We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

MCAT Physical : Translational Motion

Study concepts, example questions & explanations for MCAT Physical

Create An Account

All MCAT Physical Resources

8 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Motion In One Dimension

A child throws a ball straight up into the air. He throws the ball with an initial velocity of $\small 8\frac{m}{s}$ . Assume there is no air resistance.

How long will it take for the ball to reach a velocity of $\small 0\frac{m}{s}$ , while in the air?

Possible Answers:

0.8s

The baseball will never have a velocity of $\small 0\frac{m}{s}$ .

1.6s

1.2 s

Correct answer:

0.8s

Explanation:

In order to solve for the time at which the ball has a velocity of $\small 0\frac{m}{s}$ , we need to use an equation which incorporates all of the known variables. We know the acceleration due to gravity, the initial velocity, and the final velocity. As a result, the best equation to use is the one that allows us to simply solve for the unknown variable, time.

$\small v = v_{0} + at$

$\small 0\frac{m}{s} = 8\frac{m}{s} + (-10\frac{m}{s^{2}})(t)$

$\small t = 0.8 s$

Keep in mind that 1.6s is also a time at which the velocity is $\small 0\frac{m}{s}$ , but this time refers to the point when the boy catches the ball. The question asks for the specific time while the ball is still in the air, so the correct answer, 0.8s, refers to the point where the ball is at its peak height.

Report an Error

Example Question #1 : Calculating Motion In One Dimension

If a 15kg ball takes five seconds to strike the ground when released from rest, at what height was the ball dropped?

Possible Answers:

50m

250m

100m

75m

125m

Correct answer:

125m

Explanation:

Using the equation d=v_ot + (1/2)a(t^2) we can find the distance at which the ball was dropped. Notice that the mass of the ball does not matter in this problem. We are told that the ball is dropped from rest making, v_o =0 , thus we have d=(1/2)a(t^2) . When we plug in our values, and assuming that acceleration is equal to gravity (10m/s²) we find that d=(1/2)(10)(5^2) = 125m.

Report an Error

Example Question #2 : Calculating Motion In One Dimension

How far will an object travel after ten seconds if it is dropped into a bottomless pit?

Possible Answers:

50m

500m

25m

300m

250m

Correct answer:

500m

Explanation:

Since the object is dropped, the inital velocity is zero. Gravity is the only acceleration, the time is ten seconds, and the distance at which the object travels is unknown.

The equation d=v_ot +(1/2)at^2 can be used to find the distance traveled.

d=0+(1/2)(10m/s^2)(10s)^2=500m

Report an Error

Example Question #1 : Motion In One Dimension

How long does it take an object to travel a distance of 30m from rest at a constant acceleration of 2m/s²?

Possible Answers:

7.3s

2.7s

5.5s

10.9s

12.6s

Correct answer:

5.5s

Explanation:

Using the equation d=v_ot + (1/2)at^2 , we can solve for time.

Since the object started at rest, v_0=0 . Now we are left with the equation d=(1/2)at^2 .

$30m=\frac{1}{2}(2\frac{m}{s^2})t^2$

30s^2=t^2

t=5.5s

Plugging in the remaining values we can find that t = 5.5s.

Report an Error

Example Question #261 : Mcat Physical Sciences

A car is moving with a constant velocity of $10\frac{m}{s}$ when it abruptly stops, applying a constant breaking acceleration of $-5\frac{m}{s^2}$ . Over what distance does the car come to a stop?

Possible Answers:

10m

20m

15m

50m

Correct answer:

10m

Explanation:

This problem can be easily solved using the formula, $v{_{f}}^{2} = v{_{0}}^{2} + 2ax$ , and solving for . Our initial velocity is $10\frac{m}{s}$ , acceleration is $-5\frac{m}{s^2}$ , and final velocity is $0\frac{m}{s}$ .

$(0\frac{m}{s})^2=(10\frac{m}{s})^2+2(-5\frac{m}{s^2})x$

$0=100\frac{m^2}{s^2}-10\frac{m}{s^2}x$

$-100\frac{m^2}{s^2}=-10\frac{m}{s^2}x$

$\frac{-100\frac{m^2}{s^2}}{-10\frac{m}{s^2}}=10m=x$

The car comes to a stop after applying the breaks over 10m.

Report an Error

Example Question #262 : Mcat Physical Sciences

A sprinter running a 100m race accelerates constantly at $0.5\frac{m}{s^2}$ from rest. What is his approximate final velocity as he crosses the finish line?

Possible Answers:

$14\frac{m}{s}$

$50\frac{m}{s}$

$10\frac{m}{s}$

$7\frac{m}{s}$

Correct answer:

$10\frac{m}{s}$

Explanation:

To answer this question, we must have a solid understanding of the kinematics equations. For this question, we must use an equation relating final velocity, distance, and acceleration.

The best fit for this is $\nu_{f}^{2} - \nu_{o}^{2} = 2ax$ .

Since we are solving for final velocity, and we started from rest, we can simplify the equation.

$\nu_o=0\frac{m}{s}, a=0.5\frac{m}{s^2}, x=100m$

$\nu_{f}^{2} - (0\frac{m}{s})^{2} = 2(0.5\frac{m}{s^2})(100m)$

$\nu_{f} = \sqrt{2(0.5\frac{m}{s^2})(100m)} = \sqrt{100\frac{m^2}{s^2}}=10\frac{m}{s}$

Report an Error

Example Question #261 : Mcat Physical Sciences

An car accelerates from rest and travels 25m in 0.7s . What is the approximate acceleration of the car?

Possible Answers:

Correct answer:

Explanation:

The kinematics equation relating distance, time, and acceleration is $x = \upsilon_{o}t + \frac{1}{2}at^{2}$ .

