Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi
Undefined control sequence \dpi

ISEE Lower Level Quantitative : How to find the solution to an equation

Study concepts, example questions & explanations for ISEE Lower Level Quantitative

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Example Questions

Example Question #1 : How To Find The Solution To An Equation

What is the value of x in the equation?

\dpi{100} \frac{200+50}{5}=x

Possible Answers:

\dpi{100} 25

\dpi{100} 100

\dpi{100} 5

\dpi{100} 50

Correct answer:

\dpi{100} 50

Explanation:

First, add \dpi{100} 200+50=250.

Next, divide \dpi{100} 250\div 5=50.

So \dpi{100} x=50

Example Question #2 : How To Find The Solution To An Equation

Simplify.

\displaystyle -7x +4x-11-x+3

Possible Answers:

\displaystyle 4x+8

\displaystyle -4x-8

\displaystyle -4x+8

\displaystyle -4x-14

Correct answer:

\displaystyle -4x-8

Explanation:

When simplifying an expression, you must combine like terms. There are two types of terms in this expression: “x’s” and whole numbers.  Combine in two steps:

1) x’s:  \displaystyle -7x+4x-x=-4x

2) whole numbers:   \displaystyle -11+3=-8

The simplified expression is: \displaystyle -4x-8.

Example Question #3 : Equations

Solve, when \displaystyle x=-2.

\displaystyle -6x^{2}+12x+3=

Possible Answers:

\displaystyle -45

\displaystyle -48

\displaystyle 3

\displaystyle 51

Correct answer:

\displaystyle -45

Explanation:

To solve, insert \displaystyle -2 for each \displaystyle x:

\displaystyle -6(-2)^{2}+12(-2)+3=

Simplify:

\displaystyle -6(4)-24+3=

\displaystyle -24-24+3=-45 

*Common error: When solving this part of the equation  always remember the order of operations (PEMDAS) and square the number in the () BEFORE multiplying!

Example Question #3 : How To Find The Solution To An Equation

Solve for \displaystyle x.

\displaystyle 5x^{2}-14=6

Possible Answers:

\displaystyle -3

\displaystyle 5

\displaystyle 3

\displaystyle -2

Correct answer:

\displaystyle -2

Explanation:

\displaystyle 5(-2)^{2}-14=6

Example Question #4 : Algebraic Concepts

Use the equations to answer the question. 

\displaystyle 3 + x=4

\displaystyle 9+y=13

What is \displaystyle x+y?

Possible Answers:

\displaystyle 5

\displaystyle 10

\displaystyle 9

\displaystyle 17

Correct answer:

\displaystyle 5

Explanation:

First, you need to find what would make \displaystyle x and \displaystyle y true in their respective equations. \displaystyle x equals 1 and \displaystyle y equals 4. The next step is to add those together, which gives you 5. 

Example Question #4 : How To Find The Solution To An Equation

What story best fits the expression \displaystyle 9\times3?

Possible Answers:

Lisa had 9 pencils with two erasers each.

Nell bought 9 bags of candy with 3 pieces of candy in each bag. 

Jonah had 3 baseball cards, but after his friend gave him some, he had 12. 

Michelle had 3 stuffed animals and gave 1 away.

Correct answer:

Nell bought 9 bags of candy with 3 pieces of candy in each bag. 

Explanation:

Nell's story fits best because if she bought 9 bags with 3 pieces each, that would be 27 total. This fits best with the \displaystyle 9\times 3=27 equation.

Example Question #5 : How To Find The Solution To An Equation

What is \displaystyle x equal to in this equation: 

\displaystyle 4x+5=13

Possible Answers:

\displaystyle 1

\displaystyle 3

\displaystyle 4

\displaystyle 2

Correct answer:

\displaystyle 2

Explanation:

Find the number that makes the equation true. 2 works because when plugged in, the left side of the equation becomes 13, making the whole equation true.

Example Question #7 : Algebraic Concepts

Five more than a number is equal to \displaystyle \frac{3}{5} of twenty-five . What is the number?

Possible Answers:

\displaystyle 15

\displaystyle 11

\displaystyle 10

\displaystyle 5

Correct answer:

\displaystyle 10

Explanation:

From the question, we know that \displaystyle 5 plus a number equals \displaystyle \frac{3}{5} of \displaystyle 25. In order to find out what \displaystyle \frac{3}{5} of \displaystyle 25 is, multiply \displaystyle \frac{3}{5} by \displaystyle \frac{25}{1}.  

 

\displaystyle \frac{3}{5}\times\frac{25}{1}=\frac{75}{5}, or \displaystyle 15.

The number we are looking for needs to be five less than \displaystyle 15, or \displaystyle 10.

You can also solve this algebraically by setting up this equation and solving:

\displaystyle 5+x=\frac{3}{5}\times25

\displaystyle 5+x=15 

Subtract \displaystyle 5 from both sides of the equation.         

\displaystyle x=10

 

Example Question #3 : Algebraic Concepts

Solve for \displaystyle x.

\displaystyle 2x-2=10

Possible Answers:

\displaystyle x=6

\displaystyle x=8

\displaystyle x=10

\displaystyle x=12

Correct answer:

\displaystyle x=6

Explanation:

To solve for \displaystyle x, we want to isolate \displaystyle x, or get it by itself. 

\displaystyle 2x-2=10

Add \displaystyle 2 to both sides of the equation.

\displaystyle 2x-2=10

    \displaystyle +2        \displaystyle +2

\displaystyle 2x=12

Now we need to divide both sides by the coefficient of \displaystyle x, i.e. the number directly in front of the \displaystyle x.

\displaystyle 2x=12

\displaystyle x=6

     

Example Question #6 : How To Find The Solution To An Equation

Solve for \displaystyle x.

\displaystyle 18=3x+3

Possible Answers:

\displaystyle 6

\displaystyle 5

\displaystyle 3

\displaystyle 4

Correct answer:

\displaystyle 5

Explanation:

First, subtract the three from both sides:

\displaystyle 18-3=3x+3\left ( -3\right )

\displaystyle 15=3x

Then, divide by three on both sides:

\displaystyle \frac{15}{3}=\frac{3x}{3}

\displaystyle 5=x

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