Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Upper Level Quantitative : Median

Study concepts, example questions & explanations for ISEE Upper Level Quantitative

Create An Account

All ISEE Upper Level Quantitative Resources

8 Diagnostic Tests 234 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Median

Consider the data set $\left \{ -1, 2, -3, 4, -5, 6, -7\right \}$

Which is the greater quantity?

(a) The median of the data set

(b) The mean of the data set

Possible Answers:

(b) is greater

(a) is greater

(a) and (b) are equal

It is impossible to tell from the information given

Correct answer:

(b) is greater

Explanation:

(a) Arrange the elements in ascending order:

$\left \{ -7, -5, -3, -1, 2,4,6 \right \}$

The median is the middle element, which is .

(b) Add the elements and divide by 7:

$[ (-7) + (-5) + (-3) + (-1) + 2 + 4 + 6 ] \div 7 = -4 \div 7 = - \frac{4}{7}$

$- \frac{4}{7} > -1$ , so the mean is greater.

Report an Error

Example Question #12 : Median

In the following set of numbers compare the mean and the median of the set:

$\left \{ 7,3,2,-1,14 \right \}$

Possible Answers:

The mean of the set is equal to the median of the set.

It is not possible to tell from the information given

The mean of the set is greater than the median of the set.

The median of the set is greater than the mean of the set.

Correct answer:

The mean of the set is greater than the median of the set.

Explanation:

The median is the middle value of a set of data containing an odd number of values. In this question in order to find the median we should first put the numbers in order:

$\left \{ -1,2,3,7,14 \right \}$

So the median is .

Mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So we have:

$Mean = \frac{-1+2+3+7+14}{5}=\frac{25}{5}=5$

So the mean of the set is greater than the median of that.

Report an Error

Example Question #13 : How To Find Median

In the following set of numbers compare the mean and the median of the set:

$\left \{ 28,25,31,34,37,43,40 \right \}$

Possible Answers:

It is not possible to tell from the information given

The mean of the set is equal to the median of the set.

The mean of the set is greater than the median of the set.

The median of the set is greater than the mean of the set.

Correct answer:

The mean of the set is equal to the median of the set.

Explanation:

The median is the middle value of a set of data containing an odd number of values. In this question in order to find the median we should first put the numbers in order:

$\left \{ 25,28,31,34,37,40,43 \right \}$

So the median is .

Mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So the mean of the set is equal to the median of the set.

$Mean = \frac{25+28+31+34+37+40+43}{7}=\frac{238}{7}=34$

So the mean of the set is greater than the median of that.

Report an Error

Example Question #14 : How To Find Median

Consider the following set of data:

$\left \{ 0,0.0001,0.001,0.01,0.1 \right \}$

$A=Median\ of\ the\ set$

$B=Mean\ of\ the\ set$

Compare and

Possible Answers:

The mean of the set is greater than the median of the set.

The mean of the set is equal to the median of the set.

It is not possible to tell from the information given.

The median of the set is greater than the mean of the set.

Correct answer:

The mean of the set is greater than the median of the set.

Explanation:

The median is the middle value of a set of data containing an odd number of values. In this question in order to find the median we should first put the numbers in order:

$\left \{ 0, 0.1, 0.01, 0.001, 0.0001 \right \}$

So the median is 0.01 .

Mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So the mean of the set is equal to the median of the set.

$Mean = \frac{0+0.1+0.01+0.001+0.0001}{5}=\frac{0.1111}{5}=0.02222\approx 0.02$

So the mean of the set is greater than the median of that.

Report an Error

Example Question #15 : How To Find Median

In the following set of numbers compare the mean and the median of the set:

$\left \{ 1,3,4,115,120,185,224 \right \}$

Possible Answers:

The mean of the set is equal to the median of the set.

It is not possible to tell from the information given.

The median of the set is greater than the mean of the set.

The mean of the set is greater than the median of the set.

Correct answer:

The median of the set is greater than the mean of the set.

Explanation:

The median is the middle value of a set of data containing an odd number of values which is 115 in this problem.

Mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So the mean of the set is equal to the median of the set.

$Mean = \frac{1+3+4+115+120+185+224}{7}=\frac{652}{7}\approx 93.14$

So the median of the set is greater than the mean of that.

Report an Error

Example Question #571 : Isee Upper Level (Grades 9 12) Quantitative Reasoning

In the following set of numbers compare the mean and the median of the set:

$\left \{ 1,2,4,8,10 \right \}$

Possible Answers:

The mean of the set is equal to the median of the set.

The mean of the set is greater than the median of the set.

The median of the set is greater than the mean of the set.

It is not possible to tell from the information given

Correct answer:

The mean of the set is greater than the median of the set.

Explanation:

The median is the middle value of a set of data containing an odd number of values which is in this set of numbers.

Mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So we have:

$Mean = \frac{1+2+4+8+10}{5}=\frac{25}{5}=5$

So the mean of the set is greater than the median of the set.

Report an Error

Example Question #17 : How To Find Median

In the following set of numbers compare the mean and the median of the set:

$\left \{ 15,28,14,11,10,5 \right \}$

Possible Answers:

It is not possible to tell from the information given

The median of the set is greater than the mean of the set.

