MCAT Physical : Physical Chemistry

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

Example Question #2 : Electrochemistry

Imagine a galvanic cell which uses solid zinc and aqueous iron ions to produce a voltage.

 

    

     

Suppose that this galvanic cell was converted into an electrolytic cell. Which of the following statements would be true?

Possible Answers:

No electrons would flow from anode to cathode

The reaction is spontaneous

The cell potential would be negative

Oxidation would take place at the cathode

Correct answer:

The cell potential would be negative

Explanation:

An electrolytic cell is best thought of as a cell that requires an external power source in order to work. The reaction will go in the opposite direction of a galvanic cell, meaning that the cell potential will also be inversed and the reaction will be non-spontaneous. As a result, cell potential would be negative in an electrolytic cell.

Example Question #1 : Half Reactions And Reduction Potential

Imagine a galvanic cell which uses solid zinc and aqueous iron ions to produce a voltage.

 

    

     

Assuming standard conditions, what is the free energy for the reaction?

Possible Answers:

Correct answer:

Explanation:

Since the reaction is taking place under standard conditions, we can determine the free energy of the reaction by using the equation.

n is the number of moles of electrons transferred in the balanced reaction, F is Faraday's constant, and Eo is the cell potential for the reaction.

Example Question #1171 : Mcat Physical Sciences

Determine the cell potential of the following reaction.

Reduction potentials of and cations are  and , respectively.

Possible Answers:

Correct answer:

Explanation:

In the given reaction calcium, , is oxidized (loses electrons) and gold, , is reduced (gains electrons).

We are only given the reduction potentials. The oxidation potential of  is the negative of the reduction potential: .

Recall that only the moles of electrons must balance for these reactions, therefore no multiplication of the standard potentials is needed when balancing mole atoms; thus the cell potential is the sum of the calcium oxidation potential and the gold reduction potential.

Example Question #1172 : Mcat Physical Sciences

Consider the following half reactions and corresponding reduction potentials:

Based on the above information, which substance can oxidize  to  ?

Possible Answers:

Correct answer:

Explanation:

The reduction potential of  is , so the corresponding oxidation potential of  is .

For a substance to oxidize  to , it must have reduction potential greater than , so that the sum of the reduction potential of this compounds and the oxidation potential of  is positive.

The only choice that meets this requirement is .

Example Question #13 : Electrochemistry

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout.

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In the voltaic cell drawn above, what is true about the species Ag?

The reduction potential for  is 0.34. The reduction potential for  0.80.

Possible Answers:

It is neither reduced nor oxidized

It is oxidized and gains electons

It is oxidized and loses electrons

It is reduced and loses electrons

It is reduced and gains electrons

Correct answer:

It is reduced and gains electrons

Explanation:

As drawn above, the reaction must involve the oxidation of copper (lower reduction potential) and the reduction of silver (higher reduction potential). Reduction always means that a species gains electrons.

Example Question #1 : Voltaic/Galvanic Cells

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout. 

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In the above diagram, a KOH salt bridge is used. Which species would you anticipate finding at the tip of the arrow numbered 4?

The reduction potential for  is 0.34. The reduction potential for  0.80.

Possible Answers:

Correct answer:

Explanation:

The correct answer is , as we would need to balance the loss of positive silver ions in that half cell. Silver has the greater reduction potential, and is therefore gaining electrons to become more negative. As the negative charge develops, it will attract the positive potassium ions in the salt bridge.

Example Question #2 : Voltaic/Galvanic Cells

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout.

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The student in the passage creates a new cell, but uses the same element at both the anode and the cathode. What is likely to be true of this new cell?

Possible Answers:

This cell can generate energy, but only after energy is input into the system

The Gibbs free energy of this cell is zero

Reduction and oxidation are not occuring in the cell

This cell cannot generate energy

Different concentrations of the species are present in each cell

Correct answer:

Different concentrations of the species are present in each cell

Explanation:

This is an example of a concentration cell. If you have two half cells, each made of the same chemical species, and connect them with a wire, the cell will generate a voltage as it attempts to correct the disequilibrium induced by the concentration difference.

Example Question #1 : Voltaic/Galvanic Cells

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout.

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The student in the passage wants to replace the water, represented by the blue in the diagram, with an alternative solvent. Which solvent would be most likely to produce a functioning cell?

Possible Answers:

Carbon tetrachloride

Heptane

Ethane

Acetic acid

Benzene

Correct answer:

Acetic acid

Explanation:

The function of a voltaic cell requires the generation and dissolution of ions. Acetic acid is the only answer choice with a net dipole moment, and would therefore be the only one to dissolve the ions produced. The other choices would be unable to dissolve the ions, and the cell would not function.

Example Question #14 : Electrochemistry

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout.

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If the structure labeled X were removed from the cell, which of the folllowing would be true?

The reduction potential for  is 0.34. The reduction potential for  0.80.

Possible Answers:

The cell would generate an uncontrolled burst of high energy

Copper ions forming during cell function would be increasingly repelled by existing ions in solution

Copper ions forming during cell function would be increasingly attracted by existing ions in solution

Ag ions forming during cell function would be inceasingly repelled by existing ions in solution

Ag ions forming during cell function would be inceasingly attracted by existing ions in solution

Correct answer:

Copper ions forming during cell function would be increasingly repelled by existing ions in solution

Explanation:

As the cell runs, only copper produces ions. Silver actually loses ions from solution. If this continues without balance by the salt bridge, the positive ions build up in the solution on the left side of the diagram, without any balanced negative ions, and repel the formation of new copper ions more and more strongly.

Example Question #5 : Voltaic/Galvanic Cells

A student conducts an experiment for a chemistry class. The student wishes to explore power generation from different types of voltaic cells. He sets up three different cells, and then compares the amount of energy generated from each one.

One of his cells is shown below as an example. Both remaining cells follow the same layout. 

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The student in the passage disassembles the cell, and attempts to rebuild it the next day. He forgets, however, to include  in the solvent of the half cell on the right side of the diagram. Which of the following is likely to happen?

Possible Answers:

The cell requires , not , in the right-side half reaction to function properly

The cell will produce more energy, because there is no existing ion to repel further ionization into solution

The cell will not function at all

The cell will function, but for a shorter period of time before it reaches equilibrium and ceases to produce energy

The cell will function without pre-existing in solution, but not without 

Correct answer:

The cell will not function at all

Explanation:

There must be  pre-existing in the right-side half reaction for the cell to function at all. Without the pre-existing ions, the cell has no electron acceptor dissolved in solution, and no electron transfer can therefore take place. Electron transfer is the fundamental energy-producing process that takes place in a voltaic cell.

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