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Linear Algebra : Operations and Properties

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Example Questions

Example Question #21 : The Transpose

$C^{T}C$ is a nonsingular square matrix.

True, false, or undetermined: is a nonsingular square matrix.

Possible Answers:

Undetermined

True

False

Correct answer:

Undetermined

Explanation:

A square matrix is nonsingular - that is, it has an inverse - if and only if its determinant is 0.

Let $C = \begin{bmatrix} 1\\ 2\\ 3 \end{bmatrix}$ a column matrix. Then the transpose is equal to the row matrix

$C^{T} = \begin{bmatrix} 1& 2& 3 \end{bmatrix}$ .

The product of a row matrix and a column matrix, each with the same number of elements, is a one-by-one matrix whose only element is the sum of the squares of the elements, so

$C^{T} C$

$= \begin{bmatrix} 1& 2& 3 \end{bmatrix} \begin{bmatrix} 1\\ 2\\ 3 \end{bmatrix}$

$= [1^{2}+2^{2}+3^{2}]$

= [1+4+9]

= [14]

The determinant of a one-by-one matrix is its only entry, so $C^{T} C$ is a square matrix with a nonzero determinant. This proves that $C^{T} C$ can be nonsingular for some non-square .

Now, let C = I , the two-by-two (or any other) identity matrix. is a nonsingular square matrix, and $I^{T} = I$ , so

$C^{T} C = I^{T}I = I I = I$ .

This proves that $C^{T} C$ can be nonsingular for some square .

Consequently, if $C^{T} C$ , it cannot be determined whether or not is a nonsingular square matrix.

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Example Question #23 : The Transpose

is an upper triangular matrix.

True or false: $A^{T}$ cannot be an upper triangular matrix.

Possible Answers:

False

True

Correct answer:

False

Explanation:

The identity matrix of any dimension serves as a counterexample that proves the statement false. Examine the three-by-three identity

$I = \begin{bmatrix} 1& 0&0 \\ 0& 1& 0\\ 0& 0 &1 \end{bmatrix}$

is an upper triangular matrix - all of its elements above its main diagonal are zeroes. The transpose of - the matrix formed by interchanging rows with columns - is itself. Therefore, is an upper triangular matrix whose transpose is also upper triangular.

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Example Question #21 : The Transpose

and $A ^{T}$ are both lower triangular square matrices. Which of the following must follow from this?

Possible Answers:

is a zero matrix

is an identity matrix

is a nonsingular matrix, but not necessarily the identity matrix.

is a singular matrix, but not necessarily a zero matrix.

is a diagonal matrix, but not necessarily an identity matrix or a zero matrix.

Correct answer:

is a diagonal matrix, but not necessarily an identity matrix or a zero matrix.

Explanation:

Let be a three-by-three matrix; this reasoning extends to square matrices of all sizes.

is a lower triangular matrix, so all of the entries above its main (upper left to lower right) diagonal are zeroes; that is,

$A = \begin{bmatrix} a&0 &0 \\ b& c& 0\\ d& e& f \end{bmatrix}$ .

$A ^{T}$ , the transpose of , is the matrix formed by switching rows with columns, so

$A^{T} = \begin{bmatrix} a&b&d \\ 0& c& e\\ 0& 0& f \end{bmatrix}$ .

However, $A ^{T}$ is lower triangular also; as a consequence,

b,d,e =0 ,

and

$A = \begin{bmatrix} a&0 &0 \\0& c& 0\\ 0& 0& f \end{bmatrix}$ .

This demonstrates that must be a diagonal matrix - one with only zeroes off its main diagonal.

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Example Question #51 : Operations And Properties

Let , , and be real numbers such that

$A = \begin{bmatrix} a& b& c\\ 1& 2& 3\\ -4&-5 &-6 \end{bmatrix}$ , $B = \begin{bmatrix} a&1 &-4 \\ b& 2& -5\\ c& 3& -6 \end{bmatrix}$ ,

and the determinant of is 8.

True or false: The determinant of is 8.

Possible Answers:

False

True

Correct answer:

True

Explanation:

is the transpose of - the matrix formed by interchanging the rows of with its columns. The determinant of a matrix and that of its transpose are equal, so, since has determinant 8, so does .

