,5) , and is parallel to the line y=-3x+4 .

Possible Answers:

y=-3x-3

y=-3x+1

y=-3x-1

y=-3x-10

y=-3x

Correct answer:

y=-3x-1

Explanation:

Since we want a line that is parallel, we will have the same slope as the line (-3) . We can use point slope form to create an equation.

y-y_0=m(x-x_0) , where is the slope and (x_0, y_0) is a point.

y-5=-3(x-(-2))

y-5=-3(x+2)

y-5=-3x-6

y=-3x-1

Report an Error

Example Question #1 : Rectangles

A rectangular garden has an area of $80\: \mbox{m^2}$ . Its length is meters longer than its width. How much fencing is needed to enclose the garden?

Possible Answers:

$40\: \mbox{meters}$

$24\: \mbox{meters}$

$18\: \mbox{meters}$

$54\: \mbox{meters}$

$36\: \mbox{meters}$

Correct answer:

$36\: \mbox{meters}$

Explanation:

We define the variables as $w = \mbox{width}$ and $l = \mbox{length} = w + 2$ .

We substitute these values into the equation for the area of a rectangle and get $A_{\mbox{rectangle} }= wl = w(w + 2) = 80$ .

w^2 +2w-80=0

(w - 8)(w + 10) = 0

w = 8 or w = -10

Lengths cannot be negative, so the only correct answer is w = 8 . If w = 8 , then l = 10 .

Therefore, $\mbox{perimeter }= 2w + 2l = 16 + 20 = 36\:\mbox{m}$ .

Report an Error

Example Question #191 : New Sat

If 3x + 72 = 9x + 120 , what does equal?

Possible Answers:

Correct answer:

Explanation:

Subtract and from the both sides to get -6x = 48 .

Divide both sides by , to get

$x=\frac{48}{-6}=-8$

Report an Error

Example Question #671 : Sat Mathematics

Screen shot 2016 02 10 at 1.10.30 pm

What is the equation of the graph?

Possible Answers:

y=x^2-4x-4

y=2x^2 +4x+4

y=ax^2-4x+4

y=2x^2-4x+4

y=2x^2-4x-4

Correct answer:

y=2x^2-4x+4

Explanation:

In order to figure out what the equation of the image is, we need to find the vertex. From the graph we can determine that the vertex is at (1,2) . We can use vertex form to solve for the equation of this graph.

Recall vertex form,

y=a(x-h)^2+k , where is the coordinate of the vertex, and is the coordinate of the vertex.

Plugging in our values, we get

y=a(x-1)^2+2

To solve for , we need to pick a point on the graph and plug it into our equation.

I will pick (-1,10) .

10=a(-1-1)^2+2

10=a(-2)^2+2

10=4a+2

8=4a

$a=\frac{8}{4}=2$

Now our equation is

y=2(x-1)^2+2

Let's expand this,

y=2(x^2-2x+1)+2

y=2x^2-4x+2+2

y=2x^2-4x+4

Report an Error

Example Question #11 : New Sat Math No Calculator

Which expression is equivalent to the following quotient? For b>0, c>0 .

$\frac{10a^2b^{-3}c^3}{5bc^2}$

Possible Answers:

$\frac{2a^2c}{b^4}$

$\frac{2a^2c^0}{b^4}$

$\frac{2ac}{b^2}$

$\frac{2a^2c}{b^{-4}}$

$\frac{2a^{-2}c}{b^4}$

Correct answer:

$\frac{2a^2c}{b^4}$

Explanation:

All we need to do is remember the quotient rule for exponents.

$\frac{a^n}{a^m}=a^{n-m}$

We apply this to each term and we get the following.

$\frac{10a^2b^{-3}c^3}{5bc^2}=2a^2b^{-3-1}c^{3-2}=2a^2b^{-4}c^1=\frac{2a^2c}{b^4}$

Report an Error

Example Question #101 : Algebra

Solve for x:

$\frac{x+3}{7}=3$

Possible Answers:

x=0

x=18

x=24

x=42

x=6

Correct answer:

x=18

Explanation:

The first step is to cancel out the denominator by multiplying both sides by 7:

$7\cdot \frac{x+3}{7}=3\cdot7$

x+3=21

Subtract 3 from both sides to get by itself:

x+3-3=21-3

x=18

Report an Error

← Previous 1 2 3 4 5 6 7 Next →

View SAT Math Tutors

Zihe
Certified Tutor

State University of New York at New Paltz, Master of Philosophy, Philosophy.

View SAT Math Tutors

Leonard
Certified Tutor

Florida State University, Bachelor of Science, Environmental Science.

View SAT Math Tutors

Haani
Certified Tutor

University of North Carolina at Chapel Hill, Bachelor in Arts, Economics. North Carolina State University at Raleigh, Master ...

All New SAT Math - No Calculator Resources

3 Diagnostic Tests 1 Practice Test Question of the Day Flashcards Learn by Concept

Popular Subjects

GRE Tutors in Washington DC, ISEE Tutors in Atlanta, GRE Tutors in San Diego, GRE Tutors in Miami, Biology Tutors in Washington DC, MCAT Tutors in Atlanta, ACT Tutors in Houston, Statistics Tutors in New York City, GMAT Tutors in Washington DC, Biology Tutors in Philadelphia

Popular Courses & Classes

SAT Courses & Classes in Atlanta, ACT Courses & Classes in Miami, ACT Courses & Classes in Boston, LSAT Courses & Classes in Chicago, SSAT Courses & Classes in San Diego, Spanish Courses & Classes in Los Angeles, ACT Courses & Classes in Denver, ISEE Courses & Classes in Dallas Fort Worth, GMAT Courses & Classes in Los Angeles, MCAT Courses & Classes in Washington DC

Popular Test Prep

SAT Test Prep in Los Angeles, MCAT Test Prep in San Francisco-Bay Area, LSAT Test Prep in Houston, ISEE Test Prep in Miami, GRE Test Prep in San Francisco-Bay Area, SAT Test Prep in Philadelphia, LSAT Test Prep in Seattle, SSAT Test Prep in New York City, MCAT Test Prep in Los Angeles, ISEE Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

New SAT Math - No Calculator : New SAT Math - No Calculator

Study concepts, example questions & explanations for New SAT Math - No Calculator

All New SAT Math - No Calculator Resources

Example Questions

Example Question #1 : How To Find Compound Interest

Example Question #11 : New Sat Math No Calculator

Example Question #191 : New Sat

Example Question #11 : New Sat Math No Calculator

Example Question #21 : How To Find The Equation Of A Line

Example Question #1 : Rectangles

Example Question #191 : New Sat

Example Question #671 : Sat Mathematics

Example Question #11 : New Sat Math No Calculator

Example Question #101 : Algebra

All New SAT Math - No Calculator Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: