All GRE Subject Test: Biochemistry, Cell, and Molecular Biology Resources
Example Questions
Example Question #11 : Macromolecules And Enzymes
Which of the following nucleotides is present in RNA, but not DNA?
Guanine
Cytosine
Adenine
Uracil
Uracil
Uracil is one of the nucleotide bases that composes RNA. It is replaced by thymine in DNA.
Uracil, thymine, and cytosine are pyrimidine residues, capable of bonding and pairing with the purines adenine and guanine via hydrogen bonding. During DNA replication, thymine matches with adenine. During transcription, uracil matches with adenine.
Example Question #12 : Macromolecules And Enzymes
In DNA, which of the following nucleotides forms hydrogen bonds with guanine?
Cytosine
Thymine
Uracil
Adenine
Cytosine
Nucleotides (DNA monomers) and ribonucleotides (RNA monomers) are formed from a pentose sugar, phosphate group, and nitrogenous base. Each nitrogenous base has a complement that allows it to form hydrogen bonds to the template strand. This allows for the proper sequence of genetic code in DNA replication and RNA transcription.
Purine residues will always pair with pyrimidine residues. The purines are adenine and guanine. The pyrimidines are cytosine and thymine in DNA, and cytosine and uracil in RNA. Adenine will match with thymine or uracil, forming two hydrogen bonds, while cytosine will match with guanine to form three hydrogen bonds.
Example Question #13 : Macromolecules And Enzymes
Which of the following processes allows DNA mismatch repair enzymes to distinguish between old and new DNA strands?
Methylation
Heterochromatin
Euchromatin
Histone acetylation
Methylation
Template strand cytosine and adenine are methylated in DNA replication, which allows DNA mismatch repair enzymes to distinguish between old and new DNA strands.
In contrast, histone acetylation relaxes DNA coiling and allows for the DNA to be transcribed.
You can remember that methylation makes DNA mute, and acetylation makes DNA active.
Example Question #14 : Macromolecules And Enzymes
Which of the following amino acids is NOT necessary for purine synthesis?
Glycine
Tyrosine
Aspartate
Glutamine
Tyrosine
Purines are defined by their two-ring structure. A six-member ring with two amine groups and a five-member ring with two amino groups join to form each purine molecule. Addition substituents on the rings (often ketones or other amines) determine purine identity.
Glycine, aspartate, and glutamine are necessary for purine synthesis, along with phosphoribosyl pyrophosphate (PRPP). Glycine is incorporated into the final purine product structure, while glutamine is converted to glutamate and aspartate is converted to fumarate. The final purine product is used to make useful molecules, such as adenine and guanine for nucleotide synthesis.
Example Question #11 : Macromolecules And Enzymes
Which type of lipid acts as a buffer for membrane fluidity?
Terpenes
Sterols
Phospholipids
Glycolipids
Sterols
Membrane fluidity can be buffered by cholesterol in both warm and cold environments. At high temperatures cholesterol raises the melting point, while at lower temperatures cholesterol prevents the formation of crystalline structures between phospholipids.
Example Question #1 : Help With Lipids
Phospholipids are comprised of __________.
a glycerol head and two sphingolipids
a glycerol head containing a phosphate group and two fatty acids
a glycerol head containing a phosphate group and three fatty acids
a chain of saturated fats
a sugar, phosphate group, and nitrogenous base
a glycerol head containing a phosphate group and two fatty acids
The correct answer is a glycerol head containing a phosphate group and two fatty acids. Phospho refers to the phosphate group and lipid refers to the glycerol backbone attached to two fatty acid chains.
Example Question #2 : Help With Lipids
What qualifies a molecule to be considered an omega-3 fatty acid?
The attachment of three of the same fatty acid to a glycerol
The presence of a double bond on the third-to-last carbon in the fatty acid
The presence of three double bonds in the fatty acid
The presence of a double bond on the third carbon in the fatty acid
The presence of a double bond on the third-to-last carbon in the fatty acid
Omega-3 fatty acids are named after the double bond that starts on the third-to-last carbon in the fatty acid. The carboxylic acid carbon is considered the first carbon, while the last methyl group carbon is considered the "omega" carbon. As a result, the double bond will be three carbons away from the end.
Example Question #1 : Biochemistry
Glycogen is a polymer of glucose that is held together by __________ bonds. The branch points are held together by __________ bonds.
bonds are on the same plane, while bonds are not on the same plane; therefore, the bonds are much more useful for making branch points off of existing glycogen chains.
linkages cannot be easily broken down by eukaryotes and animals. Glycogen must be easily accessible as an energy source, and does not contain any glycosidic linkages.
Example Question #1 : Enzyme Principles
A researcher is studying the rate of an enzyme-catalyzed reaction by placing increasing amounts of substrate into a solution containing the enzyme. After a certain concentration, the rate of the reaction plateaus and does not go any higher. What has happened?
The enzyme has become saturated
The enzyme has become denatured
The concentration of enzyme is so small that the reaction has stopped occurring completely
The reaction rate has only momentarily plateaued; given enough time it will increase
The enzyme has become saturated
If the reaction rate has plateaued, this indicates that the enzyme has reached saturation. At this point, every active site on every molecule of enzyme is actively catalyzing the reaction as quickly as it can. The only way to change the reaction rate, at this point, would be to increase the concentration of the enzyme in the solution. Further increasing substrate concentration will have no effect.
We know that the enzyme has not become denatured because the reaction is still occurring. The rate of the reaction is constant during the plateau, and does not drop to zero.
Example Question #1 : Enzymes
In a Lineweaver-Burk plot, what quantity determines the y-intercept?
A Lineweaver-Burk plot is a way to graphically represent enzyme kinetics. It is convenient because several portions of the graph readily display important information, such as rate constants. The y-intercept in particular is useful because it represents the reciprocal of the maximum velocity. The x-intercept describes the negative reciprocal of the Michaelis constant. The slope is the quotient of the Michaelis constant over the maximum velocity.