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ISEE Middle Level Quantitative : How to multiply

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

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All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

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Example Question #538 : Number & Operations In Base Ten

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}6\\ \times\phantom{0}6\space{\,}7 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

30820

3072

3082

3092

Correct answer:

3082

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 67 is the multiplier and 46 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 6

$\begin{array}{r}\overset{4 \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7\\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 7 and 4 and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}3\,2\,2\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}3\,2\,2 \\ \, 0 \end{array}$

Next, we multiply 6 and 6

$\begin{array}{r}\overset{3 \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}3\,2\,2 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 4and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}3\,2\,2 \\ \, 2 \, 7 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 4} \space{\,}6\\ \times \phantom{0} 6\space{\,}7 \\ \hline \phantom{\,}3\,2\,2 \\+\, 2 \, 7 \, 6 \, 0\\ \hline 3\, 0 \, 8\, 2\end{array}$

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Example Question #11 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}3\\ \times\phantom{0}5\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3213

32130

3203

3223

Correct answer:

3213

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 51 is the multiplier and 63 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\end{array}$

Then, we multiply 1 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,6\,3\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,6\,3 \\ \, 0 \end{array}$

Next, we multiply 5 and 3

$\begin{array}{r}\overset{1 \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,6\,3 \\ \, 5 \, 0\end{array}$

Then, we multiply 5 and 6and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,6\,3 \\ \, 3 \, 1 \, 5 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 6} \space{\,}3\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,6\,3 \\+\, 3 \, 1 \, 5 \, 0\\ \hline 3\, 2 \, 1\, 3\end{array}$

Report an Error

Example Question #12 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}2\\ \times\phantom{0}7\space{\,}8 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

32760

3286

3266

3276

Correct answer:

3276

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 78 is the multiplier and 42 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 2

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 8 and 4 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8 \\ \hline \phantom{\,}3\,3\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8 \\ \hline \phantom{\,}3\,3\,6 \\ \, 0 \end{array}$

Next, we multiply 7 and 2

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8 \\ \hline \phantom{\,}3\,3\,6 \\ \, 4 \, 0\end{array}$

Then, we multiply 7 and 4and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8 \\ \hline \phantom{\,}3\,3\,6 \\ \, 2 \, 9 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}2\\ \times \phantom{0} 7\space{\,}8 \\ \hline \phantom{\,}3\,3\,6 \\+\, 2 \, 9 \, 4 \, 0\\ \hline 3\, 2 \, 7\, 6\end{array}$

Report an Error

Example Question #21 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}6\\ \times\phantom{0}1\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1074

1064

1054

10640

Correct answer:

1064

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 14 is the multiplier and 76 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 6

$\begin{array}{r}\overset{2 \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 7 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4 \\ \hline \phantom{\,}3\,0\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4 \\ \hline \phantom{\,}3\,0\,4 \\ \, 0 \end{array}$

Next, we multiply 1 and 6

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4 \\ \hline \phantom{\,}3\,0\,4 \\ \, 6 \, 0\end{array}$

Then, we multiply 1 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4 \\ \hline \phantom{\,}3\,0\,4 \\ \, 7 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}6\\ \times \phantom{0} 1\space{\,}4 \\ \hline \phantom{\,}3\,0\,4 \\+\, 7 \, 6 \, 0\\ \hline 1\, 0 \, 6\, 4\end{array}$

Report an Error

Example Question #22 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}8\\ \times\phantom{0}3\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1904

1924

1914

19140

Correct answer:

1914

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 33 is the multiplier and 58 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 8

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 3 and 5 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,7\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,7\,4 \\ \, 0 \end{array}$

Next, we multiply 3 and 8

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,7\,4 \\ \, 4 \, 0\end{array}$

Then, we multiply 3 and 5and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,7\,4 \\ \, 1 \, 7 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}8\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,7\,4 \\+\, 1 \, 7 \, 4 \, 0\\ \hline 1\, 9 \, 1\, 4\end{array}$

Report an Error

Example Question #23 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}5\\ \times\phantom{0}7\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

5485

5475

5465

54750

Correct answer:

5475

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 73 is the multiplier and 75 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 5

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3\\ \hline \phantom{\,} \,5\end{array}$

Then, we multiply 3 and 7 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3 \\ \hline \phantom{\,}2\,2\,5\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3 \\ \hline \phantom{\,}2\,2\,5 \\ \, 0 \end{array}$

Next, we multiply 7 and 5

$\begin{array}{r}\overset{3 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3 \\ \hline \phantom{\,}2\,2\,5 \\ \, 5 \, 0\end{array}$

Then, we multiply 7 and 7and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3 \\ \hline \phantom{\,}2\,2\,5 \\ \, 5 \, 2 \, 5 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 7} \space{\,}5\\ \times \phantom{0} 7\space{\,}3 \\ \hline \phantom{\,}2\,2\,5 \\+\, 5 \, 2 \, 5 \, 0\\ \hline 5\, 4 \, 7\, 5\end{array}$

Report an Error

Example Question #24 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}5\\ \times\phantom{0}8\space{\,}8 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

7480

7490

7470

74800

Correct answer:

7480

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 88 is the multiplier and 85 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 5

$\begin{array}{r}\overset{4 \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8\\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 8 and 8 and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8 \\ \hline \phantom{\,}6\,8\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8 \\ \hline \phantom{\,}6\,8\,0 \\ \, 0 \end{array}$

Next, we multiply 8 and 5

$\begin{array}{r}\overset{4 \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8 \\ \hline \phantom{\,}6\,8\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 8 and 8and add the 4 that was carried

$\begin{array}{r}\overset{4 \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8 \\ \hline \phantom{\,}6\,8\,0 \\ \, 6 \, 8 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{4 \space{\ }}{\ 8} \space{\,}5\\ \times \phantom{0} 8\space{\,}8 \\ \hline \phantom{\,}6\,8\,0 \\+\, 6 \, 8 \, 0 \, 0\\ \hline 7\, 4 \, 8\, 0\end{array}$

Report an Error

Example Question #25 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}7\\ \times\phantom{0}3\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

28710

2871

2881

2861

Correct answer:

2871

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 33 is the multiplier and 87 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3\\ \hline \phantom{\,} \,1\end{array}$

Then, we multiply 3 and 8 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,6\,1\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,6\,1 \\ \, 0 \end{array}$

Next, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,6\,1 \\ \, 1 \, 0\end{array}$

Then, we multiply 3 and 8and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,6\,1 \\ \, 2 \, 6 \, 1 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}7\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}2\,6\,1 \\+\, 2 \, 6 \, 1 \, 0\\ \hline 2\, 8 \, 7\, 1\end{array}$

Report an Error

Example Question #26 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}4\\ \times\phantom{0}6\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2782

27720

2772

2762

Correct answer:

2772

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 63 is the multiplier and 44 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 4

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3\\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 3 and 4 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,3\,2\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,3\,2 \\ \, 0 \end{array}$

Next, we multiply 6 and 4

$\begin{array}{r}\overset{2 \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,3\,2 \\ \, 4 \, 0\end{array}$

Then, we multiply 6 and 4and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,3\,2 \\ \, 2 \, 6 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 4} \space{\,}4\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,3\,2 \\+\, 2 \, 6 \, 4 \, 0\\ \hline 2\, 7 \, 7\, 2\end{array}$

Report an Error

Example Question #27 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times\phantom{0}5\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

4294

4284

42840

4274

Correct answer:

4284

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 51 is the multiplier and 84 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 1 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,8\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,8\,4 \\ \, 0 \end{array}$

Next, we multiply 5 and 4

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,8\,4 \\ \, 0 \, 0\end{array}$

Then, we multiply 5 and 8and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,8\,4 \\ \, 4 \, 2 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,8\,4 \\+\, 4 \, 2 \, 0 \, 0\\ \hline 4\, 2 \, 8\, 4\end{array}$

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All ISEE Middle Level Quantitative Resources

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ISEE Middle Level Quantitative : How to multiply

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

All ISEE Middle Level Quantitative Resources

Example Questions

Example Question #538 : Number & Operations In Base Ten

Example Question #11 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #12 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #21 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #22 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #23 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #24 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #25 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #26 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #27 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All ISEE Middle Level Quantitative Resources

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