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Example Question #51 : Operations And Properties

$A = \begin{bmatrix} 1 + i & 1 - i \\ 2 & -2 \end{bmatrix}$

Find $A^{*}$ .

Possible Answers:

$A^{*} = \begin{bmatrix} 1+ i & -2\\ 1 + i & 2 \end{bmatrix}$

$A^{*} = \begin{bmatrix} 1- i & -2\\ 1 + i &2 \end{bmatrix}$

$A^{*} = \begin{bmatrix} 1+ i & 2\\ 1 - i & -2 \end{bmatrix}$

$A^{*} = \begin{bmatrix} 1+ i & 2\\ 1 + i & -2 \end{bmatrix}$

$A^{*} = \begin{bmatrix} 1- i & 2\\ 1 + i & -2 \end{bmatrix}$

Correct answer:

$A^{*} = \begin{bmatrix} 1- i & 2\\ 1 + i & -2 \end{bmatrix}$

Explanation:

$A^{*}$ , the conjugate transpose of , is the result of transposing the matrix - interchanging rows with columns - and changing each entry to its complex conjugate. First, find transpose $A^{T}$ :

$A = \begin{bmatrix} 1 + i & 1 - i \\ 2 & -2 \end{bmatrix}$ ,

$A^{T} = \begin{bmatrix} 1 + i & 2\\ 1 - i & -2 \end{bmatrix}$

Change each entry to its complex conjugate:

$A^{*} = \begin{bmatrix} 1- i & 2\\ 1 + i & -2 \end{bmatrix}$ .

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Example Question #53 : Operations And Properties

$A = \begin{bmatrix} 1 + i & 1 - i \\ 2 & -2 \end{bmatrix}$

Find $A^{T}$ .

Possible Answers:

None of the other choices gives the correct response.

$A^{T} = \begin{bmatrix} 1 + i & -2\\ 1 - i &2 \end{bmatrix}$

$A^{T} = \begin{bmatrix} 1 - i & -2\\ 1 + i & 2 \end{bmatrix}$

$A^{T} = \begin{bmatrix} 1 - i & 2\\ 1 + i & -2 \end{bmatrix}$

$A^{T} = \begin{bmatrix} 1 + i & 2\\ 1 - i & -2 \end{bmatrix}$

Correct answer:

$A^{T} = \begin{bmatrix} 1 + i & 2\\ 1 - i & -2 \end{bmatrix}$

Explanation:

$A^{T}$ , the transpose, is the result of switching the rows of with the columns.

$A = \begin{bmatrix} 1 + i & 1 - i \\ 2 & -2 \end{bmatrix}$ ,

$A^{T} = \begin{bmatrix} 1 + i & 2\\ 1 - i & -2 \end{bmatrix}$ .

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Example Question #31 : The Transpose

and are skew-symmetric matrices.

Which of the following is true of $A^{T} B^{T}$ ?

Possible Answers:

$A^{T} B^{T} =- AB$

$A^{T} B^{T} = AB$

Correct answer:

$A^{T} B^{T} = AB$

Explanation:

By definition, the transpose $A^{T}$ of a skew-symmetric matrix is equal to its additive inverse . It follows that

$A^{T} B^{T} =( -A)(-B) =( -1) A (-1)B = (-1)(-1)AB = AB$

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Example Question #55 : Operations And Properties

$A = \begin{bmatrix} 1 & 1 + i &0 \\ 1 & 1 - i & 0 \\ 0 & 1 & i \end{bmatrix}$

Find $A^{*}$ .

Possible Answers:

$\begin{bmatrix} 1 & 1 &0 \\ 1- i & 1 + i & 1 \\ 0 & 0 &- i \end{bmatrix}$

$\begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 &- i \end{bmatrix}$

$\begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 & i \end{bmatrix}$

$\begin{bmatrix} 1 & -1 &0 \\ 1- i & 1 + i & -1 \\ 0 & 0 &- i \end{bmatrix}$

$\begin{bmatrix} 1 & 1 &0 \\ 1-i & 1 +i & 1 \\ 0 & 0 & i \end{bmatrix}$

Correct answer:

$\begin{bmatrix} 1 & 1 &0 \\ 1- i & 1 + i & 1 \\ 0 & 0 &- i \end{bmatrix}$

Explanation:

