MCAT Physical : Gases

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

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Example Question #3 : Partial Pressure

The molecular weight of gas A is .

Gas A is in a mixture with four other gases and has a partial pressure of . The other four gases have partial pressures of  respectively.

What is the mass of gas A in this mixture?

Possible Answers:

Cannot be determined from the given information

Correct answer:

Cannot be determined from the given information

Explanation:

Recall Dalton’s Law of partial pressure:

In this equation,  is the partial pressure of the gas,  is the mole fraction of the gas, and  is the total pressure of the system. The mole fraction, , is defined as the moles of a compound divided by the total moles in the system:

From the given information, we can solve for mole fraction of gas A using the partial pressure of gas A and the total pressure of the system.

To find the mass of gas A we need to find the moles of gas A in the mixture and multiply it by the molecular weight of gas A; however, the information given in this question only allows us to solve for the mole fraction of gas A, or percentage of gas A in the system. To convert mole fraction to moles we would need to know the total number of moles in the mixture; therefore, the mass of gas A cannot be determined.

Example Question #4 : Partial Pressure

A container with a total pressure () of 3atm holds 0.80mol of oxygen and 0.20mol of nitrogen. What is the partial pressure of oxygen in this container?

Possible Answers:

Correct answer:

Explanation:

Partial pressure is given by the mole fraction of a gas multiplied by the total pressure in the container. Mole fraction is equal to the moles of a given compound divided by the total moles.

This is an application of Dalton's Law.

Example Question #5 : Partial Pressure

Which of the following is false regarding partial pressure?

Possible Answers:

Partial pressure can be calculated if you know the mole fraction of the gas and the total pressure of the system

In Earth’s atmosphere, nitrogen has the largest partial pressure

Partial pressure signifies the pressure of a gas in a system at

Dalton’s Law of partial pressure is only valid for a mixture of inert gases

Correct answer:

Partial pressure signifies the pressure of a gas in a system at

Explanation:

Partial pressure of a gas is defined as the pressure of the gas in a mixture of gases. It is calculated by using Dalton’s Law of partial pressure, which states that the partial pressure is equal to the product of the mole fraction of the gas and the total pressure of the system.

One of the assumptions of this law is that the gases are independent and do not chemically react with each other. This means that the gases in the system have to be inert. If the gases were reactive with each other, then Dalton’s Law would become invalid. Recall that Earth’s atmosphere contains about 78% nitrogen, 21% oxygen, and 1% all other gases; therefore, nitrogen has the largest partial pressure in the atmosphere because it has the greatest mole fraction.

Partial pressure does signify the pressure of a gas in a mixture of gases, but it is only valid for the temperature of the system. The partial pressure of the gas will be different for different temperatures. This occurs because pressure is dependent on temperature. Changing the temperature will not alter the mole fraction (amount of gas); however, it will alter the total pressure which will subsequently alter the partial pressure of the gas according to Dalton's Law.

 

Example Question #1 : Other Gas Principles

An ideal gas with a volume of one liter at STP is placed into a piston chamber that can freely change volume. The volume is measured as the temperature is lowered. The gas will achieve its minimal volume at __________.

Possible Answers:

its boiling point

Correct answer:

its boiling point

Explanation:

The best answer is the compound's boiling point. At this point, it ceases obeying the gas laws and becomes a liquid.

If it were possible to remain in a gaseous state to zero Kelvin (), then this would be the correct answer. As the gas changes to a liquid, it becomes effectively resistant to further compression and will occupy the same volume through any further decrease in temperature.

Example Question #63 : Fluids And Gases

Diffusion can be defined as the net transfer of molecules down a gradient of differing concentrations. This is a passive and spontaneous process and relies on the random movement of molecules and Brownian motion. Diffusion is an important biological process, especially in the respiratory system where oxygen diffuses from alveoli, the basic unit of lung mechanics, to red blood cells in the capillaries.

Capture

Figure 1 depicts this process, showing an alveoli separated from neighboring cells by a capillary with red blood cells. The partial pressures of oxygen and carbon dioxide are given. One such equation used in determining gas exchange is Fick's law, given by:

ΔV = (Area/Thickness) · Dgas · (P1 – P2)

Where ΔV is flow rate and area and thickness refer to the permeable membrane through which the gas passes, in this case, the wall of the avlveoli. P1 and P2 refer to the partial pressures upstream and downstream, respectively. Further, Dgas­, the diffusion constant of the gas, is defined as:

Dgas = Solubility / (Molecular Weight)^(1/2)

At an alveoli-capillary diffusion equilibrium, which of the following is true?

Possible Answers:

There is a 2:1 exchange of oxygen.

There is a 4:1 exchange of carbon dioxide.

There is a 1:1 exchange of oxygen.

There is a 5:1 exchange of carbon dioxide.

Correct answer:

There is a 1:1 exchange of oxygen.

Explanation:

This is also a straightforward question that can be answered from little to no information from the passage. The point of emphasis here is equilibrium. At a diffusion equilibrium there is no net change, and thus, a one-to-one oxygen molecule exchange fits the bill. 

Example Question #64 : Fluids And Gases

Gas X has a density of  and gas Y has a density of . Equal volumes of the two gases are sealed in a container, which is then punctured by a small pin. Which gas diffuses faster out of the container?

Possible Answers:

Gas X because it has a lower molar mass than gas Y

Gas Y because it has a lower molar mass than gas X

Gas Y because it has a higher molar mass than gas X

Gas X because it has a higher molar mass than gas Y

Correct answer:

Gas X because it has a lower molar mass than gas Y

Explanation:

To solve this question, we can use Graham's law of effusion:

Graham's law demonstrates that the rate of effusion is inversely proportional to the square root of the molar mass. Essentially, lighter gases will effuse more quickly than heavier gases.

Given the densities and equal volumes of the two gases, we see that the gas with the greater density will account for more molar mass. The volume of gas Y weighs twice as much as the volume of gas X. Based on this information, we can conclude that gas X diffuses faster because it has a lower molar mass.

Example Question #1 : Other Gas Principles

Which equation best describes Boyle's law?

Possible Answers:

Correct answer:

Explanation:

Boyle's law describes the inverse relationship between a change and pressure and a change in volume, while a sample of gas is kept at constant temperature. This relationship can be mathematically written as:

or

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