All MCAT Physical Resources
Example Questions
Example Question #3 : Thin Layer Chromatography
After performing a TLC experiment, a researcher determines the Rf value of a component to be 2. He also notes that the solvent travelled a distance of 4cm on the plate. What can you conclude about this experiment?
The component travelled a distance of 8cm
The solvent is not volatile
There are multiple components in the mixture
The reported data does not seem valid
The reported data does not seem valid
To solve this problem we need to recall the definition of Rf.
The solvent is typically the most mobile substance on a TLC plate; therefore, it travels the farthest distance. This means that Rf is always less than one because the numerator of Rf is always smaller than the denominator. The question states that the Rf value is 2. Since this is greater than 1, the results don’t seem valid. This value indicates that the solute compounds were able to teravel farther on the TLC plate than the solvent (mobile phase).
Example Question #4 : Thin Layer Chromatography
Compounds A and B are found in a mixture. Rf values for both compounds were calculated. Which of the following sets of Rf values would reflect the largest separation between A and B?
Compounds A and B are in the same mixture; therefore, they will be separated using the same TLC plate. Recall the definition of Rf.
Since the same TLC plate was used, the denominator for both compound A and B will be the same (the total distance travelled by solvent alone is the same for a TLC plate). To separate them effectively, compounds must have travelled different distances along the plate. The best separation occurs when the difference between the distances travelled by the compounds is greatest.
Let’s assume the denominator to be 1 for both compounds. This means that the numerator is equal to the Rf value. If we compare the given Rf values with each other we realize that Rf values of 0.4 and 0.2 will give the biggest difference between the distances travelled by compounds A and B (difference is ); therefore, this will have the best separation.
Example Question #1 : Purification Techniques
In gel electrophoresis, a negatively charged particle will migrate towards the __________ and a positively charged particle will migrate towards the __________.
anode . . . anode
cathode . . . anode
anode . . . cathode
cathode . . . cathode
anode . . . cathode
Gel electrophoresis is a technique used to separate molecules based on size or charge. Charged particles can be separated because they migrate towards different ends of the gel.
Negatively charged particles always migrate towards the positive pole whereas positively charged particles always migrate towards the negative pole (opposites attract). In gel electrophoresis, the positive pole is called the anode and the negative pole is called the cathode; therefore, the charged particles will migrate to the respective nodes.
Example Question #2 : Electrophoresis
Which of the following is true regarding the isoelectric point (pI)?
I. It is a property of both the species and the environment
II. The environment is basic if the pH is greater than the pI
III. It represents the size of the species
II and III
I and II
III only
II only
II only
The isoelectric point is the pH at which a charged particle loses its charge and becomes neutral; therefore, the pI is only a property of the species (not its environment). When the pH of the environment equals the pI of the molecule, the electrical charge on the molecule disappears. A basic environment is characterized by a high pH. If the pH of the environment is higher than the pI, then the environment is basic. The size of the species is usually represented by mass or weight, not by pI.
pI of a substance affects other chemical properties, such as solubility. Charged species are polar and are likely to dissolve in polar solvents whereas uncharged species (when pH = pI) are likely nonpolar and are more soluble in nonpolar solvents.
Example Question #3 : Electrophoresis
A pH gradient is created on an electrophoresis gel. A mixture of charged proteins is run through this gel and is separated. Which of the following is a true statement?
Proteins are separated based on size in this gel
A protein stops migrating through the gel when its pH equals the pI of the gel
Other macromolecules cannot be separated via this method
Proteins that are uncharged at physiological pH can migrate through the gel
Proteins that are uncharged at physiological pH can migrate through the gel
A pH gradient in a gel facilitates the separation of charged species. The proteins in the mixture encounter different pHs as they travel through the gel. The driving force for the proteins is the electric force. Recall that each protein has an isoelectric point; when the protein's environmental pH equals the isoelectric point, the protein will become neutral and stop migrating (it loses the electric force). The physiological pH is about 7.4. Several amino acids are uncharged at this pH; however, these amino acids will become charged when presented in a different pH environment; therefore, these proteins will be charged and be able to migrate through the gel because of the pH gradient.
