All MCAT Physical Resources
Example Questions
Example Question #54 : Fluids And Gases
Phase diagrams are used to depict changes in the properties of a solution at different temperatures and pressures. Below is a phase diagram of a polar solution.
In section 3, as the temperature increases, the velocity of the molecules __________ in a(n) __________ manner.
decreases . . . indirectly proportional
decreases . . . indirectly proportional
increases . . . directly proportional
increases . . . indirectly proportional
increases . . . indirectly proportional
This question asks you how the velocity of the molecules changes with increasing temperature. From molecular kinteics, we know that temperature is proportional to kinetic energy.
We can see that as temperature rises, the kinetic energy rises, however, the question asks us how the velocity changes. Now, we need to know how kinetic energy and velocity are related. We can pull this relationship from Newtonian mechanics.
If we simplify, we can see that . Velocity increases with increasing temperature, but in an indirectly proportional manner.
Example Question #1 : Real Gases And Ideal Gases
Under what conditions will a gas most closely follow ideal behavior?
High pressure and high temperature
Low pressure and low temperature
High pressure and low temperature
Moderate levels of both temperature and pressure
Low pressure and high temperature
Low pressure and high temperature
Ideal gases are assumed to have no intermolecular forces and to be composed of particles with no volume. Under high pressure, gas particles are forced closer together and intermolecular forces become a factor. In low temperatures intermolecular forces also increase, since molecules move more slowly, similar to what would occur in a liquid state. Just remember that ideal gas behavior is most closely approximated in conditions that favor gas formation in the first place—heat and low pressure.
Example Question #1 : Real Gases And Ideal Gases
Which of the following assumptions is not made by the ideal gas law?
The intermolecular interactions follow the Coulomb model of electric repulsion
The molecules move randomly
The size of the molecules is much smaller than the container
The van der Waals forces are negligible
The molecules obey Newton's laws of motion at all times
The intermolecular interactions follow the Coulomb model of electric repulsion
Under the ideal gas law, we assume that the interactions between the molecules are very brief and that the forces involved are negligible. The assumption that the molecules obey Coulomb's law when interacting with each other is not necessary; rather, an ideal gas must disregard Coulomb's law.
The ideal gas law assumes only Newtonian mechanics, disregarding any intermolecular or electromagnetic forces.
Example Question #1 : Real Gases And Ideal Gases
Which of the following factors does not explain why measurements of real gases deviate from ideal values?
The volume between the gas particles
Intermolecular forces
The volume of the gas particles themselves
All of these factors will cause deviation from ideal values
The volume between the gas particles
Measurements of real gases deviate from ideal gas predictions because intermolecular forces and the volume of the particles themselves are not taken into consideration for ideal gases. The volume of the space between particles is considered for ideal gases and does not contribute to deviation from ideal gas behavior.
Attraction between molecules causes real pressure to be slightly less than ideal pressure, while the volume of gas particles causes real volume to be slightly greater than ideal volume.
Example Question #3 : Real Gases And Ideal Gases
The definition of ideal pressure for a real gas is given as follows:
The constant signifies the attraction coefficient. This value is positive if the molecules attract each other and is negative if the molecules repel each other.
Which of the following would have a negative attraction coefficient, , if found in the gaseous state?
Sodium chloride
Dichloromethane
Oxygen with an electron configuration of
Magnesium with an electron configuration of
Magnesium with an electron configuration of
The question wants you to pick a molecule that will have a negative attraction coefficient, . The question states that the molecules that repel each other will have a negative . Recall that similar charges repel each other; therefore, you are looking for an ionized molecule (molecule with a positive or negative charge). In a closed container, these molecules will be force into contact with each other and generate repulsion forces.
Dichloromethane is a neutral molecule. This means that the dichloromethane molecules won’t repel each other. Similarly, sodium chloride is a neutral molecule and will not experience repulsion. Oxygen, with an electron configuration of , is also a neutral molecule. If you look at the periodic table, the neutral state of oxygen occurs when there are six valence electrons. The outermost shell of oxygen in this electron configuration has a total of six electrons; therefore, the oxygen has six valence electrons and is neutral.
On the other hand, magnesium, with an electron configuration of , is not neutral. Recall that a neutral magnesium atom has two valence electrons and an electron configuration of . The magnesium atom in this question, however, has lost two electrons (from the orbital) and became positively charged with a charge of ; therefore, the magnesium atoms are ionized, will repel each other, and will have a negative .
