All ISEE Upper Level Math Resources
Example Questions
Example Question #742 : Isee Upper Level (Grades 9 12) Mathematics Achievement
Solve the equation:
First multiply both sides by :
Example Question #743 : Isee Upper Level (Grades 9 12) Mathematics Achievement
For what values of is ?
We have , so:
Example Question #744 : Isee Upper Level (Grades 9 12) Mathematics Achievement
Find :
means that or .
Then we can write:
Example Question #41 : Equations
Solve the equation for :
No solution
No solution
Since cannot be negative, no real number satisfies the equation.
Example Question #746 : Isee Upper Level (Grades 9 12) Mathematics Achievement
What are the roots of the equation?
First simplify the equation by dividing both sides by :
If are real numbers with , and if , then
.
The expression is called the discriminant of the quadratic equation, and we say .
We can write .
In this problem we have
Therefore the roots are
or .
Example Question #747 : Isee Upper Level (Grades 9 12) Mathematics Achievement
What are the roots of the equation?
First rewrite the equation in the form of :
If are real numbers with , and if , then we have:
The expression is called the discriminant of the quadratic equation, and we say . We can write
.
In this problem we have
Then the roots are and .
Example Question #748 : Isee Upper Level (Grades 9 12) Mathematics Achievement
Find the roots of the equation:
or
or
or
or
or
or
If are real numbers with , and if , then we have
.
The expression is called the discriminant of the quadratic equation, and we say . We can write
.
In this problem we have
Then the roots are
and .
Example Question #749 : Isee Upper Level (Grades 9 12) Mathematics Achievement
Find the roots of .
or
or
or
Therefore, or .
Example Question #750 : Isee Upper Level (Grades 9 12) Mathematics Achievement
Solve for :
or
or
or
or
We can factor out an :
Therefore, or:
Example Question #42 : Equations
Solve the equation for :
Sometimes you can easily factor the experssion . Then the equation can be solved by setting each factor equal to . In this problem we have:
or .
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