MCAT Physical : Newtonian Mechanics and Motion

Study concepts, example questions & explanations for MCAT Physical

varsity tutors app store varsity tutors android store

Example Questions

Example Question #21 : General Principles

A runner completes a lap on a circular track in three minutes. The track has a radius of 210ft. The runner ran at a constant speed around the track.

What was the runner's average speed around the track?

Possible Answers:

Correct answer:

Explanation:

Since  we need to solve for the total distance around the track. 

Now, we can solve for speed using our equation. With 60 seconds per minute, 3 minutes is equal to 180 seconds.

Keep in mind that the question asked for the average speed, not velocity. Had it asked for the average velocity,  would be the correct answer, as the total displacement is zero.

 

 

Example Question #14 : Displacement, Velocity, And Acceleration

A velocity vs. time graph that shows the plotted line oscillating in a sinusoidal fashion. Which of the following scenarios could be represented by the sinusoidal line on the graph?

Possible Answers:

A man drives straight to work, only to find he forgot his briefcase. He quickly turns around and heads back home. He grabs it, and returns to work

A ball is thrown straight into the air and falls back to the ground

A runner does four laps around a circular track at a constant speed

A car drives in heavy traffic on a straight road, which causes it to accelerate and decelerate periodically

A projectile is launched at an angle from a tall cliff. Once it hits the ground, it bounces several times

Correct answer:

A runner does four laps around a circular track at a constant speed

Explanation:

Keep in mind that velocity is a vector, and a change in direction results in a change in velocity. When a runner runs in a circular manner around a track, the velocity of the runner will oscillate between a maximum positive velocity and a minimum negative velocity. As a result, this scenario matches the velocity vs. time graph appropriately. 

Example Question #15 : Displacement, Velocity, And Acceleration

A child throws a ball straight up into the air. He throws the ball with an initial velocity of . Assume there is no air resistance.

The child catches the ball in his glove after it falls. What is the total displacement of the ball?

Possible Answers:

Correct answer:

Explanation:

To solve this question, you must understand the difference between total distance and total displacement. While it is true that the baseball traveled a specific distance, the displacement is the final position of the baseball relative to the original position of the ball. The ball started and ended in the same place, so its total displacement is 0m.

Example Question #184 : Newtonian Mechanics And Motion

A child throws a ball straight up into the air. He throws the ball with an initial velocity of . Assume there is no air resistance.

What is the vertical acceleration of the ball when it is at its peak height?

Possible Answers:

Correct answer:

Explanation:

At its peak height, the ball will have a velocity of ; however, the acceleration on the ball due to gravity is constantly experienced by the baseball. As a result, while in the air, the ball will always have a vertical acceleration of 

Example Question #361 : Mcat Physical Sciences

A ball is thrown straight up into the air. When the ball is at the top of its flight, what is its acceleration?

Possible Answers:

It depends on the initial velocity of the ball

Correct answer:

Explanation:

Near the earth's surface (neglecting air resistance), all objects in free-fall accelerate downwards at . This occurs even when the object's velocity is zero, for example when it is at the top of its flight.

Example Question #1 : Friction And Normal Force

A  object is originally at rest on an inclined plane, which forms an angle with the ground of . If the coefficient of static friction is , what is the force of friction that must be overcome for the object to begin moving?

Possible Answers:

Correct answer:

Explanation:

In this situation, we must simply remember how to calculate friction. Once the force of gravity overcomes the force of static friction, the object will slide. Our formula for friction is:

This means the force of friction is equal to the friction coefficient times the normal force. On an incline, the normal force is equal to the force of gravity times the cosine of the angle:

We can combine our formulas to give the force of friction.

Using the given coefficient of friction, mass, and angle, we can calculate the force of friction.

Example Question #1 : Forces

When the force applied to a moving object is equal and opposite the force of kinetic friction, what happens to the object?