$A^{*}$ , the conjugate transpose of , is the result of transposing the matrix - interchanging rows with columns - and changing each entry to its complex conjugate. First, find transpose $A^{T}$ :

$A = \begin{bmatrix} 1 & 1 + i &0 \\ 1 & 1 - i & 0 \\ 0 & 1 & i \end{bmatrix}$ ,

$A^{T}= \begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 & i \end{bmatrix}$

Change each entry to its complex conjugate:

$A^{*}= \begin{bmatrix} 1 & 1 &0 \\ 1- i & 1 + i & 1 \\ 0 & 0 &- i \end{bmatrix}$

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Example Question #56 : Operations And Properties

$A = \begin{bmatrix} -2 & 1 & 3 \\ 5 & 4 &- 1 \\ 4 & -2 & 1 \end{bmatrix}$

Which of the following is equal to $A ^{*}$ ?

Possible Answers:

$\begin{bmatrix} -2 & 5& 4 \\ 1 & 4 &- 2 \\ 3& -1&1 \end{bmatrix}$

$\begin{bmatrix} -2i & 5i & 4i \\ 1i & 4i &- 2i \\ 3i & -i & i \end{bmatrix}$

None of the other responses gives the correct answer.

$\begin{bmatrix} -2 & 5i & 4i \\ 1i & 4 &- 2i \\ 3i & -i & 1 \end{bmatrix}$

$\begin{bmatrix} -2i & 5& 4 \\ 1 & 4i &- 2 \\ 3& -i &1 \end{bmatrix}$

Correct answer:

$\begin{bmatrix} -2 & 5& 4 \\ 1 & 4 &- 2 \\ 3& -1&1 \end{bmatrix}$

Explanation:

$A^{*}$ , the conjugate transpose of , is the result of transposing the matrix - interchanging rows with columns - and changing each entry to its complex conjugate. First, find transpose $A^{T}$ :

$A = \begin{bmatrix} -2 & 1 & 3 \\ 5 & 4 &- 1 \\ 4 & -2 & 1 \end{bmatrix}$

$A^{T}= \begin{bmatrix} -2 & 5& 4 \\ 1 & 4 &- 2 \\ 3& -1&1 \end{bmatrix}$

Each entry of $A^{*}$ is equal to the complex conjugate of the corresponding entry of $A^{T}$ . However, each entry in $A^{T}$ is real, so each entry is equal to its own complex conjugate, and

$A ^{*} = A^{T}= \begin{bmatrix} -2 & 5& 4 \\ 1 & 4 &- 2 \\ 3& -1&1 \end{bmatrix}$

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Example Question #56 : Operations And Properties

$A = \begin{bmatrix} 1 & 1 + i &0 \\ 1 & 1 - i & 0 \\ 0 & 1 & i \end{bmatrix}$

Find $A^{T}$ .

Possible Answers:

$\begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 &- i \end{bmatrix}$

None of the other choices gives the correct response.

$\begin{bmatrix} 1 & 1 &0 \\ 1+i & 1 -i & 1 \\ 0 & 0 & i \end{bmatrix}$

$\begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 & i \end{bmatrix}$

$\begin{bmatrix} 1 & 1 &0 \\ 1-i & 1 +i & 1 \\ 0 & 0 & i \end{bmatrix}$

Correct answer:

$\begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 & i \end{bmatrix}$

Explanation:

$A^{T}$ , the transpose, is the result of switching the rows of with the columns.

$A = \begin{bmatrix} 1 & 1 + i &0 \\ 1 & 1 - i & 0 \\ 0 & 1 & i \end{bmatrix}$ ,

$A^{T}= \begin{bmatrix} 1 & 1 &0 \\ 1+ i & 1 - i & 1 \\ 0 & 0 & i \end{bmatrix}$ .

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Linear Algebra : Operations and Properties

Study concepts, example questions & explanations for Linear Algebra

All Linear Algebra Resources

Example Questions

Example Question #21 : The Transpose

Example Question #23 : The Transpose

Example Question #21 : The Transpose

Example Question #51 : Operations And Properties

Example Question #51 : Operations And Properties

Example Question #53 : Operations And Properties

Example Question #31 : The Transpose

Example Question #55 : Operations And Properties

Example Question #56 : Operations And Properties

Example Question #56 : Operations And Properties

All Linear Algebra Resources

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