The mean of the set is equal to the median of the set.

The mean of the set is greater than the median of the set.

Correct answer:

The mean of the set is greater than the median of the set.

Explanation:

If there are an even number of values, the median is the average of the two middle values of a set of data. In this question in order to find the median we should first put the numbers in order:

$\left \{ 5,10,11,14,15,28 \right \}$

So the median is:

$Median=\frac{11+14}{2}=\frac{25}{2}=12.5$

The mean of a data set $x_{1},x_{2}, ..., x_{n}$ is the sum of the data set values divided by the number of data:

$Mean=\frac{x_{1}+x_{2}+...+x_{n}}{n}$

So we have:

$Mean = \frac{5+10+11+14+15+28}{6}=\frac{83}{6}\approx 13.83$

So the mean of the set is greater than the median of the set.

Report an Error

Example Question #12 : How To Find Median

In the following set of data the mean is . Find the median.

$\left \{ 2,4,N,8,10 \right \}$

Possible Answers:

Correct answer:

Explanation:

First we need to find . We know that the mean of a set of data is given by the sum of the data, divided by the total number of values in the set. So we can write:

$Mean = \frac{2+4+N+8+10}{5}=\frac{24+N}{5}=10$

$\Rightarrow 24+N=50\Rightarrow N=50-24=26$

Now we have:

$\left \{ 2,4,26,8,10 \right \}$

If there are an odd number of values in a data set, the median is the middle value. First we need to put the numbers in order:

$\left \{ 2,4,8,10,26 \right \}$

So the median is .

Report an Error

Example Question #16 : How To Find Median

In the following set of data the mean and the mode are equal. Find the median.

$\left \{ 1,3,3,3,N,4,8 \right \}$

Possible Answers:

Correct answer:

Explanation:

The mode of a set of data is the value which occurs most frequently which is in this problem (it is not dependent on in this problem). So the mean is also equal to .

We know that the mean of a set of data is given by the sum of the data, divided by the total number of values in the set. So we can write:

$Mean = \frac{1+3+3+3+N+4+8}{7}=\frac{22+N}{7}=3$

$\Rightarrow 22+N=21\Rightarrow N=21-22=-1$

So we have:

$\left \{ 1,3,3,3,-1,4,8 \right \}$

If there are an odd number of values in a data set, the median is the middle value. First we need to put the numbers in order:

$\left \{ -1,1,3,3,3,4,8 \right \}$

So the median is also .

Report an Error

Example Question #91 : Data Analysis And Probability

Give the median of this data set:

20, 23, 25, 26, 28, 33, 100

Round to the nearest tenth, if applicable.

Possible Answers:

36.4

The data set has no median.

Correct answer:

Explanation:

The seven elements are already arranged in ascending order, so we need to look at the value occurring in the middle - that is, the fourth position. This element is 26.

Report an Error

View Tutors

Aaron
Certified Tutor

Portland State University, Bachelors, Economics. Portland State University, Masters, Environmental and Resource Management.

View Tutors

Gregory
Certified Tutor

Pennsylvania State University-Main Campus, Bachelor of Science, Chemical Engineering. Carnegie Mellon University, Doctor of P...

View Tutors

Magda
Certified Tutor

Heritage College, Bachelor of Science, Education.

All ISEE Upper Level Quantitative Resources

8 Diagnostic Tests 234 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Seattle, GMAT Tutors in San Diego, Calculus Tutors in San Francisco-Bay Area, Biology Tutors in Miami, SSAT Tutors in Seattle, Physics Tutors in New York City, Physics Tutors in San Francisco-Bay Area, Spanish Tutors in New York City, ISEE Tutors in Atlanta, English Tutors in Philadelphia

Popular Courses & Classes

MCAT Courses & Classes in Miami, MCAT Courses & Classes in Philadelphia, SAT Courses & Classes in Dallas Fort Worth, ACT Courses & Classes in Los Angeles, SAT Courses & Classes in Phoenix, GMAT Courses & Classes in Atlanta, SAT Courses & Classes in Miami, GRE Courses & Classes in Los Angeles, Spanish Courses & Classes in Los Angeles, GMAT Courses & Classes in Phoenix

Popular Test Prep

GMAT Test Prep in Washington DC, SSAT Test Prep in Houston, MCAT Test Prep in Washington DC, GMAT Test Prep in Atlanta, GMAT Test Prep in Boston, GMAT Test Prep in Phoenix, GMAT Test Prep in Denver, SAT Test Prep in Dallas Fort Worth, GRE Test Prep in Denver, GMAT Test Prep in San Francisco-Bay Area

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Upper Level Quantitative : Median

Study concepts, example questions & explanations for ISEE Upper Level Quantitative

All ISEE Upper Level Quantitative Resources

Example Questions

Example Question #11 : Median

Example Question #12 : Median

Example Question #13 : How To Find Median

Example Question #14 : How To Find Median

Example Question #15 : How To Find Median

Example Question #571 : Isee Upper Level (Grades 9 12) Quantitative Reasoning

Example Question #17 : How To Find Median

Example Question #12 : How To Find Median

Example Question #16 : How To Find Median

Example Question #91 : Data Analysis And Probability

All ISEE Upper Level Quantitative Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: