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ISEE Middle Level Quantitative : How to multiply

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

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All ISEE Middle Level Quantitative Resources

6 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

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Example Question #58 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times\phantom{0}1\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1178

11680

1168

1158

Correct answer:

1168

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 16 is the multiplier and 73 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 3

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6\\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 6 and 7 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 0 \end{array}$

Next, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 3 \, 0\end{array}$

Then, we multiply 1 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\ \, 7 \, 3 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}3\\ \times \phantom{0} 1\space{\,}6 \\ \hline \phantom{\,}4\,3\,8 \\+\, 7 \, 3 \, 0\\ \hline 1\, 1 \, 6\, 8\end{array}$

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Example Question #59 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times\phantom{0}4\space{\,}0 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2830

2840

28400

2850

Correct answer:

2840

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 40 is the multiplier and 71 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 0 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 0 \end{array}$

Next, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 4 \, 0\end{array}$

Then, we multiply 4 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 2\, 8\, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}1\\ \times \phantom{0} 4\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\+\, 2\, 8\, 4 \, 0\\ \hline 2\, 8 \, 4\, 0\end{array}$

Report an Error

Example Question #60 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times\phantom{0}4\space{\,}2 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

31080

3098

3108

3118

Correct answer:

3108

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 42 is the multiplier and 74 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 2 and 7

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 0 \end{array}$

Next, we multiply 4 and 4

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 6 \, 0\end{array}$

Then, we multiply 4 and 7and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\ \, 2 \, 9 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 7} \space{\,}4\\ \times \phantom{0} 4\space{\,}2 \\ \hline \phantom{\,}1\,4\,8 \\+\, 2 \, 9 \, 6 \, 0\\ \hline 3\, 1 \, 0\, 8\end{array}$

Report an Error

Example Question #61 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}7\\ \times\phantom{0}3\space{\,}8 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

646

636

656

6460

Correct answer:

646

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 38 is the multiplier and 17 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 7

$\begin{array}{r}\overset{5 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 8 and 1 and add the 5 that was carried

$\begin{array}{r}\overset{5 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 0 \end{array}$

Next, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 1 \, 0\end{array}$

Then, we multiply 3 and 1and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\ \, 5 \, 1 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 1} \space{\,}7\\ \times \phantom{0} 3\space{\,}8 \\ \hline \phantom{\,}1\,3\,6 \\+\, 5 \, 1 \, 0\\ \hline 6\, 4 \, 6\end{array}$

Report an Error

Example Question #62 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}7\\ \times\phantom{0}2\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

13110

1311

1301

1321

Correct answer:

1311

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 23 is the multiplier and 57 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 7

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3\\ \hline \phantom{\,} \,1\end{array}$

Then, we multiply 3 and 5 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 0 \end{array}$

Next, we multiply 2 and 7

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 4 \, 0\end{array}$

Then, we multiply 2 and 5and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\ \, 1 \, 1 \, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}7\\ \times \phantom{0} 2\space{\,}3 \\ \hline \phantom{\,}1\,7\,1 \\+\, 1 \, 1 \, 4 \, 0\\ \hline 1\, 3 \, 1\, 1\end{array}$

Report an Error

Example Question #63 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times\phantom{0}8\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

6730

67200

6710

6720

Correct answer:

6720

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 84 is the multiplier and 80 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 4 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 0 \end{array}$

Next, we multiply 8 and 0

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 8 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\ \, 6\, 4\, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}0\\ \times \phantom{0} 8\space{\,}4 \\ \hline \phantom{\,}3\,2\,0 \\+\, 6\, 4\, 0 \, 0\\ \hline 6\, 7 \, 2\, 0\end{array}$

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Example Question #1051 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times\phantom{0}4\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

22440

2244

2234

2254

Correct answer:

2244

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 44 is the multiplier and 51 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 0 \end{array}$

Next, we multiply 4 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 4 \, 0\end{array}$

Then, we multiply 4 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\ \, 2\, 0\, 4 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}1\\ \times \phantom{0} 4\space{\,}4 \\ \hline \phantom{\,}2\,0\,4 \\+\, 2\, 0\, 4 \, 0\\ \hline 2\, 2 \, 4\, 4\end{array}$

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Example Question #65 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times\phantom{0}2\space{\,}2 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

836

8360

846

826

Correct answer:

836

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 22 is the multiplier and 38 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 8

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 2 and 3 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 0 \end{array}$

Next, we multiply 2 and 8

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 2 and 3and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\ \, 7 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}2 \\ \hline \phantom{\,} \,7\,6 \\+\, 7 \, 6 \, 0\\ \hline 8\, 3 \, 6\end{array}$

Report an Error

Example Question #66 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times\phantom{0}2\space{\,}7 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1026

1036

1016

10260

Correct answer:

1026

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 27 is the multiplier and 38 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 8

$\begin{array}{r}\overset{5 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7\\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 7 and 3 and add the 5 that was carried

$\begin{array}{r}\overset{5 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7 \\ \hline \phantom{\,}2\,6\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7 \\ \hline \phantom{\,}2\,6\,6 \\ \, 0 \end{array}$

Next, we multiply 2 and 8

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7 \\ \hline \phantom{\,}2\,6\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 2 and 3and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7 \\ \hline \phantom{\,}2\,6\,6 \\ \, 7 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 3} \space{\,}8\\ \times \phantom{0} 2\space{\,}7 \\ \hline \phantom{\,}2\,6\,6 \\+\, 7 \, 6 \, 0\\ \hline 1\, 0 \, 2\, 6\end{array}$

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Example Question #67 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}6\\ \times\phantom{0}6\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1628

1648

1638

16380

Correct answer:

1638

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 63 is the multiplier and 26 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 6

$\begin{array}{r}\overset{1 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3\\ \hline \phantom{\,} \,8\end{array}$

Then, we multiply 3 and 2 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,} \,7\,8\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,} \,7\,8 \\ \, 0 \end{array}$

Next, we multiply 6 and 6

$\begin{array}{r}\overset{3 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,} \,7\,8 \\ \, 6 \, 0\end{array}$

Then, we multiply 6 and 2and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,} \,7\,8 \\ \, 1 \, 5 \, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 2} \space{\,}6\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,} \,7\,8 \\+\, 1 \, 5 \, 6 \, 0\\ \hline 1\, 6 \, 3\, 8\end{array}$

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All ISEE Middle Level Quantitative Resources

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ISEE Middle Level Quantitative : How to multiply

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

All ISEE Middle Level Quantitative Resources

Example Questions

Example Question #58 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #59 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #60 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #61 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #62 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #63 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #1051 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #65 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #66 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #67 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All ISEE Middle Level Quantitative Resources

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