MCAT Physical : Translational Motion

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

Example Question #11 : Momentum

car moving east at  strikes the rear of a car, also traveling east at , and the two stay in contact after the collision. What is the final velocity of the cars?

Possible Answers:

Correct answer:

Explanation:

This is a case of inelastic collision because the objects stay in contact after the impact. The total momentum in a system is always conserved, regardless of collision type. Here, the momentum before the collision is given by the sum of the individual momentum of each car, and the momentum after the collision is given by the singular momentum of the joined vehicles.

We are given the mass of each car and their initial velocities, allowing us to completely solve the left side of this equation.

We can now use the combined mass of both cars to solve for their final velocity.

Example Question #12 : Momentum

ball moving at  strikes a stationary  solid ball head on. The smaller ball moves away at . What is the velocity of the first ball after the impact?

Possible Answers:

Correct answer:

Explanation:

Momentum is conserved in all situations. Here, we have an elastic collision, meaning that the objects do not stick together after the impact. Momentum is simply the product of mass and velocity, and it has the units .

We can solve this problem by setting the initial and final momentum of the system equal to each other. The momentum of the system will be the sum of the momentum of the parts.

The second ball contributes no momentum initially, because its initial velocity is zero. The total initial momentum comes from the initial velocity of the larger ball.

We know the mass of each ball and the final velocity of the smaller ball. Using these values, we can solve for the final velocity of the larger ball.

Example Question #11 : Momentum

An object of mass  is moving at a velocity of  when it undergoes a perfect inelastic collision with a stationary mass. After the collision, the objects are moving at velocity of . What is the mass of the stationary object?

Possible Answers:

Correct answer:

Explanation:

Momentum is given by the equation . Conservation of momentum states that .

The initial momentum is given by the sum of the initial momentums of the two objects. Because the second mass starts from rest, it becomes irrelevant in the equation.

After a perfectly inelastic collision, the two objects will stick together and their masses will add. The final velocity will apply to the combined mass of the two objects.

Since we know that , we can use our values from these calculations to solve for .

The mass of the second object must be 2kg.

Example Question #1 : Understanding Elastic And Inelastic Collisions

Ball A, traveling  to the right, collides with ball B, traveling  to the left. If ball A is 4kg and ball B is 6kg, what will be the final velocity and direction after a perfectly inelastic collision?

Possible Answers:

Correct answer:

Explanation:

A perfectly inelastic collision is when the two bodies stick together at the end. At the beginning the two balls are traveling separately with individual momentum values. Using the momentum equation , we can see that ball A has a momentum of (4kg)(7m/s) to the right and ball B has a momentum of (6kg)(8m/s) to the left. The final momentum would be the mass of both balls times the final velocity, (4+6)(vf). We can solve for vf through conservation of momentum; the sum of the initial momentum values must equal the final momentum.

Note: ball B's velocity is negative because they are traveling in opposite directions.

The negative sign indicates the direction in which the two balls are traveling. Since the sign is negative and we indicated that traveling to the left is negative, the two balls must be traveling 2m/s to the left after the perfectly inelastic collision.

Example Question #11 : Momentum

Two children are playing on an icy lake. Child 1 weighs 50kg, and child 2 weighs 38kg. Child 1 has a backpack that weighs 10kg, and child 2 has a backpack that weighs 5kg.

Over the course of the afternoon, they collide many times. Four collisions are described below.

Collision 1:

Child 1 starts from the top of a ramp, and after going down, reaches the lake surface while going  and subsequently slides into a stationary child 2. They remain linked together after the collision.

Collision 2:

Child 1 and child 2 are sliding in the same direction. Child 2, moving at , slides into child 1, moving at .

Collision 3:

The two children collide while traveling in opposite directions at  each.

Collision 4:

The two children push off from one another’s back, and begin moving in exactly opposite directions. Child 2 moves with a velocity of .

In all of the above scenarios, which of the following quantities is conserved?

I. Kinetic energy

II. Potential energy

III. Momentum

Possible Answers:

I and II

II and III

III only

I and III

I, II, and III

Correct answer:

III only

Explanation:

Kinetic energy and potential energy are interconverted. While total energy is conserved, kinetic energy is allowed to increase or decrease, provided that potential energy does the opposite. For example, as the child in collision 1 is starting at the top of a ramp, she has potential energy, but no kinetic energy. At the bottom of the ramp, all the potential energy has been turned into kinetic energy.