Example Question #2 : Real Gases And Ideal Gases
Consider a real gas with a constant amount and a constant pressure. It has a temperature of and a volume of . If you double the temperature, what will happen to the volume?
The volume will become greater than
The volume will become less than
The volume will become
The volume will become
The volume will become less than
This question can be solved using either Charles's law or the ideal gas law (converted into the combined gas law).
Charles's Law:
Ideal Gas Law:
The question states that the pressure and moles are held constant; therefore, the volume and temperature are directly proportional. If the question were asking about an ideal gas, the volume would double when you double the temperature
The volume would double for an ideal gas; however, the question is asking about a real gas. To find the correct relationship between volume and temperature we need to look at the equation for real gas volume. Remember that the volume we are concerned with is the volume of the free space in the container, given by the container volume minus the volume of the gas particles. The equation for real gas volume accounts for the volume of the container and the volume of the gas particles. For a real gas, the volume is given as follows:
In this equation, is the number of moles of gas particles and is the bigness coefficient. This equation implies that the volume of free space for a real gas is always less than the volume for an ideal gas; therefore, doubling the temperature will produce a volume that is less than the predicted volume for an ideal gas. Our answer, then, must be less than double the initial volume.
Note that for an ideal gas the bigness coefficient, , would be zero and the volume of free space would be equal to the volume of the container . This occurs because the volume of the gas particles is negligible for an ideal gas.
Example Question #52 : Fluids And Gases
Which of the following gases would behave the least ideally?
For a gas to behave ideally, is should have a low mass and/or weak intermolecular forces. Contrastingly, non-ideal gasses should have very large masses and/or have strong intermolecular forces. Therefore, the correct answer is which has very strong intermolecular forces, hydrogen bonds. Nonpolar gasses such as oxygen, and other diatomic gasses have very weak intermolecular forces and thus behave ideally.
Example Question #2 : Real Gases
Which of the following is relevant for real gases, but irrelevant for ideal gases?
I. Volume of gas particles
II. Intermolecular forces between gas particles
III. Volume of container
I and III
I and II
I only
III only
I and II
There are two main assumptions for an ideal gas (and a few smaller assumptions). First, the gas particles of the ideal gas must have no molecular volume. Second, the gas particles must exert no intermolecular forces on each other; therefore, forces such hydrogen bonding, dipole-dipole interactions, and London dispersion forces are irrelevant in ideal gases. Other small assumptions of ideal gases include random particle motion (no currents), lack of intermolecular interaction with the container walls, and completely elastic collisions (a corollary of zero intermolecular forces).
For real gases, however, these assumptions are invalid. This means that the real gas particles have molecular volume and exert intermolecular forces on each other.
Recall that the volume in the ideal gas law is the volume of the free space available inside the container. For ideal gases, the free space volume is equal to the volume of the container because the gas particles take up no volume; however, for real gases, the free space volume is the volume of the container minus the volume of the gas particles. Though the exact values of free space volume will differ, the volume of the container is important for both real and ideal gases.
Example Question #1 : Partial Pressure
Which of the following is a direct application of Henry's law?
Viscosity of the fluid in the lungs
Gas exchange in the lungs
Tract system from nostrils to alveoli
Volume in lung capacity
Air pressure in the lungs
Gas exchange in the lungs
Henry's Law directly applies to gas exchange in the lungs, as it states that the amount of dissolved gas in a liquid are proportional to the solubility of the gas in the liquid. As oxygen is dissolved in the bloodstream, it is able to diffuse into the air of the lungs depending upon intrapleural pressure of that particular gas. Essentially, Henry's law dictates how readily oxygen will cross the alveolar epithelium.
Example Question #2 : Partial Pressure
A container has three moles of gas A, three moles of gas B, and six moles of gas C. The total pressure of the system is . The partial pressure of gas B is __________ less than the partial pressure of gas C.
To solve this question you need to know the Dalton’s Law of partial pressure:
In this equation, is the partial pressure of the gas, is the mole fraction of the gas, and is the total pressure of the system. You also need to know the definition of mole fraction: moles of a compound divided by total moles in the system.
This question requires us to calculate the partial pressure of both gas B and gas C. First, let’s find the partial pressure of gas B. The mole fraction of gas B is:
We are given the total pressure of the system. Using the calculated mole fraction, we can solve for the partial pressure of gas B:
Similarly, we can find the partial pressure of gas C. The mole fraction of gas C is:
The mole fraction times the total pressure will give the partial pressure of gas C:
Finally, find the difference between the partial pressures of the two gases.
The partial pressure of gas B is less than the partial pressure of gas C.
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