There is only one way that the roll of two dice can come up 2 - for both dice to come up a one. 

The probability of a fair die coming up a one is , so the probability of this happening with the fair dice is .

The probability of a "1" coming up on the first altered die is

The probability of a "1" coming up on the second altered die is

Therefore, the probability of a roll of double one on the altered dice is

Therefore, "2" is more likely to come up on the fair dice.

The line graph only indicates the high and low temperatures for the individual days; it says nothing about the temperature at any specific time of any day. Therefore, the question cannot be answered from the graph alone.

Examine the low point of the line representing the high temperatures and the high point of the line representing the low temperatures.

It can be seen that the lowest of the high temperatures is 65 degrees (Friday), and that the highest of the low temperatures is 60 degrees (Wednesday). This makes the former quantity the greater.

The graph does not tell us the temperatures at any specific time of day on any of the seven days. However, as seen below, we know from the graph that the high temperature on Friday was 65 degrees.

The temperature at noon Friday cannot have been greater than 65 degrees, so 70 is the greater quantity.

There are five unique tiles - "J", "K", "Q", "X", and "Z" - and two blanks, for a total of 7 tiles not placed in the box. Therefore, the box contains 93 tiles.

The number of tiles with each vowel is as follows:

A: 9 tiles

E: 12 tiles

I: 9 tiles

O: 8 tiles

U: 4 tiles

This is a total of  vowel tiles. Therefore,  consonants remain. Since vowel tiles comprise fewer than half of the remaining tiles, the probability that the draw will be that of a vowel is less than .

It is easier to count the tiles that are vowels or blanks than it is to count the tiles marked with consonants. Keeping in mind that one of each vowel has been added, the number of each vowel is as follows:

A: 10 tiles

E: 13 tiles

I: 10 tiles

O: 9 tiles

U: 5 tiles

Blanks: 2 tiles

Add these:  tiles not marked with consonants. 

Since the five unique tiles - "J", "K", "Q", "X", and "Z" - were replaced by five vowel tiles, the number of tiles remained constant at 100. Therefore, there are 

consonant tiles; consonants therefore make up more than one half of the tiles, and the probability that a randomly drawn tile will be a consonant is greater than .

The number of tiles with each vowel is as follows:

A: 9 tiles

E: 12 tiles

I: 9 tiles

O: 8 tiles

U: 4 tiles

This is a total of  vowel tiles in the complete set. Considering the two blanks, there are 

consonant tiles.

There are five unique tiles - "J", "K", "Q", "X", and "Z". Removing them leaves  consonant tiles. Since the removal of seven tiles and their replacement with seven others leaves the number of tiles in all at 100, at the very least, there are 51 consonant tiles in the new set - more than half.

The costs of the beverages will be as follows:

Add these amounts:

20% of this is 

, which rounds to $5.30.

The size of the regions do not matter in this problem; it is the central angles of the sectors that are relevant. The best way to understand this is to look at the spinner again, but after cutting out the central circle:

If we rearrange the sectors, we see the following:

The probability of the spinner landing in red exceeds that of it landing in green.

The median of seven (an odd number) integers is the one in the middle when the numbers are arranged in ascending order; in this case, it is the fourth lowest. Since the seven integers are consecutive, the lowest integer is three less than the median, or .