Momentum, on the other hand, is conserved in every collision.

Example Question #15 : Momentum

Two children are playing on an icy lake. Child 1 weighs 50kg, and child 2 weighs 38kg. Child 1 has a backpack that weighs 10kg, and child 2 has a backpack that weighs 5kg.

Over the course of the afternoon, they collide many times. Four collisions are described below.

Collision 1:

Child 1 starts from the top of a ramp, and after going down, reaches the lake surface while going  and subsequently slides into a stationary child 2. They remain linked together after the collision.

Collision 2:

Child 1 and child 2 are sliding in the same direction. Child 2, moving at , slides into child 1, moving at .

Collision 3:

The two children collide while traveling in opposite directions at  each.

Collision 4:

The two children push off from one another’s back, and begin moving in exactly opposite directions. Child 2 moves with a velocity of .

In collision 1, with what velocity will the children be traveling after the collision?

Assume that the velocity with which child 1 hits child 2 is the same as the velocity with which child 1 reaches the surface of the lake. Also assume that the original direction of travel for child 1 is positive. Ignore friction and wind resistance.

Possible Answers:

Correct answer:

Explanation:

Momentum is always conserved in collisions, and is equal to the product of mass and velocity.

 

Example Question #11 : Momentum

Two children are playing on an icy lake. Child 1 weighs 50kg, and child 2 weighs 38kg. Child 1 has a backpack that weighs 10kg, and child 2 has a backpack that weighs 5kg.

Over the course of the afternoon, they collide many times. Four collisions are described below.

Collision 1:

Child 1 starts from the top of a ramp, and after going down, reaches the lake surface while going  and subsequently slides into a stationary child 2. They remain linked together after the collision.

Collision 2:

Child 1 and child 2 are sliding in the same direction. Child 2, moving at , slides into child 1, moving at .

Collision 3:

The two children collide while traveling in opposite directions at  each.

Collision 4:

The two children push off from one another’s back, and begin moving in exactly opposite directions. Child 2 moves with a velocity of .

In collision 4, what is the final velocity of child 1? Ignore friction and air resistance.

Possible Answers:

Cannot be determined from the information given

Correct answer:

Explanation:

This is a reverse collision, and momentum is still conserved. The original momentum is zero.

Example Question #11 : Momentum

Which of the following is a correct description of an inelastic collision?

Possible Answers:

Neither kinetic energy nor momentum is conserved

Momentum is conserved, but kinetic energy is not

Kinetic energy is conserved, and momentum may be conserved

Kinetic energy is conserved, but momentum is not

Both kinetic energy and momentum are conserved

Correct answer:

Momentum is conserved, but kinetic energy is not

Explanation:

Momentum is conserved in any collision, but kinetic energy is only conserved in elastic collisions. So, an inelastic collision has conservation of momentum, but not conservation of kinetic energy.

Example Question #12 : Momentum

In an elastic collision, which of the following quantities is not conserved?

Possible Answers:

Mechanical energy

Potential energy

Kinetic energy

All of these are conserved

Momentum

Correct answer:

All of these are conserved

Explanation:

In an inelastic collision, kinetic energy is not conserved. In an elastic collision, kinetic energy is conserved and there is no transfer of energy to the surroundings.

Momentum is conserved regardless of the type of collision. All of the given quantities are conserved during an elastic collision.

Example Question #1 : Motion In One Dimension

A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a radius of 0.25m. The other end of the rope is attached to a massless suspended platform, upon which 0.5kg weights may be placed. While the system is initially at equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling on the rope.

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The rope is cut right above the 2 kgmass. What is the acceleration of the platform with the individual weights as it falls to the ground? 

Possible Answers:

19.6m/s2

9.8m/s2

0m/s2

4.9m/s2

Correct answer:

9.8m/s2

Explanation:

Remember that Newton’s second law is applicable regardless of whether we are talking about kinematics, torque, electric, magnetic, or gravitational force, thus, F = ma. We know that the only force acting in free-fall in an environment where we can neglect air resistance (i.e. most of the problems on the MCAT) is gravity. The acceleration due to gravity is 9.8m/s2. The sign could be + or – depending on how you decided to orient.

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