Since we know that the car was initially at rest, we can rewrite the equation with zero initial velocity.

$x=\frac{1}{2}at^2$

Now we can plug in our values from the question, and solve for the acceleration.

$25m=\frac{1}{2}a(0.7s)^2$

$25m=\frac{1}{2}a(0.49s^2)=(0.245s^2)a$

$a=\frac{25m}{0.245s^2}=102\frac{m}{s^2}\approx 100\frac{m}{s^2}$

Report an Error

Example Question #261 : Mcat Physical Sciences

If an ball is dropped from a cliff $\small 80m$ high, how long will it take the ball to strike the ground?

Possible Answers:

4.04s

16.3s

5.05s

12.7s

Correct answer:

4.04s

Explanation:

Since acceleration is constant, we can use the appropriate kinematics equation to solve:

$d=v_0t + \frac{1}{2}at^2$

We are given the height of the cliff, which will be equal to the distance traveled. The initial velocity is zero since the ball starts from rest and the acceleration will be equal to the acceleration due to gravity. Use these values to calculate the time.

$80m=(0\frac{m}{s})t+\frac{1}{2}(9.8\frac{m}{s^2})t^2$

$t^2=\frac{80m}{\frac{1}{2}(9.8\frac{m}{s^2})}=16.3s^2$

$t=\sqrt{16.3s^2}=4.04s$

Report an Error

Example Question #31 : Translational Motion

A 2kg mass is suspended on a rope that wraps around a frictionless pulley. The pulley is attached to the ceiling and has a mass of 0.01kg and a radius of 0.25m. The other end of the rope is attached to a massless suspended platform, upon which 0.5kg weights may be placed. While the system is initially at equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling on the rope.

Screen_shot_2013-10-09_at_10.32.21_pm

What is the velocity of the platform two seconds after the rope is cut?

Possible Answers:

$19.6\frac{m}{s}$

$9.8\frac{m}{s}$

$26.4\frac{m}{s}$

$3.4\frac{m}{s}$

$5.1\frac{m}{s}$

Correct answer:

$19.6\frac{m}{s}$

Explanation:

Think back to the 3 main kinematics equations that we know.

v_f² = v_i² + 2aΔx

v_f = v_i + at

Δx = v_it + ½at²

We need to determine which formula will allow us to find final velocity after a given amount of time.

v_f = v_i + at = (0m/s) + (9.8m/s²)(2s) = 19.6m/s

Report an Error

Example Question #32 : Translational Motion

If an object is dropped from a height of 450 meters above Earth, what is its velocity just before impact?

Possible Answers:

95m/s

45m/s

6.7m/s

67m/s

Correct answer:

95m/s

Explanation:

First calculate the time it takes to hit the ground using the equation $d=v_o+\frac{1}{2}at^2$ .

We can plug in values (including acceleration due to gravity) and solve for t.

$450m=0\frac{m}{s}+\frac{1}{2}(10\frac{m}{s^2})t^2$

t = 9.49s

Next, find the final velocity with the equation v_f = v_o +at .

$v_f=0\frac{m}{s}+(10\frac{m}{s})(9.49s)=95\frac{m}{s}$

Report an Error

View MCAT Chemical and Physical Foundations of Biological Systems Tutors

Zehra
Certified Tutor

Albion College, Bachelor, Biochemistry . Wayne State University, Master's/Graduate, Medicine .

View MCAT Chemical and Physical Foundations of Biological Systems Tutors

Kylee
Certified Tutor

DeSales University, Bachelor of Science, Biology, General. Thomas Jefferson University, Doctor of Medicine, Community Health ...

View MCAT Chemical and Physical Foundations of Biological Systems Tutors

Travis
Certified Tutor

University of Rochester, Bachelor in Arts, Mathematics & English. University of New Hampshire, Master of Science, Mathematics.

All MCAT Physical Resources

8 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

GMAT Tutors in Atlanta, GRE Tutors in Washington DC, ISEE Tutors in Philadelphia, Biology Tutors in Miami, MCAT Tutors in Dallas Fort Worth, GMAT Tutors in Washington DC, Statistics Tutors in Houston, Statistics Tutors in Philadelphia, Computer Science Tutors in Phoenix, French Tutors in Seattle

Popular Courses & Classes

SAT Courses & Classes in Los Angeles, LSAT Courses & Classes in Chicago, LSAT Courses & Classes in Philadelphia, ACT Courses & Classes in San Diego, GRE Courses & Classes in Seattle, MCAT Courses & Classes in Seattle, SSAT Courses & Classes in Miami, LSAT Courses & Classes in Washington DC, SAT Courses & Classes in Denver, GMAT Courses & Classes in San Francisco-Bay Area

Popular Test Prep

GMAT Test Prep in Los Angeles, GMAT Test Prep in Seattle, MCAT Test Prep in Miami, SSAT Test Prep in Dallas Fort Worth, ISEE Test Prep in San Francisco-Bay Area, ISEE Test Prep in Phoenix, SSAT Test Prep in Chicago, ACT Test Prep in Denver, ACT Test Prep in Philadelphia, ACT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

MCAT Physical : Translational Motion

Study concepts, example questions & explanations for MCAT Physical

All MCAT Physical Resources

Example Questions

Example Question #11 : Motion In One Dimension

Example Question #1 : Calculating Motion In One Dimension

Example Question #2 : Calculating Motion In One Dimension

Example Question #1 : Motion In One Dimension

Example Question #261 : Mcat Physical Sciences

Example Question #262 : Mcat Physical Sciences

Example Question #261 : Mcat Physical Sciences

Example Question #261 : Mcat Physical Sciences

Example Question #31 : Translational Motion

Example Question #32 : Translational Motion

All MCAT Physical Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: