All MCAT Physical Resources
Example Questions
Example Question #3 : Catalysts, Transition States, And Activation Energy
Carbonic anhydrase is an important enzyme that allows CO2 and H2O to be converted into H2CO3. In addition to allowing CO2 to be dissolved into the blood and transported to the lungs for exhalation, the products of the carbonic anhydrase reaction, H2CO3 and a related compound HCO3-, also serve to control the pH of the blood to prevent acidosis or alkalosis. The carbonic anhydrase reaction and acid-base reaction are presented below.
CO2 + H2O H2CO3
H2CO3 HCO3- + H+
If the pH of the blood increases above 8, how would the activity of carbonic anhydrase change?
Decrease
Increase
Not change
Decrease
Extreme temperatures and pH levels decrease the activity of enzymes because they become denatured. In the body, most enzymes work optimally around a pH of 7.4. Increasing the pH too high would denature a protein because amino acids that are normally protonated at physiological pH (i.e. acidic residues) would become deprotonated. Lack of protonation would cause collapse of the tertiary and quaternary structures, leading to a decrease in enzyme function.
Example Question #4 : Catalysts, Transition States, And Activation Energy
Carbonic anhydrase is an important enzyme that allows CO2 and H2O to be converted into H2CO3. In addition to allowing CO2 to be dissolved into the blood and transported to the lungs for exhalation, the products of the carbonic anhydrase reaction, H2CO3 and a related compound HCO3-, also serve to control the pH of the blood to prevent acidosis or alkalosis. The carbonic anhydrase reaction and acid-base reaction are presented below.
CO2 + H2O H2CO3
H2CO3 HCO3- + H+
If the pH of the blood decreases below 7, how would the concentration of HCO3- change?
Increase
Decrease
No change
Decrease
Extreme temperatures and pH levels decrease the activity of enzymes because they become denatured. In the body, most enzymes work optimally around a pH of 7.4. Decreasing the pH too low would denature a protein because amino acids that are normally deprotonated at physiological pH (i.e. basic residues) would become protonated. Protonation would cause changes in tertiary and quaternary structures, leading to a decrease in enzyme function, thus the concentration of the product in the catalyzed reaction would decrease as well.
Example Question #5 : Catalysts, Transition States, And Activation Energy
Which of the following statements is false about catalysts?
Catalysts lower the activation energy (Ea) of certain reactions
Catalysts shift the equilibrium position of a reaction in favor of the products
All of these statements are true
Catalysts change the rate of the reaction
Catalysts shift the equilibrium position of a reaction in favor of the products
Catalysts do not shift the equilibrium position of a reaction in favor of the products.
Catalysts speed up chemical reactions by lowering the activation energy (Ea) of reactions, but do not affect the equilibrium position since the change in rate from reactants to products speeds up proportionally to the change in rate from products to reactants (the same Keq will be achieved whether a catalyst is used or not).
Example Question #6 : Catalysts, Transition States, And Activation Energy
If the reactants and/or products in a chemical reaction are gases, the reaction rate can be determined by measuring the change of pressure as the reaction proceeds. Consider the following reaction and pressure vs. reaction rate data below.
Trial |
PXY(torr) |
PZ(torr) |
Rate (torr/s) |
1 |
100 |
200 |
0.16 |
2 |
200 |
200 |
0.32 |
3 |
200 |
100 |
0.04 |
4 |
200 |
150 |
0.14 |
If an inhibitory catalyst were added to the reaction __________.
the concentration of YZ would decrease at equilibrium
the concentration of YZ would increase at equilibrium
the activation energy would decrease
the activation energy would increase
the activation energy would increase
A catalyst affects activation energy; an inhibitory catalyst increases activation energy. Catalysts do not affect equilibrium concentrations of products or reactants.
Example Question #7 : Catalysts, Transition States, And Activation Energy
Which of the following is false about catalyzed reactions?
Catalysts increase the forward rate, while reducing the reverse rate.
Catalysts lower the activation energy for the reaction.
Catalysts will not alter the equilibrium of the reaction.
Catalysts do not alter the energy change between the products and reactants.
Catalysts increase the forward rate, while reducing the reverse rate.
A catalyst is a substance that increases the rate of a reaction without being altered or used up in the reaction. Both the forward and reverse rates of the reaction are accelerated by a catalyst. Slowing the reverse rate, with an increase in forward rate, would result in a shift in equilibrium. Remember that a catalyst will never change the equilibrium constant (Keq) of a reaction.
Example Question #1 : Catalysts, Transition States, And Activation Energy
Suppose a catalyst is added to the equation. How will this affect ?
It will be decreased.
It will be unaffected.
It will be increased.
A catalyst will not accelerate this reaction.
It will be unaffected.