Possible Answers:

It decelerates

It moves with a constant velocity

It accelerates

It stops

It changes direction

Correct answer:

It moves with a constant velocity

Explanation:

It is important to understand the difference between static and kinetic friction. When an object is at rest, it takes more force to get it to start moving than to keep it moving. If you match the amount of static friction that can be generated when the object is at rest, it will not move because there is zero net force; the force applied must be greater than the static friction in order to initiate motion. Once the object begins moving, the force required to keep it moving decreases. If you match the force of kinetic friction, the object moves at a constant velocity because there is again no net force. Any more force will cause acceleration, while any less will cause deceleration.

Example Question #3 : Friction And Normal Force

A block rests on a wooden table. A spring scale attached to the right side of the block is very gently pulled to the right with increasing force. Which of these is true, assuming a frictional force between the table and the block?

Possible Answers:

The block will suddenly jerk to the right, and then stop

The block will move to the right at a uniform velocity

The block will move to the right proportional to the force applied to it

When the block begins to move, it will smoothly accelerate to the right

The block will not move until the spring scale reads

Correct answer:

The block will suddenly jerk to the right, and then stop

Explanation:

This is a classic experiment to determine the coefficient of static friction, . The frictional interaction of the block on the table causes an equal and opposite force to be generated against the pulling on the spring scale. The coefficient of static friction represents the ratio of the horizontal forces caused by surface irregularities to the vertical force due to gravity. 

When the frictional force is just barely overcome, the block will start moving to the right, but as soon as it does, the tension in the spring diminishes and static frictional forces prevail. The block thus starts moving and almost immediately stops.

Example Question #4 : Friction And Normal Force

A block rests on a wooden table. What is the force of the table upon the block?

Possible Answers:

Correct answer:

Explanation:

In this question, the net force on the block is zero. We know from Newton's second law that any non-zero force will produce an acceleration, resulting in movement of some sort. Since the block is at rest, and not moving, we can conclude that the net force is zero.

The forces acting on the block are the force of gravity, pulling the block downward, and the normal force, pushing the block upward. The force of the block on the table will be the force from gravity, while the force of the table on the block will be the normal force. Since these are the only two forces acting on the block, we can add them together to get the net force.

Reorganizing the equation, we can set the two forces equal. This is a reflection of Newton's third law.

Gravitational force is equal to the mass of the object times the acceleration from gravity.

Using these values, given in the question, we can find the normal force, or the force of the table on the block.

The final normal force is positive because it acts in the upward direction, opposite of gravity.

Example Question #2 : Forces

Two children are playing with sleds on a snow-covered hill. Sam weighs 50kg, and his sled weighs 10kg. Sally weighs 40kg, and her sled weighs 12kg. When they arrive, they climb up the hill using boots. Halfway up the 50-meter hill, Sally slips and rolls back down to the bottom. Sam continues climbing, and eventually Sally joins him at the top. 

They then decide to sled down the hill, but disagree about who will go first. 

Scenario 1:

Sam goes down the hill first, claiming that he will reach a higher velocity.  If Sally had gone first, Sam says they could collide.

Scenario 2:

Sally goes down the hill first, claiming that she will experience lower friction and thus reach a higher velocity. If Sam had gone first, Sally says they could collide.

Scenario 3:

Unable to agree, Sam and Sally tether themselves with a rope and go down together.

Who would you expect to experience a greater force of friction while traveling down the hill?

Possible Answers:

Sam, because he experiences a greater normal force

Sam, because he travels more quickly

Sally, because she travels more slowly

Sally, because she experiences less normal force

They would experience equal forces of friction because the coeffecients of friction are the same for both.

Correct answer:

Sam, because he experiences a greater normal force

Explanation:

The force of friction can be found from the following equation.

Force of Friction = Normal Force * Coeffecient of Friction

Normal force here is the force that the Earth pushes back on Sam against his mass. Thus, because he is more massive, he will experience a greater normal force and greater frictional force as a result.

Learning Tools by Varsity Tutors