The protein will stop migrating when the pH of the environment (gel) equals the pI of the protein. Different types of gel electrophoresis are used to separate molecules based on charge and size. A pH gradient is used to separate molecules based on charge, whereas SDS-PAGE is used to separate molecules based on size. All types of macromolecules (nucleic acids, proteins, lipids, and carbohydrates) can be separated using gel electrophoresis.
Example Question #4 : Electrophoresis
Which of the following is true regarding sodium dodecyl sulfate (SDS)?
It binds to the primary structure of proteins
It adds positive charge to proteins
It allows for separation of proteins by size
It preserves the mass-to-charge ratio of proteins
It allows for separation of proteins by size
SDS is a substance added to polyacrylamide gels to separate substances based on size. This method is called SDS-PAGE. SDS binds to the secondary structure of proteins and gives them an overall negative charge; the bigger the substance the bigger the negative charge. The larger mass compensates for the bigger charge; therefore, SDS makes it so that the mass-to-charge ratio of all substances is the same. This standardizes the electric force experienced by each molecule, making size the only driving force for migration through the gel.
Example Question #11 : Physical Chemistry
Adenosine-triphosphate is formed by the following endothermic reaction.
If body temperature decreases, ADP production __________.
decreases
increases
is unpredictable
remains constant
increases
Since heat can be considered a reactant (endothermic), if heat is decreased, ADP is increased according to Le Chatelier’s Principle. If a reactant is removed, the equilibrium will shift toward the reactants. In this reaction, ADP and heat are both reactants.
Example Question #22 : Biochemistry, Organic Chemistry, And Other Concepts
Which of the following is true, assuming the reaction goes to completion?
I. There is an increase in , entropy
II.
III. At equilibrium,
IV. Oxygen is the reducing agent
I and IV
I and III
II and III
II only
I, II, and III
I, II, and III
This question ties together the reaction for oxidation of glucose with several thermodynamic principles.
The first option, stating that there is an increase of entropy, is true. When balanced, we see that there is an increase in total number of molecules when the reaction completes; thus, there will be an increase in entropy.
The second option states that enthalpy, or , is less than than zero. This is also true, as it implies that this is an exothermic (or heat generating) reaction. The oxidation of glucose is how our bodies generate heat and keep homeostasis.
The third option, stating that Gibb's free energy is zero at equilibrium, is also true. Any equation will have at equilibrium.
The last option, stating that oxygen is the reducing agent, is false. Oxygen is actually the oxidizing agent and is itself reduced.
Example Question #1 : Energetics Of Biological Reactions And Atp
ATP stores energy through its ability to lose a phosphate group to form ADP in the following reaction
At body temperature, the thermodynamic values for ATP hydrolysis are as follow.
Glycolysis is an energy-liberating process (, ) that is coupled with the conversion of two ADP molecules into two ATP molecules according to the following reaction.
Glycolysis results in which of the following?
A decrease in entropy
An increase in entropy
An increase in enthalpy
A conservation of entropy
An increase in entropy
Since glycolysis is an exothermic reaction (ΔH is negative), enthalpy does not increase. As for entropy, the reaction begins with a large molecule and ends with smaller molecules, therefore entropy increases.
Example Question #1 : Thermochemistry And Energetics
ATP stores energy through its ability to lose a phosphate group to form ADP in the following reaction
At body temperature, the thermodynamic values for ATP hydrolysis are as follow.
ΔG = –30kJ/mol
ΔH = –20kJ/mol
ΔS = 34kJ/mol
Glycolysis is an energy-liberating process (ΔG = –218kJ/mol, ΔH = –20 kJ/mol) that is coupled with the conversion of two ADP molecules into two ATP molecules according to the following reaction.
Glycolysis is __________.
endergonic and endothermic
exergonic and endothermic
endergonic and exothermic
exergonic and exothermic
exergonic and exothermic
ΔG and ΔH are both negative for glycolysis, meaning that the reaction is exergonic and exothermic.
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