Remember that catalysts affect the kinetics of a reaction, but will not affect the equilibrium. As a result, will remain the same in the presence of a catalyst, though the reaction rate will accelerate.
Example Question #2 : Catalysts, Transition States, And Activation Energy
A scientist is studying a reaction, and places the reactants in a beaker at room temperature. The reaction progresses, and she analyzes the products via NMR. Based on the NMR readout, she determines the reaction proceeds as follows:
In an attempt to better understand the reaction process, she varies the concentrations of the reactants and studies how the rate of the reaction changes. The table below shows the reaction concentrations as she makes modifications in three experimental trials.
A different scientist runs the same reaction described in the passage. In this trial, however, the scientist adds a catalyst. With the addition of a catalyst, which of the following must be true?
I. The overall order of the reaction increases
II. The rate constant increases
III. The activation energy decreases
II and III
III only
I, II, and III
II only
I and II
II and III
The addition of a catalyst lowers the activation energy of a reaction. This means that the rate constant will increase, as the activation energy is a term used to calculate this value.
The Arrhenius equation shows that , where is the activation energy.
The order of the reaction, however, does not increase.
Example Question #3 : Catalysts, Transition States, And Activation Energy
Acids and bases can be described in three principal ways. The Arrhenius definition is the most restrictive. It limits acids and bases to species that donate protons and hydroxide ions in solution, respectively. Examples of such acids include HCl and HBr, while KOH and NaOH are examples of bases. When in aqueous solution, these acids proceed to an equilibrium state through a dissociation reaction.
All of the bases proceed in a similar fashion.
The Brønsted-Lowry definition of an acid is a more inclusive approach. All Arrhenius acids and bases are also Brønsted-Lowry acids and bases, but the converse is not true. Brønsted-Lowry acids still reach equilibrium through the same dissociation reaction as Arrhenius acids, but the acid character is defined by different parameters. The Brønsted-Lowry definition considers bases to be hydroxide donors, like the Arrhenius definition, but also includes conjugate bases such as the A- in the above reaction. In the reverse reaction, A- accepts the proton to regenerate HA. The Brønsted-Lowry definition thus defines bases as proton acceptors, and acids as proton donors.
Acids and bases can be used as catalysts to promote faster reactions of various types. Which of the following will be be true of these catalytic reactions?
I. The acid or base will be regenerated by the reaction
II. The acid or base will increase the activation energy of the reaction
III. The acid or base will increase the amount of energy released by exothermic reactions
I, II, and III
I only
I and II
I and III
II and III
I only
A catalyst must be regenerated in its original form for it to be considered as such. A catalyst is never consumed or produced by a reaction. At once, a catalyst cannot change the thermodynamic properties of a reaction, including the energy absorbed or released. Catalysts typically function by lowering the activation energy, not increasing it.
Example Question #11 : Catalysts, Transition States, And Activation Energy
As the above reaction progresses, a catalyst is added to the system. When the reaction reaches equilibrium, the amount of catalyst is doubled. What effect will this addition have on the reaction?
The rate of the forward reaction will increase and the rate of the reverse reaction will decrease
The rate of the forward reaction will increase
The rate of the reverse reaction will decrease
The rate of the forward reaction will increase and the rate of the reverse reaction will increase
The rate of the forward reaction will increase and the rate of the reverse reaction will increase
Catalysts affect reaction rate by lowering the energy of the transition state. In doing so, they lower the activation energy for the reaction and allow it to proceed faster. Catalysts do not affect the equilibrium constant, the equilibrium concentration of reactions, or the equilibrium concentration of products.
Chemical equilibrium is a dynamic state. The reaction still progresses, but in such a manner that the forward and reverse reaction rates are equal, creating the illusion of static chemical concentrations. Adding catalyst to the reaction at equilibrium will still impact reaction rate, but will not impact the chemical concentrations. For this to be achieved, the catalyst accelerates both the forward and reverse reactions, causing the increases to cancel out and leave the equilibrium concentrations unaffected.
Example Question #12 : Catalysts, Transition States, And Activation Energy
Reaction:
Step 1: (fast)
Step 2: (slow)
In the reaction above, which step is the rate-determining step and what is the intermediate?
Step 1 is the rate-determining step and BC2 is the intermediate
Step 2 is the rate-determining step and B is the intermediate
Step 2 is the rate-determining step and BC2 is the intermediate
Step 1 is the rate-determining step and B is the intermediate
Step 2 is the rate-determining step and BC2 is the intermediate
In this reaction, step 2 is the rate-determining step and BC2 is the intermediate. The rate-determining step is always the slowest step in the reaction; the rate of the entire reaction depends on the speed of this step. BC2 is the intermediate because intermediates are not found in the overall reaction; they are produced and then immediately consumed.
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