GRE Subject Test: Biochemistry, Cell, and Molecular Biology : Macromolecules and Enzymes

Study concepts, example questions & explanations for GRE Subject Test: Biochemistry, Cell, and Molecular Biology

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Example Questions

Example Question #11 : Macromolecules And Enzymes

Which of the following nucleotides is present in RNA, but not DNA?

Possible Answers:

Guanine

Cytosine

Adenine

Uracil

Correct answer:

Uracil

Explanation:

Uracil is one of the nucleotide bases that composes RNA. It is replaced by thymine in DNA.

Uracil, thymine, and cytosine are pyrimidine residues, capable of bonding and pairing with the purines adenine and guanine via hydrogen bonding. During DNA replication, thymine matches with adenine. During transcription, uracil matches with adenine.

Example Question #12 : Macromolecules And Enzymes

In DNA, which of the following nucleotides forms hydrogen bonds with guanine?

Possible Answers:

Cytosine

Thymine

Uracil

Adenine

Correct answer:

Cytosine

Explanation:

Nucleotides (DNA monomers) and ribonucleotides (RNA monomers) are formed from a pentose sugar, phosphate group, and nitrogenous base. Each nitrogenous base has a complement that allows it to form hydrogen bonds to the template strand. This allows for the proper sequence of genetic code in DNA replication and RNA transcription.

Purine residues will always pair with pyrimidine residues. The purines are adenine and guanine. The pyrimidines are cytosine and thymine in DNA, and cytosine and uracil in RNA. Adenine will match with thymine or uracil, forming two hydrogen bonds, while cytosine will match with guanine to form three hydrogen bonds.

Example Question #13 : Macromolecules And Enzymes

Which of the following processes allows DNA mismatch repair enzymes to distinguish between old and new DNA strands?

Possible Answers:

Methylation

Heterochromatin

Euchromatin

Histone acetylation

Correct answer:

Methylation

Explanation:

Template strand cytosine and adenine are methylated in DNA replication, which allows DNA mismatch repair enzymes to distinguish between old and new DNA strands.

In contrast, histone acetylation relaxes DNA coiling and allows for the DNA to be transcribed.

You can remember that methylation makes DNA mute, and acetylation makes DNA active.

Example Question #14 : Macromolecules And Enzymes

Which of the following amino acids is NOT necessary for purine synthesis?

Possible Answers:

Glycine

Tyrosine

Aspartate

Glutamine

Correct answer:

Tyrosine

Explanation:

Purines are defined by their two-ring structure. A six-member ring with two amine groups and a five-member ring with two amino groups join to form each purine molecule. Addition substituents on the rings (often ketones or other amines) determine purine identity.

Glycine, aspartate, and glutamine are necessary for purine synthesis, along with phosphoribosyl pyrophosphate (PRPP). Glycine is incorporated into the final purine product structure, while glutamine is converted to glutamate and aspartate is converted to fumarate. The final purine product is used to make useful molecules, such as adenine and guanine for nucleotide synthesis.

Example Question #11 : Macromolecules And Enzymes

Which type of lipid acts as a buffer for membrane fluidity?

Possible Answers:

Terpenes

Sterols

Phospholipids

Glycolipids

Correct answer:

Sterols

Explanation:

Membrane fluidity can be buffered by cholesterol in both warm and cold environments. At high temperatures cholesterol raises the melting point, while at lower temperatures cholesterol prevents the formation of crystalline structures between phospholipids.

Example Question #1 : Help With Lipids

Phospholipids are comprised of __________.

Possible Answers:

a glycerol head and two sphingolipids

a glycerol head containing a phosphate group and two fatty acids

a glycerol head containing a phosphate group and three fatty acids

a chain of saturated fats

a sugar, phosphate group, and nitrogenous base

Correct answer:

a glycerol head containing a phosphate group and two fatty acids

Explanation:

The correct answer is a glycerol head containing a phosphate group and two fatty acids. Phospho refers to the phosphate group and lipid refers to the glycerol backbone attached to two fatty acid chains.

Example Question #2 : Help With Lipids

What qualifies a molecule to be considered an omega-3 fatty acid?

Possible Answers:

The attachment of three of the same fatty acid to a glycerol

The presence of a double bond on the third-to-last carbon in the fatty acid

The presence of three double bonds in the fatty acid

The presence of a double bond on the third carbon in the fatty acid

Correct answer:

The presence of a double bond on the third-to-last carbon in the fatty acid

Explanation:

Omega-3 fatty acids are named after the double bond that starts on the third-to-last carbon in the fatty acid. The carboxylic acid carbon is considered the first carbon, while the last methyl group carbon is considered the "omega" carbon. As a result, the double bond will be three carbons away from the end.

Example Question #1 : Biochemistry

Glycogen is a polymer of glucose that is held together by __________ bonds. The branch points are held together by __________ bonds. 

Possible Answers:

Correct answer:

Explanation:

 bonds are on the same plane, while  bonds are not on the same plane; therefore, the  bonds are much more useful for making branch points off of existing glycogen chains.

linkages cannot be easily broken down by eukaryotes and animals. Glycogen must be easily accessible as an energy source, and does not contain any glycosidic linkages.

Example Question #1 : Enzyme Principles

A researcher is studying the rate of an enzyme-catalyzed reaction by placing increasing amounts of substrate into a solution containing the enzyme. After a certain concentration, the rate of the reaction plateaus and does not go any higher. What has happened?

Possible Answers:

The enzyme has become saturated

The enzyme has become denatured

The concentration of enzyme is so small that the reaction has stopped occurring completely

The reaction rate has only momentarily plateaued; given enough time it will increase

Correct answer:

The enzyme has become saturated

Explanation:

If the reaction rate has plateaued, this indicates that the enzyme has reached saturation. At this point, every active site on every molecule of enzyme is actively catalyzing the reaction as quickly as it can. The only way to change the reaction rate, at this point, would be to increase the concentration of the enzyme in the solution. Further increasing substrate concentration will have no effect.

We know that the enzyme has not become denatured because the reaction is still occurring. The rate of the reaction is constant during the plateau, and does not drop to zero.

Example Question #1 : Enzymes

In a Lineweaver-Burk plot, what quantity determines the y-intercept?

Possible Answers:

Correct answer:

Explanation:

A Lineweaver-Burk plot is a way to graphically represent enzyme kinetics. It is convenient because several portions of the graph readily display important information, such as rate constants. The y-intercept in particular is useful because it represents the reciprocal of the maximum velocity. The x-intercept describes the negative reciprocal of the Michaelis constant. The slope is the quotient of the Michaelis constant over the maximum velocity.

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